Chapter 17, Problem 17.105SP

Interpretation Introduction

Interpretation:

The amount of copper (in kilograms) that are refined by transfer from anode to cathode in $\text{24}\text{.0}\text{h}$ period has to be calculated.

Concept Introduction:

Moles of Electrons:

The charge on one mole of electrons is $\text{96,500}\text{C,}$ and the number of moles of electrons passed through the cell is calculated as,

$\text{Moles}\text{of}{\text{e}}^{\text{-}}\text{=}\text{Charge(C)×}\frac{\text{1}\text{mole}{\text{e}}^{\text{-}}}{\text{96,500}\text{C}}$

Mass of Substance:

The mass of a substance is calculated from the moles of electrons and atomic weight of the substance.  Using the conversion factors, the mass of substance is calculated from the formula shown below,

$\text{Mass}\text{=}\text{calculated}\text{mole}{\text{e}}^{\text{-}}\text{×}\frac{\text{1}\text{mole}\text{Cu}}{\text{n}\text{mole}{\text{e}}^{\text{-}}}\text{×}\frac{\text{Atomic weight of substance(in g)}}{\text{1}\text{mole}\text{ofsubstance}}\text{×}\frac{\text{1}\text{kg}}{\text{1000}\text{g}}$

The flow chart below is useful in the calculation of grams or litres of the product.

Figure 1