Chapter 18, Problem 18.67QE

Interpretation Introduction

Interpretation:

Solubility product ${\text{K}}_{\text{sp}}$ for $\text{Cd}{\left(\text{OH}\right)}_{\text{2}}$ has to be calculated.

Concept Introduction:

The relation between standard cell potential and equilibrium constant is as follows.

  $\text{lnK = }\frac{{\text{nE}}^{\text{0}}}{\text{0}\text{.0257}}\text{ at 298K}$

The relation between solubility product ${\text{K}}_{\text{sp}}$ and equilibrium constant is as follows.

  ${\text{K}}_{\text{sp}}{\text{= e}}^{\text{+lnK}}$