Chapter 18, Problem 18.134MP

Interpretation Introduction

(a)

Interpretation:

The temperature when the equilibrium would have twice as much ${\text{NO}}_{\text{2}}$ as ${\text{N}}_2{\text{O}}_4$ is to be calculated.

Concept introduction:

The expression to evaluate $\text{ΔH}°$ is given by the equation as follows:

$\text{ln}\frac{K_{\text{1}}}{K_2}\text{=}\frac{\text{Δ}H°}{R}\left(\frac{1}{T_2}-\frac{1}{T_1}\right)$

Interpretation Introduction

(b)

Interpretation:

The temperature when the equilibrium mixture has equal amounts of ${\text{NO}}_{\text{2}}$ and ${\text{N}}_2{\text{O}}_4$ is to be calculated.

Concept introduction:

The expression to evaluate $\text{ΔH}°$ is given by the equation as follows:

$\text{ln}\frac{K_{\text{1}}}{K_2}\text{=}\frac{\text{Δ}H°}{R}\left(\frac{1}{T_2}-\frac{1}{T_1}\right)$