Introduction to General, Organic and Biochemistry
Introduction to General, Organic and Biochemistry
12th Edition
ISBN: 9780357391594
Author: Frederick A. Bettelheim; William H. Brown; Mary K. Campbell
Publisher: Cengage Learning US
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Chapter 16, Problem 38P
Interpretation Introduction

Interpretation:

To identify the functional groups in Warfarin.

Concept Introduction:

A group of atoms which are responsible for the chemical reactions of a various compounds is known as functional groups.

A stereo centre is the centre where all the 4 groups attached to a carbon are different.

A keto group stays in the equilibrium with its enol (−OH) form by resonance.

NaBH4 is a reducing agent it reduces ketone or aldehyde to an alcohol.

Interpretation Introduction

Interpretation:

To draw the stereorepresentation of the r enantiomer as s enantiomer is more active than r enantiomer.

Concept Introduction:

A stereo centre is the centre where all the 4 groups attached to a carbon are different.

A keto group stays in the equilibrium with its enol (−OH) form by resonance.

NaBH4 is a reducing agent it reduces ketone or aldehyde to an alcohol.

Interpretation Introduction

Interpretation:

To draw the structural formula of keto form of Warfarin.

Concept Introduction:

A stereo centre is the centre where all the 4 groups attached to a carbon are different.

A keto group stays in the equilibrium with its enol (−OH) form by resonance.

NaBH4 is a reducing agent it reduces ketone or aldehyde to an alcohol.

Interpretation Introduction

Interpretation:

To draw the product formed by treating warfarin with NaBH4..

Concept Introduction:

A stereo centre is the centre where all the 4 groups attached to a carbon are different.

A keto group stays in the equilibrium with its enol (−OH) form by resonance.

NaBH4 is a reducing agent it reduces ketone or aldehyde to an alcohol.

Interpretation Introduction

Interpretation:

The number of molecules of warfarin present in 4 mg tablet should be determined.

Concept Introduction:

A stereo centre is the centre where all the 4 groups attached to a carbon are different.

A keto group stays in the equilibrium with its enol (−OH) form by resonance.

NaBH4 is a reducing agent it reduces ketone or aldehyde to an alcohol.

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Just try completing it and it should be straightforward according to the professor and TAs.
The grading is not on correctness, so if you can just get to the correct answers without perfectionism that would be great. They care about the steps and reasoning and that you did something. I asked for an extension, but was denied the extension.

Chapter 16 Solutions

Introduction to General, Organic and Biochemistry

Ch. 16 - 17-11 What is the difference in structure between...Ch. 16 - 17-12 Is it possible for the carbon atom of a...Ch. 16 - 17-13 Which compounds contain carbonyl groups?Ch. 16 - 17-14 Following are structural formulas for two...Ch. 16 - 17-15 Draw structural formulas for the four...Ch. 16 - Prob. 8PCh. 16 - Prob. 9PCh. 16 - 17-18 Draw structural formulas for these ketones....Ch. 16 - 17-19 Write the JUPAC names for these compounds.Ch. 16 - Prob. 12PCh. 16 - 17-2 1 Explain why each name is incorrect. Write...Ch. 16 - Prob. 14PCh. 16 - Prob. 15PCh. 16 - 17-24 In each pair of compounds, select the one...Ch. 16 - Prob. 17PCh. 16 - 17-26 Account for the fact that acetone has a...Ch. 16 - 17-27 Pentane, 1-butanol, and butanal all have...Ch. 16 - 17-28 Show how acetaldehyde can form hydrogen...Ch. 16 - 17-29 Why can’t two molecules of acetone form a...Ch. 16 - 17-30 Answer true or false. (a) The reduction of...Ch. 16 - 17-3 1 Draw a structural formula for the principal...Ch. 16 - Prob. 24PCh. 16 - 17-33 What simple chemical test could you use to...Ch. 16 - 17-34 Explain why liquid aldehydes are often...Ch. 16 - 17-35 Suppose that you take a bottle of...Ch. 16 - 17-36 Explain why the reduction of an aldehyde...Ch. 16 - Prob. 29PCh. 16 - Prob. 30PCh. 16 - Prob. 31PCh. 16 - Prob. 32PCh. 16 - Prob. 33PCh. 16 - Prob. 34PCh. 16 - Prob. 35PCh. 16 - Prob. 36PCh. 16 - Prob. 37PCh. 16 - Prob. 38PCh. 16 - 17-47 What is the characteristic structural...Ch. 16 - Prob. 40PCh. 16 - Prob. 41PCh. 16 - Prob. 42PCh. 16 - Prob. 43PCh. 16 - Prob. 44PCh. 16 - Prob. 45PCh. 16 - 17-54 Following is the structure of...Ch. 16 - Prob. 47PCh. 16 - Prob. 48PCh. 16 - Prob. 49PCh. 16 - Prob. 50PCh. 16 - Prob. 51PCh. 16 - 17-60 1-Propanol can be prepared by the reduction...Ch. 16 - Prob. 53PCh. 16 - 17-62 Show how to bring about these conversions....Ch. 16 - Prob. 55PCh. 16 - Prob. 56PCh. 16 - Prob. 57PCh. 16 - Prob. 58PCh. 16 - 17-67 Draw structural formulas for these...Ch. 16 - Prob. 60PCh. 16 - 17-69 Propanal (bp 49°C) and 1-propanol (bp 97°C)...Ch. 16 - 17-70 What simple chemical test could you use to...Ch. 16 - Prob. 63PCh. 16 - Prob. 64PCh. 16 - Prob. 65PCh. 16 - 17-72 The following molecule is an enediol; each...Ch. 16 - 17-73 Alcohols can be prepared by the...Ch. 16 - 17-74 Glucose, C6H12O6, contains an aldehyde group...Ch. 16 - Prob. 69PCh. 16 - Prob. 70PCh. 16 - Prob. 71PCh. 16 - 17-78 Complete the following equation for these...Ch. 16 - 17-79 Write an equation for each conversion. (a)...Ch. 16 - Prob. 74P
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