Chapter 18, Problem 18.60QE

Interpretation Introduction

Interpretation:

${\text{E}}^0\text{,}\Delta {\text{G}}^0\text{and}{\text{K}}_{\text{eq}}$ for the reaction has to be calculated.

Concept Introduction:

In voltaic cell, the maximum cell potential is directly related to the free energy difference between the reactants and products in the cell.

  $\begin{array}{c}{\text{ΔG}}^{\text{0}}{\text{= -nFE}}^{\text{0}}\\ \text{n = Number of moles transferred per mole of reactant and products}\\ \text{F = Faradayconstant=96485C/mol}\\ {\text{ E}}^{\text{0}}\text{= Volts = Work(J)/Charge(C)}\end{array}$

The relation between standard cell potential and equilibrium constant is as follows.

  $\text{log}\text{K = }\frac{{\text{nE}}^{\text{0}}}{\text{0}\text{.0591}}\text{ at 298K}$

The relation between solubility product ${\text{K}}_{\text{sp}}$ and equilibrium constant is as follows.

  ${\text{K}}_{\text{sp}}{\text{= e}}^{\text{+lnK}}$