Concepts of Genetics (12th Edition)
12th Edition
ISBN: 9780134604718
Author: William S. Klug, Michael R. Cummings, Charlotte A. Spencer, Michael A. Palladino, Darrell Killian
Publisher: PEARSON
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Chapter 17, Problem 20PDQ
DNA supercoiling, which occurs when coiling tension is generated ahead of the replication fork, is relieved by DNA gyrase. Supercoiling may also be involved in transcription regulation. Researchers discovered that enhancers operating over a long distance (2500 bp) are dependent on DNA supercoiling, while enhancers operating over shorter distances (110 bp) are not so dependent [Liu et al. (2001). Proc. Natl. Acad. Sci. USA 98:14,883–14,888]. Using a diagram, suggest a way in which supercoiling may positively influence enhancer activity over long distances.
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During the process of transcription, the polymerase must handle several distinct polynucleotide chains: the double-stranded DNA ahead of the polymerase, the single-stranded template DNA, the nontemplate DNA strand, and the freshly-synthesized mRNA. How does the polymerase keep each of these strands--as well as the incoming ribonucleotides needed for the polymerase reaction--separate?
Consider the Rho-dependent terminator sequence
5’CCCAGCCCGCCUAAUGAGCGGCCUUUUUUUU-3’. What affect would a point mutation at any one of the bolded and underlined nucleotides disrupt termination of transcription?
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Mutation in one of these nucleotides would disrupt base pairing, preventing the formation of the hairpin and disrupting termination.
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Mutation in one of these nucleotides would disrupt base pairing, but not affect the formation of the hairpin and termination proceeds.
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Chapter 17 Solutions
Concepts of Genetics (12th Edition)
Ch. 17 - Cancer cells often have abnormal patterns of...Ch. 17 - The hormone estrogen converts the estrogen...Ch. 17 - Each year in the United States, there are over...Ch. 17 - Prob. 2CSCh. 17 - Each year in the United States, there are over...Ch. 17 - HOW DO WE KNOW? In this chapter, we focused on how...Ch. 17 - CONCEPT QUESTION Review the Chapter Concepts list...Ch. 17 - What features of eukaryotes provide additional...Ch. 17 - Provide a definition of chromatin remodeling, and...Ch. 17 - Describe the organization of the interphase...
Ch. 17 - A number of experiments have demonstrated that...Ch. 17 - Provide a brief description of two different types...Ch. 17 - Present an overview of the manner in which...Ch. 17 - Prob. 9PDQCh. 17 - Explain how the addition of acetyl groups to...Ch. 17 - Distinguish between the cis-acting regulatory...Ch. 17 - Prob. 12PDQCh. 17 - Describe the manner in which activators and...Ch. 17 - Compare the control of gene regulation in...Ch. 17 - Many promoter regions contain CAAT boxes...Ch. 17 - Prob. 16PDQCh. 17 - Prob. 17PDQCh. 17 - Many transcriptional activators are proteins with...Ch. 17 - Prob. 19PDQCh. 17 - DNA supercoiling, which occurs when coiling...Ch. 17 - Prob. 21ESPCh. 17 - Prob. 22ESPCh. 17 - Because the degree of DNA methylation appears to...Ch. 17 - A particular type of anemia in humans, called...Ch. 17 - Regulation of the lac operon in E. coli (see...Ch. 17 - DNA methylation is commonly associated with a...Ch. 17 - During an examination of the genomic sequences...Ch. 17 - Prob. 28ESPCh. 17 - Although a single activator may bind many...Ch. 17 - Hereditary spherocytosis (HS) is a disorder...Ch. 17 - Transcription factors play key roles in the...
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- When Laybourne and Kadonaga studied the effects of histone proteins on eukaryotic transcription using an in vitro transcription assay explain why: a) they used two different DNA templates that contained different promoter structures. b) when they included both activator protein and histones, they always added the histone proteins before adding the activator to the transcription assay mixture. (Ctri) -arrow_forwardConsider the Rho-dependent terminator sequence 5’CCCAGCCCGCCUAAUGAGCGGCCUUUUUUUU-3’. What affect would a point mutation at any one of the bolded and underlined nucleotides disrupt termination of transcription? Group of answer choices 1.Mutation in one of these nucleotides would disrupt base pairing, but not affect the formation of the hairpin and termination proceeds. 2.Mutation in one of these nucleotides would have no affect on base pairing, so the termination hairpin is formed and termination proceeds. 3.Mutation in one of these nucleotides would not disrupt base pairing, but would prevent the formation of the hairpin and disrupt termination. 4.Mutation in one of these nucleotides would disrupt base pairing, preventing the formation of the hairpin and disrupting termination.arrow_forwardHow do you think that transcription randomizes positions of nucleosomes and repression restores the ordering after transcription? How might you test to see if there was an exchange of histone subunits during transcription or if the nucleosome is truly transferred as a single unit? Would you expect the DNA band representing the distance from the restriction enzyme site to the hypersensitive site to be a single band or a smear? Defend your answer.arrow_forward
- DNA topoisomerases play important roles in DNA replication and in supercoiling . These enzymes are also the targets for certain anticancer drugs (see the introduction to this chapter). Eric Nelson and his colleagues studied m-AMSA, one of the anticancer compounds that acts on topoisomerase (E. M. Nelson, K. M. Tewey, and L. F. Liu. 1984. Proceedings of the National Academy of Sciences of the United States of America 81:1361–1365). They found that m-AMSA stabilizes an intermediate produced in the course of topoisomerase action. The intermediate consists of topoisomerase bound to the broken ends of the DNA. Breaks in DNA that are produced by anticancer compounds such as m-AMSA inhibit the replication of the cellular DNA and thus stop cancer cells from proliferating. Explain how m-AMSA and other anticancer agents that target topoisomerase enzymes taking part in replication might lead to DNA breaks and chromosome rearrangements.arrow_forwardDNA polymerases are capable of editing and error correction, meaning it is able to edit and correct single base error so that the gene is not affected. However, RNA polymerase has a limited capacity for error correction. Given that a single base error in either replication or transcription can lead to error in protein synthesis, suggest a brief explanation for this difference in the capability of error correction between DNA polymerase and RNA polymerase.arrow_forwardWhich of the following set(s) of primers a–d couldyou use to amplify the following target DNA sequence, which is part of the last protein-coding exonof the CFTR gene?5′ GGCTAAGATCTGAATTTTCCGAG ... TTGGGCAATAATGTAGCGCCTT 3′3′ CCGATTCTAGACTTAAAAGGCTC ... AACCCGTTATTACATCGCGGAA 5′a. 5′ GGAAAATTCAGATCTTAG 3′;5′ TGGGCAATAATGTAGCGC 3′b. 5′ GCTAAGATCTGAATTTTC 3′;3′ ACCCGTTATTACATCGCG 5′c. 3′ GATTCTAGACTTAAAGGC 5′;3′ ACCCGTTATTACATCGCG 5′d. 5′ GCTAAGATCTGAATTTTC 3′;5′ TGGGCAATAATGTAGCGC 3′arrow_forward
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