From the given salt solution systems, the X − ion that has the weakest conjugate acidand the decreasing order of the basic strength of the given anions, is to be determined. Concept introduction: A salt is a strong electrolyte, which dissociates completely when added to water. When a salt contains an anion that comes from a weak acid then the anion recombines with water to produce a weak acid and hydroxide ions, and forms a basic solution. The cation, if it comes from a strong base, does not recombine and is present in the solution as a free ion without having any effect on the pH of the solution. The reaction of the salt ( BA ) which takes place is: A − ( aq ) + H 2 O ( l ) ⇌ HA ( aq ) + OH − ( aq ) Here, A − comes from the weak acid HA and B + comes from strong base BOH . The pH of this solution is determined by the [ OH − ] The relationship between K b , K a and K w gives the quantitative basis of the reciprocal relationship between the strength of an acid and its conjugate base or vice-versa. K a × K b = K w …… (1) K b is the measure of dissociation of a base and is known as the base-ionization constant, which is specific at a particular temperature. K b = [ OH − ] [ HA ] [ A − ] …… (2)
From the given salt solution systems, the X − ion that has the weakest conjugate acidand the decreasing order of the basic strength of the given anions, is to be determined. Concept introduction: A salt is a strong electrolyte, which dissociates completely when added to water. When a salt contains an anion that comes from a weak acid then the anion recombines with water to produce a weak acid and hydroxide ions, and forms a basic solution. The cation, if it comes from a strong base, does not recombine and is present in the solution as a free ion without having any effect on the pH of the solution. The reaction of the salt ( BA ) which takes place is: A − ( aq ) + H 2 O ( l ) ⇌ HA ( aq ) + OH − ( aq ) Here, A − comes from the weak acid HA and B + comes from strong base BOH . The pH of this solution is determined by the [ OH − ] The relationship between K b , K a and K w gives the quantitative basis of the reciprocal relationship between the strength of an acid and its conjugate base or vice-versa. K a × K b = K w …… (1) K b is the measure of dissociation of a base and is known as the base-ionization constant, which is specific at a particular temperature. K b = [ OH − ] [ HA ] [ A − ] …… (2)
Solution Summary: The author explains the relationship between the strength of an acid and its conjugate base or vice-versa.
From the given salt solution systems, the X− ion that has the weakest conjugate acidand the decreasing order of the basic strength of the given anions, is to be determined.
Concept introduction:
A salt is a strong electrolyte, which dissociates completely when added to water.
When a salt contains an anion that comes from a weak acid then the anion recombines with water to produce a weak acid and hydroxide ions, and forms a basic solution. The cation, if it comes from a strong base, does not recombine and is present in the solution as a free ion without having any effect on the pH of the solution.
The reaction of the salt (BA) which takes place is:
A−(aq)+H2O(l)⇌HA(aq)+OH−(aq)
Here, A− comes from the weak acid HA and B+ comes from strong base BOH. The pH of this solution is determined by the [OH−]
The relationship between Kb, Ka and Kw gives the quantitative basis of the reciprocal relationship between the strength of an acid and its conjugate base or vice-versa.
Ka×Kb=Kw …… (1)
Kb is the measure of dissociation of a base and is known as the base-ionization constant, which is specific at a particular temperature.
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Problem 19 of 48
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Curved arrows are used to
illustrate the flow of electrons.
Use the reaction conditions
provided and follow the curved
arrows to draw the product of
this carbocation rearrangement.
Include all lone pairs and
charges as appropriate.
H
1,2-alkyl shift
+
Would the following organic synthesis occur in one step? Add any missing products, required catalysts, inorganic reagents, and other important conditions. Please include a detailed explanation and drawings showing how the reaction may occur in one step.
Below is the SN1 reaction of (S)-3-chlorocyclohexene and hydroxide (OH). Draw the missing curved arrows, lone pairs of electrons, and nonzero
formal charges. In the third box, draw the two enantiomeric products that will be produced.
5th attempt
Please draw all four bonds at chiral centers.
Draw the two enantiomeric products that will be produced. Draw in any hydrogen at chiral centers.
1000
4th attempt
Feedback
Please draw all four bonds at chiral centers.
8.
R5
HO:
See Periodic Table
See Hint
H
Cl
Br
Jid See Periodic Table See Hint
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