(a)
Interpretation:
The reaction in which
Concept introduction:
Grignard reagents are

Answer to Problem 17.45AP
The complete reaction between
Explanation of Solution
The given reaction is shown below.
Figure 1
The complete reaction is shown below.
Figure 2
The hydrolysis of Grignard reagent is shown in Figure 2 in the presence of a solvent
Therefore, the product formed is shown in Figure 2.
The complete reaction between
(b)
Interpretation:
The reaction between
Concept introduction:
Grignard reagents are organometallic compounds which are prepared using alkyl halides in the presence of magnesium metal in dry ether. These reagents act as strong nucleophiles and bases.

Answer to Problem 17.45AP
The complete reaction between
Explanation of Solution
The given reaction is shown below.
Figure 3
The complete reaction is shown below.
Figure 4
The Grignard reagent on treatment with epoxides in the presence of
Therefore, the product formed is shown in Figure 4.
The complete reaction between
(c)
Interpretation:
The reaction between
Concept introduction:
Nucleophiles are electron-rich species. The nucleophilic substitution reactions are the reactions in which nucleophile attacks the electrophilic center and eliminates another group.

Answer to Problem 17.45AP
The complete reaction between
Explanation of Solution
The given reaction is shown below.
Figure 5
The complete reaction is shown below.
Figure 6
The above figure shows the reaction between ethyl sulfide ion and
The complete reaction between
(d)
Interpretation:
The reaction between
Concept introduction:
Nucleophiles are electron-rich species. The nucleophilic substitution reactions are the reactions in which nucleophile attacks the electrophilic center and eliminates another group.

Answer to Problem 17.45AP
The complete reaction between
Explanation of Solution
The given reaction is shown below.
Figure 7
The complete reaction is shown below.
Figure 8
Figure 8 shows the reaction between
The complete reaction between
(e)
Interpretation:
The reaction of a given compound with NBS is to be completed.
Concept introduction:
Cyclic alkenes on reaction with N-Bromosuccinimide (NBS) forms allyl bromide, that is, bromine is substituted at the allylic position. NBS is a rich source of free radical of

Answer to Problem 17.45AP
The complete reaction of a given compound with NBS is shown below.
Explanation of Solution
The given reaction is shown below.
Figure 9
The complete reaction is shown below.
Figure 10
The NBS is used for allylic bromination that is it substitutes
Therefore, the products formed are shown in Figure 10.
The complete reaction of given compound with NBS is shown in Figure 10.
(f)
Interpretation:
The reaction between
Concept introduction:
Cyclic alkenes on reaction with N-Bromosuccinimide (NBS) forms allyl bromide, that is, bromine is substituted at the allylic position. NBS is a rich source of free radical of

Answer to Problem 17.45AP
The complete reaction between
Explanation of Solution
The given reaction is shown below.
Figure 11
The complete reaction is shown below.
Figure 12
The molecular formula of the product is
Due to the addition of NBS, benzylic bromination of
Therefore, the product formed is shown in Figure 12.
The complete reaction between
(g)
Interpretation:
The complete reaction in which
Concept introduction:
The elimination reaction of alkyl halide,

Answer to Problem 17.45AP
The complete reaction in which
Explanation of Solution
The given reaction is shown below.
Figure 13
The complete reaction is shown below.
Figure 14
The addition of
Therefore, the product formed is shown in Figure 14.
The complete reaction in which
(h)
Interpretation:
The reaction between
Concept introduction:
When an alkene reacts with water in the acidic medium the reaction follows Markovnikov rule which states that the negative part of the reagent attacks the carbon with the least number of hydrogen atoms attached to it.

Answer to Problem 17.45AP
The complete reaction between
Explanation of Solution
The given reaction is shown below.
Figure 15
The complete reaction is shown below.
Figure 16
The compound,
Therefore, the products formed are shown in Figure 16.
The complete reaction between
(i)
Interpretation:
The reaction between
Concept introduction:
The substance which gets easily reduced is termed as a strong oxidizing agent. It is also defined as the substances which oxidize other substances by accepting their electrons. Examples of strong oxidizing agents are potassium permanganate, hydrogen peroxide and many more.

Answer to Problem 17.45AP
The complete reaction between
Explanation of Solution
The given reaction is shown below.
Figure 17
The complete reaction is shown below.
Figure 18
The compound,
Therefore, the product formed is shown in Figure 18.
The complete reaction between
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Chapter 17 Solutions
ORGANIC CHEM +SG +SAPLING >IP<
- PROBLEMS Q1) Label the following salts as either acidic, basic, or neutral a) Fe(NOx) c) AlBr b) NH.CH COO d) HCOON (1/2 mark each) e) Fes f) NaBr Q2) What is the pH of a 0.0750 M solution of sulphuric acid?arrow_forward8. Draw all the resonance forms for each of the fling molecules or ions, and indicate the major contributor in each case, or if they are equivalent (45) (2) -PH2 سمة مدarrow_forwardA J то گای ه +0 Also calculate the amount of starting materials chlorobenzaldehyde and p-chloroacetophenone required to prepare 400 mg of the given chalcone product 1, 3-bis(4-chlorophenyl)prop-2-en-1-one molar mass ok 1,3-bis(4-Chlorophenyl) prop-2-en-1-one = 277.1591m01 number of moles= 0.400/277.15 = 0.00144 moles 2 x 0.00 144=0.00288 moves arams of acetophenone = 0.00144 X 120.16 = 0.1739 0.1739x2=0.3469 grams of benzaldehyde = 0.00144X106.12=0.1539 0.1539x2 = 0.3069 Starting materials: 0.3469 Ox acetophenone, 0.3069 of benzaldehyde 3arrow_forward
- 1. Answer the questions about the following reaction: (a) Draw in the arrows that can be used make this reaction occur and draw in the product of substitution in this reaction. Be sure to include any relevant stereochemistry in the product structure. + SK F Br + (b) In which solvent would this reaction proceed the fastest (Circle one) Methanol Acetone (c) Imagine that you are working for a chemical company and it was your job to perform a similar reaction to the one above, with the exception of the S atom in this reaction being replaced by an O atom. During the reaction, you observe the formation of three separate molecules instead of the single molecule obtained above. What is the likeliest other products that are formed? Draw them in the box provided.arrow_forward3. For the reactions below, draw the arrows corresponding to the transformations and draw in the boxes the reactants or products as indicated. Note: Part A should have arrows drawn going from the reactants to the middle structure and the arrows on the middle structure that would yield the final structure. For part B, you will need to draw in the reactant before being able to draw the arrows corresponding to product formation. A. B. Rearrangement ΘΗarrow_forward2. Draw the arrows required to make the following reactions occur. Please ensure your arrows point from exactly where you want to exactly where you want. If it is unclear from where arrows start or where they end, only partial credit will be given. Note: You may need to draw in lone pairs before drawing the arrows. A. B. H-Br 人 C Θ CI H Cl Θ + Br Oarrow_forward
- 4. For the reactions below, draw the expected product. Be sure to indicate relevant stereochemistry or formal charges in the product structure. a) CI, H e b) H lux ligh Br 'Harrow_forwardArrange the solutions in order of increasing acidity. (Note that K (HF) = 6.8 x 10 and K (NH3) = 1.8 × 10-5) Rank solutions from least acidity to greatest acidity. To rank items as equivalent, overlap them. ▸ View Available Hint(s) Least acidity NH&F NaBr NaOH NH,Br NaCIO Reset Greatest acidityarrow_forward1. Consider the following molecular-level diagrams of a titration. O-HA molecule -Aion °° о ° (a) о (b) (c) (d) a. Which diagram best illustrates the microscopic representation for the EQUIVALENCE POINT in a titration of a weak acid (HA) with sodium. hydroxide? (e)arrow_forward
- Answers to the remaining 6 questions will be hand-drawn on paper and submitted as a single file upload below: Review of this week's reaction: H₂NCN (cyanamide) + CH3NHCH2COOH (sarcosine) + NaCl, NH4OH, H₂O ---> H₂NC(=NH)N(CH3)CH2COOH (creatine) Q7. Draw by hand the reaction of creatine synthesis listed above using line structures without showing the Cs and some of the Hs, but include the lone pairs of electrons wherever they apply. (4 pts) Q8. Considering the Zwitterion form of an amino acid, draw the Zwitterion form of Creatine. (2 pts) Q9. Explain with drawing why the C-N bond shown in creatine structure below can or cannot rotate. (3 pts) NH2(C=NH)-N(CH)CH2COOH This bond Q10. Draw two tautomers of creatine using line structures. (Note: this question is valid because problem Q9 is valid). (4 pts) Q11. Mechanism. After seeing and understanding the mechanism of creatine synthesis, students should be ready to understand the first half of one of the Grignard reactions presented in a past…arrow_forwardPropose a synthesis pathway for the following transformations. b) c) d)arrow_forwardThe rate coefficient of the gas-phase reaction 2 NO2 + O3 → N2O5 + O2 is 2.0x104 mol–1 dm3 s–1 at 300 K. Indicate whether the order of the reaction is 0, 1, or 2.arrow_forward
- Organic Chemistry: A Guided InquiryChemistryISBN:9780618974122Author:Andrei StraumanisPublisher:Cengage Learning
