The acid and the base among the two diagrams along with the reason for the difference in their properties is to be explained. Concept introduction: The ability of an acid to ionize describes the strength of the acid. The strength of an oxoacid depends on the polarity of the O − H bond. The polarity is dependent mainly on the electronegativity of the central atom present in the oxoacid. The more electronegative the central atom, the more is its acidic strength. Metals ( M ) have the tendency to lose an electron to form stable ions. Thus, they do not polarize O − H bond, but can polarize M − OH bond releasing OH − ions.

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Answer 1

Question

Chapter 16.19, Problem 1PPC

Interpretation Introduction

Interpretation:

The acid and the base among the two diagrams along with the reason for the difference in their properties is to be explained.

Concept introduction:

The ability of an acid to ionize describes the strength of the acid.

The strength of an oxoacid depends on the polarity of the O−H bond. The polarity is dependent mainly on the electronegativity of the central atom present in the oxoacid. The more electronegative the central atom, the more is its acidic strength.

Metals (M) have the tendency to lose an electron to form stable ions. Thus, they do not polarize O−H bond, but can polarize M−OH bond releasing OH− ions.

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Answer 2

Question

Chapter 16.19, Problem 1PPC

Interpretation Introduction

Interpretation:

The acid and the base among the two diagrams along with the reason for the difference in their properties is to be explained.

Concept introduction:

The ability of an acid to ionize describes the strength of the acid.

The strength of an oxoacid depends on the polarity of the O−H bond. The polarity is dependent mainly on the electronegativity of the central atom present in the oxoacid. The more electronegative the central atom, the more is its acidic strength.

Metals (M) have the tendency to lose an electron to form stable ions. Thus, they do not polarize O−H bond, but can polarize M−OH bond releasing OH− ions.

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Check out a sample textbook solution

See solution

Answer 3

Question

Chapter 16.19, Problem 1PPC

Interpretation Introduction

Interpretation:

The acid and the base among the two diagrams along with the reason for the difference in their properties is to be explained.

Concept introduction:

The ability of an acid to ionize describes the strength of the acid.

The strength of an oxoacid depends on the polarity of the O−H bond. The polarity is dependent mainly on the electronegativity of the central atom present in the oxoacid. The more electronegative the central atom, the more is its acidic strength.

Metals (M) have the tendency to lose an electron to form stable ions. Thus, they do not polarize O−H bond, but can polarize M−OH bond releasing OH− ions.

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Answer 4

Question

Chapter 16.19, Problem 1PPC

Interpretation Introduction

Interpretation:

The acid and the base among the two diagrams along with the reason for the difference in their properties is to be explained.

Concept introduction:

The ability of an acid to ionize describes the strength of the acid.

The strength of an oxoacid depends on the polarity of the O−H bond. The polarity is dependent mainly on the electronegativity of the central atom present in the oxoacid. The more electronegative the central atom, the more is its acidic strength.

Metals (M) have the tendency to lose an electron to form stable ions. Thus, they do not polarize O−H bond, but can polarize M−OH bond releasing OH− ions.

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Answer 5

Chapter 16.19, Problem 1PPC

Interpretation Introduction

Interpretation:

The acid and the base among the two diagrams along with the reason for the difference in their properties is to be explained.

Concept introduction:

The ability of an acid to ionize describes the strength of the acid.

The strength of an oxoacid depends on the polarity of the O−H bond. The polarity is dependent mainly on the electronegativity of the central atom present in the oxoacid. The more electronegative the central atom, the more is its acidic strength.

Metals (M) have the tendency to lose an electron to form stable ions. Thus, they do not polarize O−H bond, but can polarize M−OH bond releasing OH− ions.

Answer 6

Chapter 16.19, Problem 1PPC

Interpretation Introduction

Interpretation:

The acid and the base among the two diagrams along with the reason for the difference in their properties is to be explained.

Concept introduction:

The ability of an acid to ionize describes the strength of the acid.

The strength of an oxoacid depends on the polarity of the O−H bond. The polarity is dependent mainly on the electronegativity of the central atom present in the oxoacid. The more electronegative the central atom, the more is its acidic strength.

Metals (M) have the tendency to lose an electron to form stable ions. Thus, they do not polarize O−H bond, but can polarize M−OH bond releasing OH− ions.

Answer 7

Chapter 16.19, Problem 1PPC

Interpretation Introduction

Interpretation:

The acid and the base among the two diagrams along with the reason for the difference in their properties is to be explained.

Concept introduction:

The ability of an acid to ionize describes the strength of the acid.

The strength of an oxoacid depends on the polarity of the O−H bond. The polarity is dependent mainly on the electronegativity of the central atom present in the oxoacid. The more electronegative the central atom, the more is its acidic strength.

Metals (M) have the tendency to lose an electron to form stable ions. Thus, they do not polarize O−H bond, but can polarize M−OH bond releasing OH− ions.

Answer 8

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Answer 9

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Answer 10

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Answer 11

Ch. 16.1 - Practice Problem ATTEMPT What is (a) the conjugate...Ch. 16.1 - Practice Problem BUILD HSO 3 − is the conjugate...Ch. 16.1 - Practice Problem CONCEPTUALIZE Which of the models...Ch. 16.1 - 16.1.1 Which of the following pairs of species are...Ch. 16.1 - Which of the following species does not have a...Ch. 16.2 - Practice Problem ATTEMPT Identify and label the...Ch. 16.2 - Practice Problem BUILD (a) Write an equation in...Ch. 16.2 - Practice Problem CONCEPTUALIZE Write the formula...Ch. 16.2 - Calculate [ OH − ] in a solution in which [ H 3 O...Ch. 16.2 - Calculate [ H 3 O − ] in a solution in which [ OH...

Solution Summary: The author explains the difference between the two diagrams of the same formula: the ability of an acid to ionize describes its strength, whereas the strength of a non-metal depends on the polarity of its

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