(a) Interpretation: The state that has greater entropy in terms of probability is to be identified and explained. Concept introduction: The third law of thermodynamics suggests that the entropy associated with a perfectly crystalline substance is zero. The Boltzmann equation used to calculate entropy is as follows: S = k ln W Where, k denotes Boltzmann’s constant. W denotes probability or ways that a specific arrangement can be achieved. S denotes entropy.
(a) Interpretation: The state that has greater entropy in terms of probability is to be identified and explained. Concept introduction: The third law of thermodynamics suggests that the entropy associated with a perfectly crystalline substance is zero. The Boltzmann equation used to calculate entropy is as follows: S = k ln W Where, k denotes Boltzmann’s constant. W denotes probability or ways that a specific arrangement can be achieved. S denotes entropy.
Solution Summary: The author explains that the third law of thermodynamics suggests that entropy associated with a perfectly crystalline substance is zero.
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Consider the following reaction:
CH3OH(g)
CO(g) + 2H2(g)
(Note that AG,CH3OH(g) = -162.3 kJ/mol and AG,co(g)=-137.2 kJ/mol.)
Part A
Calculate AG for this reaction at 25 °C under the following conditions:
PCH₂OH
Pco
PH2
0.815 atm
=
0.140 atm
0.170 atm
Express your answer in kilojoules to three significant figures.
Ο ΑΣΦ
AG = -150
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Calculate the free energy change under nonstandard conditions (AGrxn) by using the following relationship:
AGrxn = AGrxn + RTInQ,
AGxn+RTInQ,
where AGxn is the standard free energy change, R is the ideal gas constant, T is the temperature in kelvins, a
is the reaction quotient.
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Identify and provide a brief explanation of Gas Chromatography (GC) within the context of chemical analysis of food. Incorporate the specific application name, provide a concise overview of sample preparation methods, outline instrumental parameters and conditions ultilized, and summarise the outcomes and findings achieved through this analytical approach.
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