Explanation Section 1: To determine: The final temperature of the body. Answer: The final temperature of the body is 36.85 ° C . Given information: The mass of the body is 70 kg , the specific heat capacity is 3480 J / kg-K and the rate of energy release by the body is 7 × 10 3 kJ / day . Formula to calculate heat lost by the man is, Q 1 = m 1 c 1 ( 37 ° C − T ) Q 1 is the heat lost by the man. m 1 is the mass of the man. T is the final temperature. c 1 is the specific heat capacity of body. The formula to calculate the heat gained by the drink is, Q 2 = m 2 c 2 ( T − 12 ° C ) Q 2 is the heat gained by the drink. m 2 is the mass of the drink. c 2 is the specific heat of drink. From the conservation of energy, the heat lost by the man is equal to the heat gained by the drink. Q 1 = Q 2 m 1 c 1 ( 37 ° C − T ) = m 2 c 2 ( T − 12 ° C ) ( T − 12 ° C ) = m 1 c 1 m 2 c 2 ( 37 ° C − T ) Substitute 70 kg for m 1 , 3480 J / kg- ° C for c 1 , 0.3551 kg for m 2 and 4184 J / kg- ° C for c 2 to find T . ( T − 12 ° C ) = 70 kg ( 3480 J / kg- ° C ) 0.3551 kg ( 4184 J / kg- ° C ) ( 37 ° C − T ) = 164 ( 37 ° C − T ) T = 36

University Physics with Modern Physics Plus Mastering Physics with eText -- Access Card Package (14th Edition)

14th Edition

ISBN: 9780321982582

Author: Hugh D. Young, Roger A. Freedman

Publisher: PEARSON

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Chapter 17, Problem 17.43E

To determine

The time taken by the body to return to 37°C.

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Chapter 17, Problem 17.42E

Chapter 17, Problem 17.44E

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University Physics with Modern Physics Plus Mastering Physics with eText -- Access Card Package (14th Edition)

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The time taken by the body to return to 37 ° C .

Solution Summary: The author explains the formula to calculate the heat lost by the man and the specific heat capacity of the body.

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The time taken by the body to return to 37°C.

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Chapter 17 Solutions