CALCULUS (CLOTH)
4th Edition
ISBN: 9781319050733
Author: Rogawski
Publisher: MAC HIGHER
expand_more
expand_more
format_list_bulleted
Concept explainers
Question
Chapter 18.2, Problem 2E
To determine
The validity of Stokes’ theorem for the given vector field and surface, oriented with an upward-pointing normal.
Expert Solution & Answer
Want to see the full answer?
Check out a sample textbook solutionStudents have asked these similar questions
Q1] Find a unit
vector normal to
the surface
3x? у — у?z? at
the point (1,-2,
-1)
Verify Stokes's theorem over a quarter circular disk with a radius, r = 4 in the 1*
F -а, ху-ӑ, 2х (Figure: 1)
quadrant for any given vector,
B
r= 4
A
Figure: 1
−Y+z5
Let F (x, y, z) :=
x+yz7
3+2⁹
let ʼn be the outward unit normal vector. Evaluate ſf (curl F) · ndS.
(Use syntax like 2*pi/3 .)
Let S be the upper half of the sphere of radius 2 centered at the origin. At each point of S
Chapter 18 Solutions
CALCULUS (CLOTH)
Ch. 18.1 - Prob. 1PQCh. 18.1 - Prob. 2PQCh. 18.1 - Prob. 3PQCh. 18.1 - Prob. 4PQCh. 18.1 - Prob. 5PQCh. 18.1 - Prob. 1ECh. 18.1 - Prob. 2ECh. 18.1 - Prob. 3ECh. 18.1 - Prob. 4ECh. 18.1 - Prob. 5E
Ch. 18.1 - Prob. 6ECh. 18.1 - Prob. 7ECh. 18.1 - Prob. 8ECh. 18.1 - Prob. 9ECh. 18.1 - Prob. 10ECh. 18.1 - Prob. 11ECh. 18.1 - Prob. 12ECh. 18.1 - Prob. 13ECh. 18.1 - Prob. 14ECh. 18.1 - Prob. 15ECh. 18.1 - Prob. 16ECh. 18.1 - Prob. 17ECh. 18.1 - Prob. 18ECh. 18.1 - Prob. 19ECh. 18.1 - Prob. 20ECh. 18.1 - Prob. 21ECh. 18.1 - Prob. 22ECh. 18.1 - Prob. 23ECh. 18.1 - Prob. 24ECh. 18.1 - Prob. 25ECh. 18.1 - Prob. 26ECh. 18.1 - Prob. 27ECh. 18.1 - Prob. 28ECh. 18.1 - Prob. 29ECh. 18.1 - Prob. 30ECh. 18.1 - Prob. 31ECh. 18.1 - Prob. 32ECh. 18.1 - Prob. 33ECh. 18.1 - Prob. 34ECh. 18.1 - Prob. 35ECh. 18.1 - Prob. 36ECh. 18.1 - Prob. 37ECh. 18.1 - Prob. 38ECh. 18.1 - Prob. 39ECh. 18.1 - Prob. 40ECh. 18.1 - Prob. 41ECh. 18.1 - Prob. 42ECh. 18.1 - Prob. 43ECh. 18.1 - Prob. 44ECh. 18.1 - Prob. 45ECh. 18.1 - Prob. 46ECh. 18.1 - Prob. 47ECh. 18.1 - Prob. 48ECh. 18.1 - Prob. 49ECh. 18.1 - Prob. 50ECh. 18.1 - Prob. 51ECh. 18.2 - Prob. 1PQCh. 18.2 - Prob. 2PQCh. 18.2 - Prob. 3PQCh. 18.2 - Prob. 4PQCh. 18.2 - Prob. 5PQCh. 18.2 - Prob. 1ECh. 18.2 - Prob. 2ECh. 18.2 - Prob. 3ECh. 18.2 - Prob. 4ECh. 18.2 - Prob. 5ECh. 18.2 - Prob. 6ECh. 18.2 - Prob. 7ECh. 18.2 - Prob. 8ECh. 18.2 - Prob. 9ECh. 18.2 - Prob. 10ECh. 18.2 - Prob. 11ECh. 18.2 - Prob. 12ECh. 18.2 - Prob. 13ECh. 18.2 - Prob. 14ECh. 18.2 - Prob. 15ECh. 18.2 - Prob. 16ECh. 18.2 - Prob. 17ECh. 18.2 - Prob. 18ECh. 18.2 - Prob. 19ECh. 18.2 - Prob. 20ECh. 18.2 - Prob. 21ECh. 18.2 - Prob. 22ECh. 18.2 - Prob. 23ECh. 18.2 - Prob. 24ECh. 18.2 - Prob. 25ECh. 18.2 - Prob. 26ECh. 18.2 - Prob. 27ECh. 18.2 - Prob. 28ECh. 18.2 - Prob. 29ECh. 18.2 - Prob. 30ECh. 18.2 - Prob. 31ECh. 18.2 - Prob. 32ECh. 18.2 - Prob. 33ECh. 18.2 - Prob. 34ECh. 18.2 - Prob. 35ECh. 18.2 - Prob. 36ECh. 18.2 - Prob. 37ECh. 18.2 - Prob. 38ECh. 18.3 - Prob. 1PQCh. 18.3 - Prob. 2PQCh. 18.3 - Prob. 3PQCh. 18.3 - Prob. 4PQCh. 18.3 - Prob. 5PQCh. 18.3 - Prob. 1ECh. 18.3 - Prob. 2ECh. 18.3 - Prob. 3ECh. 18.3 - Prob. 4ECh. 18.3 - Prob. 5ECh. 18.3 - Prob. 6ECh. 18.3 - Prob. 7ECh. 18.3 - Prob. 8ECh. 18.3 - Prob. 9ECh. 18.3 - Prob. 10ECh. 18.3 - Prob. 11ECh. 18.3 - Prob. 12ECh. 18.3 - Prob. 13ECh. 18.3 - Prob. 14ECh. 18.3 - Prob. 15ECh. 18.3 - Prob. 16ECh. 18.3 - Prob. 17ECh. 18.3 - Prob. 18ECh. 18.3 - Prob. 19ECh. 18.3 - Prob. 20ECh. 18.3 - Prob. 21ECh. 18.3 - Prob. 22ECh. 18.3 - Prob. 23ECh. 18.3 - Prob. 24ECh. 18.3 - Prob. 25ECh. 18.3 - Prob. 26ECh. 18.3 - Prob. 27ECh. 18.3 - Prob. 28ECh. 18.3 - Prob. 29ECh. 18.3 - Prob. 30ECh. 18.3 - Prob. 31ECh. 18.3 - Prob. 32ECh. 18.3 - Prob. 33ECh. 18.3 - Prob. 34ECh. 18.3 - Prob. 35ECh. 18.3 - Prob. 36ECh. 18.3 - Prob. 37ECh. 18.3 - Prob. 38ECh. 18.3 - Prob. 39ECh. 18.3 - Prob. 40ECh. 18.3 - Prob. 41ECh. 18.3 - Prob. 42ECh. 18.3 - Prob. 43ECh. 18.3 - Prob. 44ECh. 18 - Prob. 1CRECh. 18 - Prob. 2CRECh. 18 - Prob. 3CRECh. 18 - Prob. 4CRECh. 18 - Prob. 5CRECh. 18 - Prob. 6CRECh. 18 - Prob. 7CRECh. 18 - Prob. 8CRECh. 18 - Prob. 9CRECh. 18 - Prob. 10CRECh. 18 - Prob. 11CRECh. 18 - Prob. 12CRECh. 18 - Prob. 13CRECh. 18 - Prob. 14CRECh. 18 - Prob. 15CRECh. 18 - Prob. 16CRECh. 18 - Prob. 17CRECh. 18 - Prob. 18CRECh. 18 - Prob. 19CRECh. 18 - Prob. 20CRECh. 18 - Prob. 21CRECh. 18 - Prob. 22CRECh. 18 - Prob. 23CRECh. 18 - Prob. 24CRECh. 18 - Prob. 25CRECh. 18 - Prob. 26CRECh. 18 - Prob. 27CRECh. 18 - Prob. 28CRECh. 18 - Prob. 29CRECh. 18 - Prob. 30CRECh. 18 - Prob. 31CRECh. 18 - Prob. 32CRECh. 18 - Prob. 33CRECh. 18 - Prob. 34CRECh. 18 - Prob. 35CRECh. 18 - Prob. 36CRECh. 18 - Prob. 37CRECh. 18 - Prob. 38CRECh. 18 - Prob. 39CRECh. 18 - Prob. 40CRECh. 18 - Prob. 41CRE
Knowledge Booster
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, calculus and related others by exploring similar questions and additional content below.Similar questions
- Evaluate the line intergral by stokes theorem where, F(vector arrow)=[0,xyz,0] ( i hat, j hat, k hat components) , C is the boundary of the traingle with vertices (1,0,0),(0,1,0) and (0,0,1).arrow_forwardFind a vector normal to the surface 3z 3 + x 2 y - y 2 x = 1 at P =(1,-1,1) .arrow_forwardon a parametrized surface The tangent plane at a point Po (f (uo.vo),g (uovo),h(uovo)) r(u,v) = f(u,v) i + g(u,v) j + h(u,v) k is the plane through På normal to the vector ru (uo.Vo) xrv (uo,vo), the cross product of the tangent vectors ru (uo,vo) and rv (uovo) at Po. Find an equation for the plane tangent to the surface at Po. Then find a Cartesian equation for the surface and sketch the surface and tangent plane together. The circular cylinder r(0,z) = (2 sin (20)) i + (4sin²0) j+zk at the point Po (√3,3,2) corresponding to (0,z) = An equation for the plane tangent to the surface at Po is (Type an equation using x, y, and z as the variables.) A Cartesian equation for the surface is (Type an equation using x, y, and z as the variables.) Choose the correct graph of the surface, point, and tangent plane below. A. B B. C. w:arrow_forward
- 4. Consider the vector function r(z, y) (r, y, r2 +2y"). (a) Re-write this vector function as surface function in the form f(1,y). (b) Describe and draw the shape of the surface function using contour lines and algebraic analysis as needed. Explain the contour shapes in all three orthogonal directions and explain and label all intercepts as needed. (c) Consider the contour of the surface function on the plane z= for this contour in vector form. 0. Write the general equationarrow_forwardin both ways of stokes theorm, thank youarrow_forwardLet us verify Stokes' theorem using the vector field F = (x 2 - y)i + 4zj + x 2k, where the closed contour consists of the x and y coordinate axes and that portion of the circle 2 + y 2 = a 2 that lies in the first quadrant with z = 1arrow_forward
- Identify the surface by eliminating the parameters from the vector-valued function r(u,v) = 3 cosv cosui + 3 cosv sinuj + Śsinvk a. plane b. sphere c. paraboloid d. cylinder e. ellipsoid d b a e (Darrow_forwardFind the space curve represented by the intersection of the surfaces. Then represent the curve by a vector-valued function using the given parameter (Use technology to sketch) x2 + y? + z? = 10, x + y = 4 x = 2 + sin (t)arrow_forwardFind a unit vector u that is normal to the level curve of f(x, y) = 5x²y through P = (x, y) = (5, −4) at P. The figure shows the level curves of f(x, y) = ax² y. a u = y (x,y) a (Give your answer using component form or standard basis vectors. Express numbers in exact form. Use symbolic notation and fractions where needed.)arrow_forward
- show all the work plssarrow_forward2.Vector analysis (calculus 4)arrow_forwardLet rlu, v)= [2usin(v), 2ucos(v), 2] be a parametrization of a surface S, where 0sus2,0svs2n. Then we have O A Sisacylinder of radius 2 and the normal vector is N= [0, 0, -4u]. O B. S isa disc of radius 2 and the normal vector is N= 14u, 0, 0]. OC Sisacylinder of radius 4 and the normal vector is N= [4u, 0, 0]. O D. S isadisc of radius 4 and the normal vector is N= (0, 0, -4u).arrow_forward
arrow_back_ios
SEE MORE QUESTIONS
arrow_forward_ios
Recommended textbooks for you
- Algebra and Trigonometry (MindTap Course List)AlgebraISBN:9781305071742Author:James Stewart, Lothar Redlin, Saleem WatsonPublisher:Cengage Learning
Algebra and Trigonometry (MindTap Course List)
Algebra
ISBN:9781305071742
Author:James Stewart, Lothar Redlin, Saleem Watson
Publisher:Cengage Learning
01 - What Is an Integral in Calculus? Learn Calculus Integration and how to Solve Integrals.; Author: Math and Science;https://www.youtube.com/watch?v=BHRWArTFgTs;License: Standard YouTube License, CC-BY