Chapter 18, Problem 8MCP

An electron is released between the plates of a charged parallel-plate capacitor very close to the right-hand plate. Just as it reaches the left-hand plate, its speed is v If the distance between the plates were halved without changing the electric potential difference between them, then the speed of the electron when it reached the left-hand plate would be

1. A.    2v.
2. B.     $\text{v}\sqrt{2}$.
3. C.     v.
4. D.    $v/\sqrt{2}$.
5. E.     v/2.