
Concept explainers
To calculate: The product of the rational expression,

Answer to Problem 30E
The product of rational expression is
Explanation of Solution
Given information:
The expression is given as:
Formula used:
For the rationalexpression:
Fractions property:
Product formula:
Factoring trinomials: The factor of rationalexpression which contain three terms is of the from
Choose the values of
Calculation:
Consider therationalexpression,
Use the fraction property,
Factor the terms in numerator by Factoring trinomials rule,
Factor the terms in denominator by Factoring trinomials rule and product property,
Cancel common factors from the numerators and denominator,
Thus, the product of rationalexpression is
Chapter 1 Solutions
Precalculus - A Custom Text for UNLV
- A Content X MindTap - Cengage Learning x Function Evaluations x + /ui/evo/index.html?elSBN=9780357038406&id=339416021&snapshotld=877369& GE MINDTAP , Limits, and the Derivative ⭑ វា a ANSWEI 16. Refer to the graph of the function f in the following figure. कर्ट AA C 54 -3-2 7 7 Ay 6. S 5. y=f(x) 4 3. 2. 1 -3- 34567 8 00 9 10 a. Find the value of ƒ (7). b. Find the values of x corresponding to the point(s) on the graph of ƒ located at a height of 5 units from the x-axis. c. Find the point on the x-axis at which the graph of ƒ crosses it. What is the value of f (x) at this point? d. Find the domain and range of f. MacBook Pro G Search or type URL + > % Λ & 5 6 7 29 ( 8 9 0arrow_forwardMorgan F. - C X A Courses MindTap - Cengage Learning Х Domain of Square Roots X + gage.com/static/nb/ui/evo/index.html?elSBN 9780357038406&id=339416021&snapshotld=877369& CENGAGE MINDTAP 2: Functions, Limits, and the Derivative 47. x if x < 0 f(x) = 2x+1 if x 0 Answerarrow_forwardA Content MindTap - Cengage Learning × Function Evaluations * + c/nb/ui/evo/index.html?elSBN 9780357038406&id=339416021&snapshotld=877369& GAGE MINDTAP ions, Limits, and the Derivative 15. Refer to the graph of the function f in the following figure. 6 y = f(x) 5 4+ 3- 2- 1 + 2 -1 3 4 5 6 a. Find the value of ƒ (0). Answer-> b. Find the value of x for which (i) f (x) = 3 and (ii) f (x) = 0. Answer ▾ c. Find the domain of f. Answer + d. Find the range of f. Answer+ MacBook Proarrow_forward
- Answer-> 12. Let g be the function defined by Find g(-2), g(0), g (2), and g (4). - +1 if x <2 g(x) = √√√x-2 if x 2arrow_forward13. Let f be the function defined by Find f (-1), f (0), ƒ (1) and ƒ (2). Answer f(x) = .2 J-x² +3 if x <1 2x²+1 2x²+1 if x ≥ 1arrow_forwardΛ Content Mind Tap - Cengage Learning × Function Evaluations x + c/nb/ui/evo/index.html?elSBN 9780357038406&id=339416021&snapshotld=877369& GAGE MINDTAP ons, Limits, and the Derivative 14. Let f be the function defined by Find f (0), f (1), and f (2). 2+1 x if x 1 if x 1 f(x) = 1 1-xarrow_forward
- A Content c/nb/ui/evo/index.html?elSBN 9780357038406&id=339416021&snapshotld=877369& GAGE MINDTAP ons, Limits, and the Derivative 11. Let f be the function defined by Find f (-2), f (0), and f (1). Answer f(x) = [ x² + 1 if x ≤ 0 if x > 0arrow_forwardGiven that 4−4i is a zero, factor the following polynomial function completely. Use the Conjugate Roots Theorem, if applicable. f(x)=x4−5x3−2x2+176x−320arrow_forwardeliminate the parameter to find the cartesian equation of the curve and sketch the graph. On the graph show the direction it takes and the initial and terminal point. Please draw by hand and show how you got to each steparrow_forward
- Calculus: Early TranscendentalsCalculusISBN:9781285741550Author:James StewartPublisher:Cengage LearningThomas' Calculus (14th Edition)CalculusISBN:9780134438986Author:Joel R. Hass, Christopher E. Heil, Maurice D. WeirPublisher:PEARSONCalculus: Early Transcendentals (3rd Edition)CalculusISBN:9780134763644Author:William L. Briggs, Lyle Cochran, Bernard Gillett, Eric SchulzPublisher:PEARSON
- Calculus: Early TranscendentalsCalculusISBN:9781319050740Author:Jon Rogawski, Colin Adams, Robert FranzosaPublisher:W. H. FreemanCalculus: Early Transcendental FunctionsCalculusISBN:9781337552516Author:Ron Larson, Bruce H. EdwardsPublisher:Cengage Learning





