Concepts of Genetics (12th Edition)
12th Edition
ISBN: 9780134604718
Author: William S. Klug, Michael R. Cummings, Charlotte A. Spencer, Michael A. Palladino, Darrell Killian
Publisher: PEARSON
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Chapter 17, Problem 6PDQ
A number of experiments have demonstrated that areas of the genome that are transcriptionally inactive are also resistant to DNase I digestion. However, transcriptionally active areas are DNase I sensitive. Describe how DNase I resistance or sensitivity might indicate transcriptional activity.
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Chapter 17 Solutions
Concepts of Genetics (12th Edition)
Ch. 17 - Cancer cells often have abnormal patterns of...Ch. 17 - The hormone estrogen converts the estrogen...Ch. 17 - Each year in the United States, there are over...Ch. 17 - Prob. 2CSCh. 17 - Each year in the United States, there are over...Ch. 17 - HOW DO WE KNOW? In this chapter, we focused on how...Ch. 17 - CONCEPT QUESTION Review the Chapter Concepts list...Ch. 17 - What features of eukaryotes provide additional...Ch. 17 - Provide a definition of chromatin remodeling, and...Ch. 17 - Describe the organization of the interphase...
Ch. 17 - A number of experiments have demonstrated that...Ch. 17 - Provide a brief description of two different types...Ch. 17 - Present an overview of the manner in which...Ch. 17 - Prob. 9PDQCh. 17 - Explain how the addition of acetyl groups to...Ch. 17 - Distinguish between the cis-acting regulatory...Ch. 17 - Prob. 12PDQCh. 17 - Describe the manner in which activators and...Ch. 17 - Compare the control of gene regulation in...Ch. 17 - Many promoter regions contain CAAT boxes...Ch. 17 - Prob. 16PDQCh. 17 - Prob. 17PDQCh. 17 - Many transcriptional activators are proteins with...Ch. 17 - Prob. 19PDQCh. 17 - DNA supercoiling, which occurs when coiling...Ch. 17 - Prob. 21ESPCh. 17 - Prob. 22ESPCh. 17 - Because the degree of DNA methylation appears to...Ch. 17 - A particular type of anemia in humans, called...Ch. 17 - Regulation of the lac operon in E. coli (see...Ch. 17 - DNA methylation is commonly associated with a...Ch. 17 - During an examination of the genomic sequences...Ch. 17 - Prob. 28ESPCh. 17 - Although a single activator may bind many...Ch. 17 - Hereditary spherocytosis (HS) is a disorder...Ch. 17 - Transcription factors play key roles in the...
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Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, biology and related others by exploring similar questions and additional content below.Similar questions
- You would like to add a nuclear localization sequence (NLS) of Lys-Lys-Lys-Arg-Lys to a protein that is usually found in the cytoplasm of a yeast cell. To accomplish this, you introduce the nucleotide sequence encoding the NLS into the gene that encodes the cytoplasmic protein of interest. a. What is the size of the nucleotide insert that will encode the NLS? Briefly explain. 5' 3' b. Below is a diagram of the gene encoding the cytoplasmic protein of interest in the yeast genome. If your goal is to put the NLS at the carboxyl (C) terminus of the protein, at which location (A-E) should the NLS be inserted? Briefly explain. A TATAA ATATT promoter +1 B ATG TAC D TAA ATT stop codon E 3' 5'arrow_forwardThe IMD2 promoter contains three upstream transcription start sites (TSS) that are utilized under high GTP conditions and a single downstream TSS (-106) that is normally only utilized under low GTP conditions. In a wild type cell, expression of IMD2 mRNA only occurs if transcription initiates from the -106 TSS. In 300 words or less, describe: 1.) The normal function of Ssl2, and 2.) why a mutation in Ssl2, that increases its catalytic rate, would allow expression of the IMD2 ORF under high GTP conditions. (Conditions under which the IMD2 ORF is NOT expressed in the wild type.)arrow_forwardConsider a gene being transcribed at a constant rate k1 and being degraded with first order kinetics with a rate constant of k2. a. Write the chemical reaction for transcriptionb. Derive the instantaneous concentration of the mRNA within the cell. Explicitly list all assumptions.arrow_forward
- Consider the mechanism of the enzyme RNase: What would happen to the Km (i.e., would it increase, decrease, or stay the same) if the his12 was mutated to a lysine? Explain. What would happen to the Kcat (i.e., would it increase, decrease, or stay the same) if the his12 was mutated to a valine? Explain.arrow_forwardWhat is meant by the term transcription factor modulation? List three general ways this can occur.arrow_forwardSince RNA polymerase has an error rate of 1 / 10^4 nucleotides, and the DNA polymerase has an error rate of 1 / 10^7 nucleotides, can cells tolerate errors made in transcription in comparison to errors made during DNA replication?arrow_forward
- Consider the Rho-dependent terminator sequence 5’CCCAGCCCGCCUAAUGAGCGGCCUUUUUUUU-3’. What affect would a point mutation at any one of the bolded and underlined nucleotides disrupt termination of transcription? Group of answer choices Mutation in one of these nucleotides would disrupt base pairing, preventing the formation of the hairpin and disrupting termination. Mutation in one of these nucleotides would have no affect on base pairing, so the termination hairpin is formed and termination proceeds. Mutation in one of these nucleotides would not disrupt base pairing, but would prevent the formation of the hairpin and disrupt termination. Mutation in one of these nucleotides would disrupt base pairing, but not affect the formation of the hairpin and termination proceeds.arrow_forwardCTP synthetase catalyzes the glutamine-dependent conversion of UTP to CTP. The enzyme is allosterically inhibited by the product, CTP. Mamma- lian cells defective in this allosteric inhibition are found to have a complex phenotype: They require thymidine in the growth medium, they have unbal- anced nucleotide pools, and they have an elevated spontaneous mutation rate. Explain the likely basis for these observations.arrow_forwardConsider a mutant form of the lac repressor protein whose ΔGo for binding DNA differs from that of the wild-type protein by 2 kcal/mol, the approximate free energy equivalent of a single hydrogen bond. What is the difference (i.e., the ratio) of the Kd values (for DNA binding) of the wild-type versus the mutant lac repressor protein?arrow_forward
- Explain the Mutations at the Huntington disease locus are caused by an expansion of a trinucleotide repeat SSR in a coding region.arrow_forwardMicrosomal enzyme induction is often brought about by drugs stimulating gene transcription, which increases production of the enzyme. But enzyme activity can also be increased through a process that interferes with the degradation of an enzyme. How could a drug induce a microsomal enzyme by inhibiting its degradation as opposed to stimulating drug transcription?arrow_forwardThe presence of a DNA template (e.g. a product from PCR), general transcription factors, and RNA polymerase II allows for the initiation of transcription in vitro. Explain why the initiation of transcription is not possible with only general transcription factors and RNA polymerase II using the genomic DNA as a template.arrow_forward
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