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Reaction of p-cresol with two equivalents of
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ORGANIC CHEMISTRY
- Compound H (C8H6O3) gives a precipitate when treated with hydroxylamine in aqueous ethanol and a silver mirror when treated with Tollens solution. Following is its 1H-NMR spectrum. Deduce the structure of compound H.arrow_forwardFollowing are 1H-NMR spectra for compounds G, H, and I, each with the molecular formula C5H12O. Each is a liquid at room temperature, is slightly soluble in water, and reacts with sodium metal with the evolution of a gas. (a) Propose structural formulas of compounds G, H, and I. (b) Explain why there are four lines between 0.86 and 0.90 for compound G. (c) Explain why the 2H multiplets at 1.5 and 3.5 for compound H are so complex.arrow_forwardPropose a structural formula for each compound consistent with its 1H-NMR and 13C-NMR spectra. (a) C5H10O2 (b) C7H14O2 (c) C6 H12O2 (d) C7H12O4 (e) C4H7ClO2 (f) C4H6O2arrow_forward
- How can 1H NMR distinguish between the compounds in the following pairs?arrow_forwardWhat is the structure of a compound of molecular formula C10H14O2 that shows a strong IR absorption at 3150–2850 cm-1 and gives the following 1H NMR absorptions: 1.4 (triplet, 6 H), 4.0 (quartet, 4 H), and 6.8 (singlet, 4 H) ppm?arrow_forwardCompound X (molecular formula C10H120) was treated with NH2NH2, ¯OH to yield compound Y (molecular formula C10H14). Match the 1H NMR spectra of X and Y to the corresponding structures of X and Y. Compound NH2NH2 Compound 'H NMR of X 6 H OH Y 1 H 5H 8. 6. 4 ppm or H NMR of Y 6 H 2H 5H 1 H multiplet multiplet 8. 6. 4. 3. 1 nnm 2. 2. 3, O:arrow_forward
- Reaction of aldehyde D with amino alcohol E in the presence of NaH forms F (molecular formula C11H15NO2). F absorbs at 1730 cm−1 in its IR spectrum. F also shows eight lines in its 13C NMR spectrum, and gives the following 1H NMR spectrum: 2.32 (singlet, 6 H), 3.05 (triplet, 2 H), 4.20 (triplet, 2 H), 6.97 (doublet, 2 H), 7.82 (doublet, 2 H), and 9.97 (singlet, 1 H) ppm. Propose a structure for F. We will learn about this reaction in Chapter 18.arrow_forwardReaction of aldehyde D with amino alcohol E in the presence of NaH forms F (molecular formula C11H15NO2). F absorbs at 1730 cm−1 in its IR spectrum. F also shows eight lines in its 13C NMR spectrum, and gives the following 1H NMR spectrum: 2.32 (singlet, 6 H), 3.05 (triplet, 2 H), 4.20 (triplet, 2 H), 6.97 (doublet, 2 H), 7.82 (doublet, 2 H), and 9.97 (singlet, 1 H) ppm. Propose a structure for F. We will learn about this reaction in Chapter 16.arrow_forwardWhat is the structure of a compound of molecular formula C1H1402 that shows a strong IR absorption at 3150-2850 cm1 and gives the following 'H NMR absorptions: 1.4 (triplet, 6 H), 4.0 (quartet, 4 H), and 6.8 (singlet, 4 H) ppm?arrow_forward
- When treated with an equivalent of methanol, compound A, with molecular formula C4H6Cl2O, forms the compound whose 1H NMR spectrum is shownhere. Identify compound A.arrow_forwardUsing the following NMR data, and the molecular formula C9H120, select the best compound. NMR Data triplet 1.15 ppm (3H) quartet 2.75 ppm (2H) singlet 3.75 ppm (3H) split quartet 7.5 ppm (4H) Multiple choice options A: 1-ethyl-4-methoxybenzene B: 1-ethoxy-4-methylbenzene C: 1-bromo-4-methylbenzene D: 1-bromo-4-ethylbenzenearrow_forwardCompound X (molecular formula C10H12O) was treated with NH2NH2, −OH to yield compound Y (molecular formula C10H14). Based on the 1HNMR spectra of X and Y given below, what are the structures of X and Y?arrow_forward
- Organic ChemistryChemistryISBN:9781305580350Author:William H. Brown, Brent L. Iverson, Eric Anslyn, Christopher S. FootePublisher:Cengage Learning