Universe: Stars And Galaxies
6th Edition
ISBN: 9781319115098
Author: Roger Freedman, Robert Geller, William J. Kaufmann
Publisher: W. H. Freeman
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Chapter 17, Problem 21Q
To determine
The ratio of the luminosities for the given conditions.
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You measure a star to have a parallax angle of 0.12 arc-seconds. What fraction of a degree is this?
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Chapter 17 Solutions
Universe: Stars And Galaxies
Ch. 17 - Prob. 1QCh. 17 - Prob. 2QCh. 17 - Prob. 3QCh. 17 - Prob. 4QCh. 17 - Prob. 5QCh. 17 - Prob. 6QCh. 17 - Prob. 7QCh. 17 - Prob. 8QCh. 17 - Prob. 9QCh. 17 - Prob. 10Q
Ch. 17 - Prob. 11QCh. 17 - Prob. 12QCh. 17 - Prob. 13QCh. 17 - Prob. 14QCh. 17 - Prob. 15QCh. 17 - Prob. 16QCh. 17 - Prob. 17QCh. 17 - Prob. 18QCh. 17 - Prob. 19QCh. 17 - Prob. 20QCh. 17 - Prob. 21QCh. 17 - Prob. 22QCh. 17 - Prob. 23QCh. 17 - Prob. 24QCh. 17 - Prob. 25QCh. 17 - Prob. 26QCh. 17 - Prob. 27QCh. 17 - Prob. 28QCh. 17 - Prob. 29QCh. 17 - Prob. 30QCh. 17 - Prob. 31QCh. 17 - Prob. 32QCh. 17 - Prob. 33QCh. 17 - Prob. 34QCh. 17 - Prob. 35QCh. 17 - Prob. 36QCh. 17 - Prob. 37QCh. 17 - Prob. 38QCh. 17 - Prob. 39QCh. 17 - Prob. 40QCh. 17 - Prob. 41QCh. 17 - Prob. 42QCh. 17 - Prob. 43QCh. 17 - Prob. 44QCh. 17 - Prob. 45QCh. 17 - Prob. 46QCh. 17 - Prob. 47QCh. 17 - Prob. 48QCh. 17 - Prob. 49QCh. 17 - Prob. 50QCh. 17 - Prob. 51QCh. 17 - Prob. 52QCh. 17 - Prob. 53QCh. 17 - Prob. 54QCh. 17 - Prob. 55QCh. 17 - Prob. 56QCh. 17 - Prob. 57QCh. 17 - Prob. 58QCh. 17 - Prob. 59QCh. 17 - Prob. 60QCh. 17 - Prob. 61QCh. 17 - Prob. 62QCh. 17 - Prob. 63QCh. 17 - Prob. 64QCh. 17 - Prob. 65QCh. 17 - Prob. 66QCh. 17 - Prob. 67QCh. 17 - Prob. 68QCh. 17 - Prob. 69QCh. 17 - Prob. 70QCh. 17 - Prob. 71QCh. 17 - Prob. 72QCh. 17 - Prob. 73QCh. 17 - Prob. 74QCh. 17 - Prob. 75QCh. 17 - Prob. 76QCh. 17 - Prob. 77QCh. 17 - Prob. 78QCh. 17 - Prob. 79QCh. 17 - Prob. 80Q
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- Distance from Apparent Brightness (rank; brightest, 8 = dimmest) Name of Star Earth (light years) | 1 = Sun Sirius 8.6 Canopus Arcturus 309 3. 36.7 4 Rigel Vega Alpha Centauri Bernard's Star 773 5 25.3 4.3 7 5.9 8 13 What sentence explains why a star can be much farther from Earth than the Sun, but still be bright? nida nenv A. Distance from Earth and apparent brightness are related. B. Bright stars that are farther away are larger than the Sun. C. The higher it appears in the sky, the brighter the star. D. The apparent brightness scale goes up as stars get dimmer. del sdTarrow_forwardYou measure a star to have a parallax angle of 0.12 arc-seconds What is the distance to this star in parsecs? 8.33 Hint: d = 1/p What is the parallax angle of a different star that is twice as far away as the star from the previous problems? [answer in arc-seconds without including the unit]arrow_forwardI need the answer as soon as possiblearrow_forward
- Two stars-A and B, of luminosities 0.5 and 4.5 times the observed to have the luminosity of the Sun, respectively-are same apparent brightness. Which star is more distant, and how much farther away is it than the other?arrow_forwardA brand new telescope has been named after you. It is therefore only fitting that you get to make the very first set of observations. During your first night observing, you first measure the apparent brightness and spectrum of a group of stars that appear close to each other within the telescopes field of view. From a separate set of observations 6 months later, you are able to measure each star’s parallax. Next you plot the luminosity and temperature of each star in a Hertzsprung-Russell Diagram What features below help you conclude that the group of stars is a star cluster? Explain Approximately how old do you think this star cluster is? Explain How do you expect the spectrum of the most luminous and least luminous main sequence stars in the cluster to differ? Explain why these differences occur in terms of the star’s properties and any measured absorption lines. A year after your discovery, another new star cluster has been found by the same telescope, but its distance is too far…arrow_forwardL = ( 0.0813 ) x (Rs) ^2 x 10-0.4m x Ls where L = luminosity of the desired star Rs = distance of the stars in light years m = apparent magnitude of star Ls = Luminosity of Sun = 1.00 The calculated value of Polaris' luminosity is: a. 2382 times Ls b. 6040 times Ls c. 5566 times Ls d. 2612 times Lsarrow_forward
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