The detailed mechanism for the given reaction is to be drawn and major product is determined. Concept introduction: TsOH is a strong acid. Under mild acidic conditions, the N acts as the nucleophile and undergoes a nucleophilic addition reaction. Under mild acidic conditions, the carbonyl oxygen will not get protonated. During the reaction, five membered cyclic ring formation takes place. The final product is a cyclic hemiacetal – a functional group that has O and N attached to the same C atom.

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Answer 1

Question

Chapter 18, Problem 18.62P

Interpretation Introduction

Interpretation:

The detailed mechanism for the given reaction is to be drawn and major product is determined.

Concept introduction:

TsOH is a strong acid. Under mild acidic conditions, the N acts as the nucleophile and undergoes a nucleophilic addition reaction. Under mild acidic conditions, the carbonyl oxygen will not get protonated. During the reaction, five membered cyclic ring formation takes place. The final product is a cyclic hemiacetal – a functional group that has O and N attached to the same C atom.

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Answer 2

Question

Chapter 18, Problem 18.62P

Interpretation Introduction

Interpretation:

The detailed mechanism for the given reaction is to be drawn and major product is determined.

Concept introduction:

TsOH is a strong acid. Under mild acidic conditions, the N acts as the nucleophile and undergoes a nucleophilic addition reaction. Under mild acidic conditions, the carbonyl oxygen will not get protonated. During the reaction, five membered cyclic ring formation takes place. The final product is a cyclic hemiacetal – a functional group that has O and N attached to the same C atom.

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Answer 3

Question

Chapter 18, Problem 18.62P

Interpretation Introduction

Interpretation:

The detailed mechanism for the given reaction is to be drawn and major product is determined.

Concept introduction:

TsOH is a strong acid. Under mild acidic conditions, the N acts as the nucleophile and undergoes a nucleophilic addition reaction. Under mild acidic conditions, the carbonyl oxygen will not get protonated. During the reaction, five membered cyclic ring formation takes place. The final product is a cyclic hemiacetal – a functional group that has O and N attached to the same C atom.

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Answer 4

Question

Chapter 18, Problem 18.62P

Interpretation Introduction

Interpretation:

The detailed mechanism for the given reaction is to be drawn and major product is determined.

Concept introduction:

TsOH is a strong acid. Under mild acidic conditions, the N acts as the nucleophile and undergoes a nucleophilic addition reaction. Under mild acidic conditions, the carbonyl oxygen will not get protonated. During the reaction, five membered cyclic ring formation takes place. The final product is a cyclic hemiacetal – a functional group that has O and N attached to the same C atom.

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Answer 5

Chapter 18, Problem 18.62P

Interpretation Introduction

Interpretation:

The detailed mechanism for the given reaction is to be drawn and major product is determined.

Concept introduction:

TsOH is a strong acid. Under mild acidic conditions, the N acts as the nucleophile and undergoes a nucleophilic addition reaction. Under mild acidic conditions, the carbonyl oxygen will not get protonated. During the reaction, five membered cyclic ring formation takes place. The final product is a cyclic hemiacetal – a functional group that has O and N attached to the same C atom.

Answer 6

Chapter 18, Problem 18.62P

Interpretation Introduction

Interpretation:

The detailed mechanism for the given reaction is to be drawn and major product is determined.

Concept introduction:

TsOH is a strong acid. Under mild acidic conditions, the N acts as the nucleophile and undergoes a nucleophilic addition reaction. Under mild acidic conditions, the carbonyl oxygen will not get protonated. During the reaction, five membered cyclic ring formation takes place. The final product is a cyclic hemiacetal – a functional group that has O and N attached to the same C atom.

Answer 7

Chapter 18, Problem 18.62P

Interpretation Introduction

Interpretation:

The detailed mechanism for the given reaction is to be drawn and major product is determined.

Concept introduction:

TsOH is a strong acid. Under mild acidic conditions, the N acts as the nucleophile and undergoes a nucleophilic addition reaction. Under mild acidic conditions, the carbonyl oxygen will not get protonated. During the reaction, five membered cyclic ring formation takes place. The final product is a cyclic hemiacetal – a functional group that has O and N attached to the same C atom.

Answer 8

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Answer 11

Ch. 18 - Prob. 18.1P Ch. 18 - Prob. 18.2P Ch. 18 - Prob. 18.3P Ch. 18 - Prob. 18.4P Ch. 18 - Prob. 18.5P Ch. 18 - Prob. 18.6P Ch. 18 - Prob. 18.7P Ch. 18 - Prob. 18.8P Ch. 18 - Prob. 18.9P Ch. 18 - Prob. 18.10P

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Chapter 18 Solutions