Interpretation Introduction To determine: The ranges of [ H + ] and [ OH − ] in the raindrops, pH range of which is 5.2 to 5.6 . Explanation Given The initial pH of the raindrops is 5.2 . The final pH of the raindrops is 5.6 . The initial [ H + ] of raindrops is calculated by the formula, [ H + ] 1 = 10 ( − pH 1 ) Where, [ H + ] 1 is the initial H + pH 1 is the initial pH of the raindrops. Substitute the value of pH 1 in the above formula. [ H + ] 1 = 10 ( − 5.2 ) = 6.31 × 10 − 6 M The final [ H + ] of raindrops is calculated by the formula, [ H + ] 2 = 10 ( − pH 2 ) Where, [ H + ] 2 is the final H + ion concentration of the raindrops. pH 2 is the final pH of the raindrops. Substitute the value of pH 2 in the above formula, [ H + ] 2 = 10 ( − 5.6 ) = 2.51 × 10 − 6 M The initial [ OH − ] of raindrops is calculated by the formula, [ OH − ] 1 = K w [ H + ] 1 Where, [ OH − ] 1 is the initial [ OH − ] of raindrops. K w is the ion-product constant of water ( 1.0 × 10 − 14 ) . Substitute the values of [ H + ] 1 and K w in the above formula

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Chapter 16, Problem 38E

Interpretation Introduction

To determine: The ranges of [H+] and [OH−] in the raindrops, pH range of which is 5.2 to 5.6 .

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Chapter 16, Problem 37E

Chapter 16, Problem 39E

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Chapter 16 Solutions

EP CHEMISTRY:CENTRAL SCI.-MOD.MASTERING

Ch. 16.2 - Practice Exercise 1 Consider the following...Ch. 16.2 - Prob. 16.1.2PE Ch. 16.2 - Prob. 16.2.1PE Ch. 16.2 - Practice Exercise 2 When lithium oxide (Li2O) is...Ch. 16.2 - Based on information in Figure 16.4, place the...Ch. 16.2 - Practice Exercise 2 For each reaction, use Figure...Ch. 16.3 - Practice Exercise 1 In a certain acidic solution...Ch. 16.3 - Practice Exercise 2 Indicate whether solutions...Ch. 16.3 - Prob. 16.5.1PE Ch. 16.3 - Prob. 16.5.2PE

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