(a) Interpretation: The products of the reaction between HCN and HO − are to be drawn. Concept introduction: The hydoxide ion is both a base and a nucleophile. It is quite strong as a base and deprotonates most acids, forming its conjugate acid, H 2 O .

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Answer 1

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Chapter 18, Problem 18.5YT

Interpretation Introduction

(a)

Interpretation:

The products of the reaction between HCN and HO− are to be drawn.

Concept introduction:

The hydoxide ion is both a base and a nucleophile. It is quite strong as a base and deprotonates most acids, forming its conjugate acid, H2O.

Interpretation Introduction

(b)

Interpretation:

The numerical factor by which the products side of the reaction between HCN and HO− is favored is to be determined from the appropriate pKa values.

Concept introduction:

In an acid-base reaction, the side with weaker acid (and base) is favored. The pKa values of the two acids in the reaction can be used to determine the factor by which that side is favored. The factor is given by the difference between the pKa values, 10Δ(pKa).

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Part VII. Below are the 'HNMR, 13 C-NMR, COSY 2D- NMR, and HSQC 2D-NMR (similar with HETCOR but axes are reversed) spectra of an organic compound with molecular formula C6H1003 - Assign chemical shift values to the H and c atoms of the compound. Find the structure. Show complete solutions. Predicted 1H NMR Spectrum 4.7 4.6 4.5 4.4 4.3 4.2 4.1 4.0 3.9 3.8 3.7 3.6 3.5 3.4 3.3 3.2 3.1 3.0 2.9 2.8 2.7 2.6 2.5 2.4 2.3 2.2 2.1 2.0 1.9 1.8 1.7 1.6 1.5 1.4 1.3 1.2 1.1 f1 (ppm) Predicted 13C NMR Spectrum 100 f1 (ppm) 30 220 210 200 190 180 170 160 150 140 130 120 110 90 80 70 -26 60 50 40 46 30 20 115 10 1.0 0.9 0.8 0 -10

Answer 2

Question

Chapter 18, Problem 18.5YT

Interpretation Introduction

(a)

Interpretation:

The products of the reaction between HCN and HO− are to be drawn.

Concept introduction:

The hydoxide ion is both a base and a nucleophile. It is quite strong as a base and deprotonates most acids, forming its conjugate acid, H2O.

Interpretation Introduction

(b)

Interpretation:

The numerical factor by which the products side of the reaction between HCN and HO− is favored is to be determined from the appropriate pKa values.

Concept introduction:

In an acid-base reaction, the side with weaker acid (and base) is favored. The pKa values of the two acids in the reaction can be used to determine the factor by which that side is favored. The factor is given by the difference between the pKa values, 10Δ(pKa).

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Answer 3

Question

Chapter 18, Problem 18.5YT

Interpretation Introduction

(a)

Interpretation:

The products of the reaction between HCN and HO− are to be drawn.

Concept introduction:

The hydoxide ion is both a base and a nucleophile. It is quite strong as a base and deprotonates most acids, forming its conjugate acid, H2O.

Interpretation Introduction

(b)

Interpretation:

The numerical factor by which the products side of the reaction between HCN and HO− is favored is to be determined from the appropriate pKa values.

Concept introduction:

In an acid-base reaction, the side with weaker acid (and base) is favored. The pKa values of the two acids in the reaction can be used to determine the factor by which that side is favored. The factor is given by the difference between the pKa values, 10Δ(pKa).

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Answer 4

Question

Chapter 18, Problem 18.5YT

Interpretation Introduction

(a)

Interpretation:

The products of the reaction between HCN and HO− are to be drawn.

Concept introduction:

The hydoxide ion is both a base and a nucleophile. It is quite strong as a base and deprotonates most acids, forming its conjugate acid, H2O.

Interpretation Introduction

(b)

Interpretation:

The numerical factor by which the products side of the reaction between HCN and HO− is favored is to be determined from the appropriate pKa values.

Concept introduction:

In an acid-base reaction, the side with weaker acid (and base) is favored. The pKa values of the two acids in the reaction can be used to determine the factor by which that side is favored. The factor is given by the difference between the pKa values, 10Δ(pKa).

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Answer 5

Chapter 18, Problem 18.5YT

Interpretation Introduction

(a)

Interpretation:

The products of the reaction between HCN and HO− are to be drawn.

Concept introduction:

The hydoxide ion is both a base and a nucleophile. It is quite strong as a base and deprotonates most acids, forming its conjugate acid, H2O.

Interpretation Introduction

(b)

Interpretation:

The numerical factor by which the products side of the reaction between HCN and HO− is favored is to be determined from the appropriate pKa values.

Concept introduction:

In an acid-base reaction, the side with weaker acid (and base) is favored. The pKa values of the two acids in the reaction can be used to determine the factor by which that side is favored. The factor is given by the difference between the pKa values, 10Δ(pKa).

Answer 6

Chapter 18, Problem 18.5YT

Interpretation Introduction

(a)

Interpretation:

The products of the reaction between HCN and HO− are to be drawn.

Concept introduction:

The hydoxide ion is both a base and a nucleophile. It is quite strong as a base and deprotonates most acids, forming its conjugate acid, H2O.

Answer 7

Chapter 18, Problem 18.5YT

Interpretation Introduction

(a)

Interpretation:

The products of the reaction between HCN and HO− are to be drawn.

Concept introduction:

The hydoxide ion is both a base and a nucleophile. It is quite strong as a base and deprotonates most acids, forming its conjugate acid, H2O.

Answer 8

Interpretation Introduction

(b)

Interpretation:

The numerical factor by which the products side of the reaction between HCN and HO− is favored is to be determined from the appropriate pKa values.

Concept introduction:

In an acid-base reaction, the side with weaker acid (and base) is favored. The pKa values of the two acids in the reaction can be used to determine the factor by which that side is favored. The factor is given by the difference between the pKa values, 10Δ(pKa).

Answer 9

Interpretation Introduction

(b)

Interpretation:

The numerical factor by which the products side of the reaction between HCN and HO− is favored is to be determined from the appropriate pKa values.

Concept introduction:

In an acid-base reaction, the side with weaker acid (and base) is favored. The pKa values of the two acids in the reaction can be used to determine the factor by which that side is favored. The factor is given by the difference between the pKa values, 10Δ(pKa).

Answer 10

Expert Solution & Answer

Answer 11

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Answer 12

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Answer 13

Ch. 18 - Prob. 18.1P Ch. 18 - Prob. 18.2P Ch. 18 - Prob. 18.3P Ch. 18 - Prob. 18.4P Ch. 18 - Prob. 18.5P Ch. 18 - Prob. 18.6P Ch. 18 - Prob. 18.7P Ch. 18 - Prob. 18.8P Ch. 18 - Prob. 18.9P Ch. 18 - Prob. 18.10P

(a) Interpretation: The products of the reaction between HCN and HO − are to be drawn. Concept introduction: The hydoxide ion is both a base and a nucleophile. It is quite strong as a base and deprotonates most acids, forming its conjugate acid, H 2 O .

Solution Summary: The author explains that the products of the reaction between HCN and HO- are to be drawn.

(a)

Interpretation:

The products of the reaction between HCN and HO− are to be drawn.

Concept introduction:

The hydoxide ion is both a base and a nucleophile. It is quite strong as a base and deprotonates most acids, forming its conjugate acid, H2O.

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Chapter 18 Solutions

(a) Interpretation: The products of the reaction between HCN and HO − are to be drawn. Concept introduction: The hydoxide ion is both a base and a nucleophile. It is quite strong as a base and deprotonates most acids, forming its conjugate acid, H 2 O .

Solution Summary: The author explains that the products of the reaction between HCN and HO- are to be drawn.

(a) Interpretation: The products of the reaction between HCN and HO− are to be drawn. Concept introduction: The hydoxide ion is both a base and a nucleophile. It is quite strong as a base and deprotonates most acids, forming its conjugate acid, H2O.

Want to see the full answer?

Chapter 18 Solutions

(a)

Interpretation:

The products of the reaction between HCN and HO− are to be drawn.

Concept introduction:

The hydoxide ion is both a base and a nucleophile. It is quite strong as a base and deprotonates most acids, forming its conjugate acid, H2O.