
To show: The equation x2+y2−4x+10y+13=0 represents a circle and evaluate the center and radius of the circle.

Answer to Problem 103E
The equation x2+y2−4x+10y+13=0 represents a circle. The center of the circle is (2,−5) and radius is 4 units.
Explanation of Solution
Given information:
The equation x2+y2−4x+10y+13=0 .
Formula used:
In order to solve a
Step1: Divide the equation by coefficient of x2 if it is not equal to 1.
Step 2: Take the square of the half of the coefficient of x and add it to both sides of the equation.
Step 3: Factor the equation.
The standard form of the equation of the circle is (x−h)2+(y−k)2=r2 , where (h,k) denote the center of the circle and r denote the radius.
Calculation:
Consider the equation x2+y2−4x+10y+13=0 .
Recall that in order to solve a quadratic equation, completing the square method is used that transforms the equation in the form of square trinomial.
Step1: Divide the equation by coefficient of x2 if it is not equal to 1.
Step 2: Take the square of the half of the coefficient of x and add it to both sides of the equation.
Step 3: Factor the equation.
In the provided equation, add 4 to both the sides of the equation,
x2+y2−4x+10y+13+4=0+4
Next, add 25 to both the sides of the equation,
x2+y2−4x+10y+13+4+25=0+4+25
Group the terms,
x2+y2−4x+10y+13+4+25=0+4+25(x2−4x+4)+(y2+10y+25)=29−13
Factor out the trinomial, recall that (a+b)2=a2+2ab+b2 and (a−b)2=a2−2ab+b2 .
Apply it,
x2+y2−4x+10y+13+4+25=0+4+25(x2−4x+4)+(y2+10y+25)=29−13(x−2)2+(y+5)2=16
Recall that the standard form of the equation of the circle is (x−h)2+(y−k)2=r2 , where (h,k) denote the center of the circle and r denote the radius.
Convert the equation obtained above in standard form,
x2+y2−4x+10y+13+4+25=0+4+25(x2−4x+4)+(y2+10y+25)=29−13(x−2)2+(y+5)2=16(x−2)2+(y−(−5))2=42
Compare, (x−h)2+(y−k)2=r2 and (x−2)2+(y−(−5))2=42 .
Here, h=2,k=−5 and r=4 .
Therefore, center of circle is (2,−5) and radius is 4.
Thus, the equation x2+y2−4x+10y+13=0 represents a circle. The center of the circle is (2,−5) and radius is 4 units.
Chapter 1 Solutions
Precalculus - A Custom Text for UNLV
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