ORGANIC CHEM +SG +SAPLING >IP<
ORGANIC CHEM +SG +SAPLING >IP<
6th Edition
ISBN: 9781319171179
Author: LOUDON
Publisher: MAC HIGHER
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Chapter 17, Problem 17.44AP
Interpretation Introduction

(a)

Interpretation:

The reason as to why 1,3cyclopentadiene is stronger carbon acid than 1,4pentadiene is to be stated.

Concept introduction:

Diene is a hydrocarbon that contains two double bonds in a compound. Conjugated diene consists of two double bonds that are separated by a single bond, whereas, isolated diene also consists of two double bonds but they are separated by two more carbon atoms.

Interpretation Introduction

(b)

Interpretation:

The reason as to why 3bromo1,4pentadiene undergoes solvolysis easily in protic solvents but 5bromo1,3cyclopentadiene not is to be stated.

Concept introduction:

Diene is a hydrocarbon that contains two double bonds in a compound. Conjugated diene consists of two double bonds that are separated by a single bond, whereas isolated diene also consists of two double bonds but they are separated by two more carbon atoms.

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Part II. two unbranched ketone have molecular formulla (C8H100). El-ms showed that both of them have a molecular ion peak at m/2 =128. However ketone (A) has a fragment peak at m/2 = 99 and 72 while ketone (B) snowed a fragment peak at m/2 = 113 and 58. 9) Propose the most plausible structures for both ketones b) Explain how you arrived at your conclusion by drawing the Structures of the distinguishing fragments for each ketone, including their fragmentation mechanisms.
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