(a)
The position and height of the game piece.
(a)
Answer to Problem 67A
Explanation of Solution
Given:
Height of an image is
Distance between the image and the diverging lens is
Focal length of a diverging lens is
Formula used:
The relationship between the object distance
The magnification
Calculation:
Position of the game piece can be calculated by substituting the numerical values in equation
Height of the game piece can be calculated by substituting the numerical values in the equation
Conclusion:
Position of the game piece is at
(b)
The position, height, and orientation of the image.
To identify: Whether the image formed is real or virtual.
(b)
Answer to Problem 67A
The image is upright and virtual.
Explanation of Solution
Given:
Since diverging lens is replaced by a converging lens,
Focal length of the lens,
Height of the game piece,
The distance between the game piece and the lens,
Formula used:
The relationship between the object distance
The relationship between the image height
Calculation:
The distance between the lens and the image can be calculated by substituting the numerical values in equation
The height of the image can be calculated by substituting the numerical values in equation
The values of
Conclusion:
The distance between the lens and the image is
The height of the image is
The image formed is virtual and upright.
Chapter 18 Solutions
Glencoe Physics: Principles and Problems, Student Edition
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