Campbell Biology: Custom Edition
18th Edition
ISBN: 9781323717271
Author: Urry, Cain, Wasserman, Minorsky, Reece
Publisher: PEARSON C
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Textbook Question
Chapter 17.1, Problem 2CC
What polypeptide product would you expect from a poly-G mRNA that is 30
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What polypeptide sequences would you expect to result from a synthetic mRNA with the repeating sequence 5’-UUUGGGUUUGGGUUUGGG-3'?
Using the genetic code table provided below, write out the sequence of three different possible
mRNA sequences that could encode the following sequence of amino acids:
Met-Phe-Cys-Trp-Glu
C
A
G
U
C
UUU Phe UCU Ser
UUC Phe UCC Ser
UCA Ser
UUA Leu
UUG Leu UCG Ser
CUU Leu CCU Pro
CUC Leu
CUA Leu
CUG Leu CCG
A
CAU His CGU Arg
CCC Pro CAC His CGC Arg
UAU Tyr UGU Cys U
UAC Tyr UGC Cys C
Stop UGA Stop
Stop UGG
Trp
UAA
A
UAG
G
CCA Pro CAA Gln
Pro CAG
AUU lle
AUC lle
AUA lle
AUG Met ACG
G
등등
Gln
CGA Arg
CGG Arg
ACU Thr AAU Asn AGU Ser
ACC
AAC Asn
AGC Ser
Thr
ACA Thr
Thr
AAA Lys AGA Arg
AAG
Lys
AGG Arg
GUU Val GCU
Ala
GAU Asp
GGU Gly
GGC Gly
GUC Val GCC
Ala
GAC
Asp
GUA Val
GCA
Ala
GAA
Glu GGA Gly
GUG Val
GCG Ala GAG
Glu GGG Gly
U
C
A
G
U
C
A
G
SUAU
The mRNA formed from the repeating tetranucleotide UUACincorporates only three amino acids, but the use of UAUC incorporates four amino acids. Why?
Chapter 17 Solutions
Campbell Biology: Custom Edition
Ch. 17.1 - Prob. 1CCCh. 17.1 - What polypeptide product would you expect from a...Ch. 17.1 - Prob. 3CCCh. 17.2 - MAKE CONNECTIONS In a research artide about...Ch. 17.2 - What enables RNA polymerase to start transcribing...Ch. 17.2 - WHAT IF? Suppose X-rays caused a sequence change...Ch. 17.3 - There are about 20,000 human protein-coding genes....Ch. 17.3 - How is RNA splicing similar to how you would watch...Ch. 17.3 - Prob. 3CCCh. 17.4 - What two processes ensure that the correct amino...
Ch. 17.4 - Prob. 2CCCh. 17.4 - Prob. 3CCCh. 17.4 - WH AT IF? In eukaryotic cells, mRNAs have been...Ch. 17.5 - What happens when one nucleotide pair is lost from...Ch. 17.5 - MAKE CONNECTIONS Individuals heterozygous for the...Ch. 17.5 - WHAT IF? DRAW IT The template strand of a gene...Ch. 17 - Describe the process of gene expression, by which...Ch. 17 - What are the similarities and differences in the...Ch. 17 - What function do the 5' cap and the poly-A tail...Ch. 17 - Prob. 17.4CRCh. 17 - What will be the results of chemically modifying...Ch. 17 - In eukaryotic cells, transcription cannot begin...Ch. 17 - Which of the following is not true of a codon? (A)...Ch. 17 - The anticodon of a particular tRNA molecule is (A)...Ch. 17 - Which of the following is not true of RNA...Ch. 17 - Which component is not directly involved in...Ch. 17 - Using Figure 17.6, identify a 5' 3' sequence of...Ch. 17 - Prob. 7TYUCh. 17 - Would the coupling of the processes shown in...Ch. 17 - Prob. 9TYUCh. 17 - Prob. 10TYUCh. 17 - scientific inquiry Knowing that the genetic code...Ch. 17 - Prob. 12TYUCh. 17 - Prob. 13TYU
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Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, biology and related others by exploring similar questions and additional content below.Similar questions
- Consider the following DNA sequence, which codes for a short polypeptide: 5'-ATGGGCTTAGCGTAGGTTAGT-3' Determine the mRNA transcript of this sequence. You have to write these sequences from the 5' end to the 3' end and indicate those ends as shown in the original sequence in order to get the full mark. How many amino acids will make up this polypeptide? Determine the first four anticodons that will be used in order to translate this sequence.arrow_forwardSequence 1 : TACGCTACGGTAATC Sequence 2: TACGCTACTATCGTAarrow_forwardUsing the genetic code table provided below, identify the open reading frame in this mRNA sequence, and write out the encoded 9 amino acid long peptide sequence: 5'- CGACAUGCCUAAAAUCAUGCCAUGGAGGGGGUAACCUUUU C A G U UUU Phe UCU Ser UUC Phe UCC Ser UAC UCA Ser UAA UCG Ser UAG UUA Leu Leu G C CUU Leu CUC Leu CCC CUA Leu CUG Leu AUU lle AUC lle AUA lle AUG Met ACG ACU Thr ACC Thr ACA Thr Thr A UAU Tyr UGU Cys Tyr UGC Cys CCU Pro CAU His CGU Arg Pro CAC His Pro CAA Gln CGC Arg CGA Arg CCA CCG Pro CAG Gln CGG Arg GUU Val GCU Ala GAU GUC Val GCC Ala GAC GUA Val GCA Ala GAA GUG Val GCG Ala GAG Stop UGA Stop UGG AAU Asn AAC AAA AAG AGU Asn AGC G Lys Lys Asp Asp Glu Glu Stop A Trp Ser Ser AGA Arg AGG Arg GGU Gly GGC Gly UCAG GGA Gly GGG Gly с U C A G U C A G U C A Garrow_forward
- Assume the following portion of an mRNA. Find a start signal, and write the amino acid sequence that is coded for. 5'-GCCAUGUUUCCGAGUUAUCCCAAAGAUAAAAAAGAG 3'arrow_forwardGiven the following mRNA transcript: 5’-UUUGGCAUGGGUAUCGUAGAGAUGGAAUUCAUAGUGGAGUAA-3’ What is the one-letter abbreviation of the protein product of the mRNA transcript?arrow_forwardIn eukaryotic mRNA there are 90 nucleotide involved in translation process. What is the number of amino acid in the protein formed by this mRNA molecule?arrow_forward
- After the intron (which is in a lariat configuration) is released during pre-mRNA splicing, a brief moment occurs before the two exons are connected to each other. Which snRNP(s) hold(s) the exons in place so they can be covalently connected to each other?arrow_forwardWhat is the peptide encoded by this mRNA sequence 5’-UCU-GCA- AAU-UAA -GUU-3’?arrow_forwardThe amino acids, in one-letter symbols and no spaces, coded by the following mRNA sequence is 5’ AAUGGAACGUCGGUACUGCCAUCGCAUUAGUACCAUGGCAAGCUGAAGC 3’arrow_forward
- For each of the following items, fill in either the DNA strand, the MRNA codons, the tRNA anticodons, or the amino acid sequence that have been left blank. If several sequences might work, choose only one. Furthermore, circle the start and the stop codons of each mRNA sequence. 1. DNA (3'-5') ACG TAC GGC CGG TTA AAG CAT ACT TTC TTG MRNA TRNA Amino Acid 2. DNA (3'-5') MRNA AUG ACU AGC UGG GGG UAU UAC UUU UAG AAA TRNA Amino Acid 3. DNA (3'-5') MRNA TRNA GCU CCU UAC CAC ССС CGU AUG GCU GGG AUC Activate Go to Sett Amino Acidarrow_forwardThe base sequence of the gene coding for a short polypeptide is TAC CTA CGC TAG GCG ATT GAC T. What would be the base sequence of the mRNA transcribed from this gene? The base sequence of the gene coding for a short polypeptide is TAC CTA CGC TAG GCG ATT GAC T. From your answer to the last question, answer this Using the genetic code, give the amino acid sequence of the polypeptide translated from this mRNA. Use the three-letter abbrebviation of the amino acid and start with the start codon and stop in the stop codon.arrow_forwardif a protein that contain the two codon sequences showed a molar mass of 97,313 g /mol and the UV data showed that it contains 0.67 % Tyrosine amino acid by weight. How many Tyrosine amino acids this protein contain? If this protein that was formed contains a total of 865 amino acids long, how many nucleic acids are there in the mRNA including the initiator and the terminator codons?arrow_forward
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