Explanation Use the formula for obtaining the volume as a triple integral and using the divergence theorem Given : Let F ( x , y , z ) = 〈 x , y , z 〉 Formula used : d i v ( F ) = ∂ x ∂ x + ∂ y ∂ y + ∂ z ∂ z Proof : Using the volume as a triple integral, we have V o l u m e ( W ) = 1 3 ∭ W d V -------- (a) However, using Divergence Theorem, we know that d ...

4th Edition

ISBN: 9781319050733

Author: Rogawski

Publisher: MAC HIGHER

See similar textbooks

Concept explainers

Arc Length

Arc length can be thought of as the distance you would travel if you walked along the path of a curve. Arc length is used in a wide range of real applications. We might be interested in knowing how far a rocket travels if it is launched along a parabolic…

Line Integral

A line integral is one of the important topics that are discussed in the calculus syllabus. When we have a function that we want to integrate, and we evaluate the function alongside a curve, we define it as a line integral. Evaluation of a function along…

Triple Integral

Examples:

Videos

Question

Chapter 18.3, Problem 20E

To determine

To prove:

That if $W$ is a region $R^{3}$ with a smooth boundary $S$ then

$V o l u m e (W) = \frac{1}{3} \iint_{S} F . d S$

Expert Solution & Answer

Want to see the full answer?

Check out a sample textbook solution

See solution

Chapter 18.3, Problem 19E

Chapter 18.3, Problem 21E

Students have asked these similar questions

Find the Laplace transform of f(t). f(t) = sin(2t)e-4t

Find the Laplace transform of f(t). f(t) = 8t6 + 3t4 - 2t + 5

42.37590 is correct and 42.11205 is incorect.

Chapter 18 Solutions

CALCULUS (CLOTH)

Ch. 18.1 - Prob. 1PQ Ch. 18.1 - Prob. 2PQ Ch. 18.1 - Prob. 3PQ Ch. 18.1 - Prob. 4PQ Ch. 18.1 - Prob. 5PQ Ch. 18.1 - Prob. 1E Ch. 18.1 - Prob. 2E Ch. 18.1 - Prob. 3E Ch. 18.1 - Prob. 4E Ch. 18.1 - Prob. 5E

Ch. 18.1 - Prob. 6E Ch. 18.1 - Prob. 7E Ch. 18.1 - Prob. 8E Ch. 18.1 - Prob. 9E Ch. 18.1 - Prob. 10E Ch. 18.1 - Prob. 11E Ch. 18.1 - Prob. 12E Ch. 18.1 - Prob. 13E Ch. 18.1 - Prob. 14E Ch. 18.1 - Prob. 15E Ch. 18.1 - Prob. 16E Ch. 18.1 - Prob. 17E Ch. 18.1 - Prob. 18E Ch. 18.1 - Prob. 19E Ch. 18.1 - Prob. 20E Ch. 18.1 - Prob. 21E Ch. 18.1 - Prob. 22E Ch. 18.1 - Prob. 23E Ch. 18.1 - Prob. 24E Ch. 18.1 - Prob. 25E Ch. 18.1 - Prob. 26E Ch. 18.1 - Prob. 27E Ch. 18.1 - Prob. 28E Ch. 18.1 - Prob. 29E Ch. 18.1 - Prob. 30E Ch. 18.1 - Prob. 31E Ch. 18.1 - Prob. 32E Ch. 18.1 - Prob. 33E Ch. 18.1 - Prob. 34E Ch. 18.1 - Prob. 35E Ch. 18.1 - Prob. 36E Ch. 18.1 - Prob. 37E Ch. 18.1 - Prob. 38E Ch. 18.1 - Prob. 39E Ch. 18.1 - Prob. 40E Ch. 18.1 - Prob. 41E Ch. 18.1 - Prob. 42E Ch. 18.1 - Prob. 43E Ch. 18.1 - Prob. 44E Ch. 18.1 - Prob. 45E Ch. 18.1 - Prob. 46E Ch. 18.1 - Prob. 47E Ch. 18.1 - Prob. 48E Ch. 18.1 - Prob. 49E Ch. 18.1 - Prob. 50E Ch. 18.1 - Prob. 51E Ch. 18.2 - Prob. 1PQ Ch. 18.2 - Prob. 2PQ Ch. 18.2 - Prob. 3PQ Ch. 18.2 - Prob. 4PQ Ch. 18.2 - Prob. 5PQ Ch. 18.2 - Prob. 1E Ch. 18.2 - Prob. 2E Ch. 18.2 - Prob. 3E Ch. 18.2 - Prob. 4E Ch. 18.2 - Prob. 5E Ch. 18.2 - Prob. 6E Ch. 18.2 - Prob. 7E Ch. 18.2 - Prob. 8E Ch. 18.2 - Prob. 9E Ch. 18.2 - Prob. 10E Ch. 18.2 - Prob. 11E Ch. 18.2 - Prob. 12E Ch. 18.2 - Prob. 13E Ch. 18.2 - Prob. 14E Ch. 18.2 - Prob. 15E Ch. 18.2 - Prob. 16E Ch. 18.2 - Prob. 17E Ch. 18.2 - Prob. 18E Ch. 18.2 - Prob. 19E Ch. 18.2 - Prob. 20E Ch. 18.2 - Prob. 21E Ch. 18.2 - Prob. 22E Ch. 18.2 - Prob. 23E Ch. 18.2 - Prob. 24E Ch. 18.2 - Prob. 25E Ch. 18.2 - Prob. 26E Ch. 18.2 - Prob. 27E Ch. 18.2 - Prob. 28E Ch. 18.2 - Prob. 29E Ch. 18.2 - Prob. 30E Ch. 18.2 - Prob. 31E Ch. 18.2 - Prob. 32E Ch. 18.2 - Prob. 33E Ch. 18.2 - Prob. 34E Ch. 18.2 - Prob. 35E Ch. 18.2 - Prob. 36E Ch. 18.2 - Prob. 37E Ch. 18.2 - Prob. 38E Ch. 18.3 - Prob. 1PQ Ch. 18.3 - Prob. 2PQ Ch. 18.3 - Prob. 3PQ Ch. 18.3 - Prob. 4PQ Ch. 18.3 - Prob. 5PQ Ch. 18.3 - Prob. 1E Ch. 18.3 - Prob. 2E Ch. 18.3 - Prob. 3E Ch. 18.3 - Prob. 4E Ch. 18.3 - Prob. 5E Ch. 18.3 - Prob. 6E Ch. 18.3 - Prob. 7E Ch. 18.3 - Prob. 8E Ch. 18.3 - Prob. 9E Ch. 18.3 - Prob. 10E Ch. 18.3 - Prob. 11E Ch. 18.3 - Prob. 12E Ch. 18.3 - Prob. 13E Ch. 18.3 - Prob. 14E Ch. 18.3 - Prob. 15E Ch. 18.3 - Prob. 16E Ch. 18.3 - Prob. 17E Ch. 18.3 - Prob. 18E Ch. 18.3 - Prob. 19E Ch. 18.3 - Prob. 20E Ch. 18.3 - Prob. 21E Ch. 18.3 - Prob. 22E Ch. 18.3 - Prob. 23E Ch. 18.3 - Prob. 24E Ch. 18.3 - Prob. 25E Ch. 18.3 - Prob. 26E Ch. 18.3 - Prob. 27E Ch. 18.3 - Prob. 28E Ch. 18.3 - Prob. 29E Ch. 18.3 - Prob. 30E Ch. 18.3 - Prob. 31E Ch. 18.3 - Prob. 32E Ch. 18.3 - Prob. 33E Ch. 18.3 - Prob. 34E Ch. 18.3 - Prob. 35E Ch. 18.3 - Prob. 36E Ch. 18.3 - Prob. 37E Ch. 18.3 - Prob. 38E Ch. 18.3 - Prob. 39E Ch. 18.3 - Prob. 40E Ch. 18.3 - Prob. 41E Ch. 18.3 - Prob. 42E Ch. 18.3 - Prob. 43E Ch. 18.3 - Prob. 44E Ch. 18 - Prob. 1CRE Ch. 18 - Prob. 2CRE Ch. 18 - Prob. 3CRE Ch. 18 - Prob. 4CRE Ch. 18 - Prob. 5CRE Ch. 18 - Prob. 6CRE Ch. 18 - Prob. 7CRE Ch. 18 - Prob. 8CRE Ch. 18 - Prob. 9CRE Ch. 18 - Prob. 10CRE Ch. 18 - Prob. 11CRE Ch. 18 - Prob. 12CRE Ch. 18 - Prob. 13CRE Ch. 18 - Prob. 14CRE Ch. 18 - Prob. 15CRE Ch. 18 - Prob. 16CRE Ch. 18 - Prob. 17CRE Ch. 18 - Prob. 18CRE Ch. 18 - Prob. 19CRE Ch. 18 - Prob. 20CRE Ch. 18 - Prob. 21CRE Ch. 18 - Prob. 22CRE Ch. 18 - Prob. 23CRE Ch. 18 - Prob. 24CRE Ch. 18 - Prob. 25CRE Ch. 18 - Prob. 26CRE Ch. 18 - Prob. 27CRE Ch. 18 - Prob. 28CRE Ch. 18 - Prob. 29CRE Ch. 18 - Prob. 30CRE Ch. 18 - Prob. 31CRE Ch. 18 - Prob. 32CRE Ch. 18 - Prob. 33CRE Ch. 18 - Prob. 34CRE Ch. 18 - Prob. 35CRE Ch. 18 - Prob. 36CRE Ch. 18 - Prob. 37CRE Ch. 18 - Prob. 38CRE Ch. 18 - Prob. 39CRE Ch. 18 - Prob. 40CRE Ch. 18 - Prob. 41CRE

Knowledge Booster

$Calculus$

Learn more about

Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, calculus and related others by exploring similar questions and additional content below.

To prove : That if W is a region R 3 with a smooth boundary S then V o l u m e ( W ) = 1 3 ∬ S F . d S

Solution Summary: The author explains the formula for obtaining the volume as a triple integral and using the divergence theorem.

Concept explainers

Videos

To prove:

That if $W$ is a region $R^{3}$ with a smooth boundary $S$ then

$V o l u m e (W) = \frac{1}{3} \iint_{S} F . d S$

Want to see the full answer?

Chapter 18 Solutions

To prove : That if W is a region R 3 with a smooth boundary S then V o l u m e ( W ) = 1 3 ∬ S F . d S

Solution Summary: The author explains the formula for obtaining the volume as a triple integral and using the divergence theorem.

Concept explainers

Videos

To prove: That if W is a region R3 with a smooth boundary S then Volume(W)=13∬SF.dS

Want to see the full answer?

Chapter 18 Solutions

To prove:

That if $W$ is a region $R^{3}$ with a smooth boundary $S$ then

$V o l u m e (W) = \frac{1}{3} \iint_{S} F . d S$