Concept explainers
(a)
Interpretation: The given disaccharide has to be classified as a reducing or non-reducing sugar.
Concept introduction: Monosaccharides and most of the disaccharides give positive test with Benedict’s solution. It is used to detect the presence of
(b)
Interpretation: The given disaccharide has to be classified as a reducing or non-reducing sugar.
Concept introduction: Monosaccharides and most of the disaccharides give positive test with Benedict’s solution. It is used to detect the presence of aldehyde or alpha hydroxy ketones. A positive test with Benedict’s solution is confirmed by the formation of a brick-red precipitate.
(c)
Interpretation: The given disaccharide has to be classified as a reducing or non-reducing sugar.
Concept introduction: Monosaccharides and most of the disaccharides give positive test with Benedict’s solution. It is used to detect the presence of aldehyde or alpha hydroxy ketones. A positive test with Benedict’s solution is confirmed by the formation of a brick-red precipitate.
(d)
Interpretation: The given disaccharide has to be classified as a reducing or non-reducing sugar.
Concept introduction: Monosaccharides and most of the disaccharides give positive test with Benedict’s solution. It is used to detect the presence of aldehyde or alpha hydroxy ketones. A positive test with Benedict’s solution is confirmed by the formation of a brick-red precipitate.
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Chapter 18 Solutions
GENERAL,ORGANIC,+BIO.CHEM.-MINDTAP
- Following are Fischer projections for a group of five-carbon sugars, all of which are aldopentoses. Identify the pairs that are enantiomers and the pairs that are epimers. (The sugars shown here are not all of the possible five-carbon sugars.) 1 СНО 2 СНО СНО Н-С—ОН Н-С—ОН Н—С—ОН Н-С—ОН НО —С—Н Н-С—ОН Н- С—ОН НО—С— Н НО—С—Н CH̟OH CH̟OH ČH̟OH в iоchemistry |61 STATE ATION Republic of the Philippines Romblon State University Romblan, Philippines 4 СНО 5 СНО 6 СНО НО—С—Н Н-С—ОН НО -С—Н Н—С—ОН НО -С—Н НО -С—Н H-C–OH Н-С—ОН НО—С—Н CH,OH ČH,OH CH,OHarrow_forwardFollowing are Fischer projections for a group of five-carbon sugars, all of which are aldopentoses. Identify the pairs that are enantiomers and the pairs that are epimers. (The sugars shown here are not all of the possible five-carbon )arrow_forwardWhat is the family-name ending for a sugar?arrow_forward
- When the amino acid sequences of insulin isolated from differentorganisms were determined, some differences were noted.For example, alanine was substituted for threonine, serine wassubstituted for glycine, and valine was substituted for isoleucineat corresponding positions in the protein. List the single-basechanges that could occur in triplets to produce these amino acidchanges.arrow_forwardAll naturally occurring polysaccharides have one terminal residue, which contains a free anomeric carbon. Why do these polysaccharides not give a positive chemical test for a reducing sugar?Please explainarrow_forwardWhat is the pyranose/furanose ring structure of this sugar?arrow_forward
- D- and L- designations are used to distinguish between the two possible enantiomers of the monosaccharide, galactose. From the Fischer projection, determine the designation of this monosaccharide.arrow_forwardSketch the titration curve for the amino acid alanine with pka1 = 2.34 and pka2 = 9.69.arrow_forwardWhat is the pI for histadine?arrow_forward
- Following are Fischer projections for a groupof five-carbon sugars, all of which are aldopentoses. Identify thepairs that are enantiomers and the pairs that are epimers. (Thesugars shown here are not all of the possible five-carbon sugars.)arrow_forwardnumber 5-21arrow_forwardFollowing are Fischer projections for a group of five-carbon sugars, all of which are aldopentoses. Identify the pairs that are enantiomers. CHO сно H-C- OH H-C-OH H-C- OH но-с — н н-с—он но- ČHOH ČH,OH сно CHO Н-с—он но—с— н H-C- OH H-C-OH но—с—н Н-с—он ČHOH ČH,OH сно сно н-с—он но—с —н но—с— н но -с — н H-C- OH но- C-H ČH,OH ČH,OHarrow_forward
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