Explanation Given The value of p K a 2 .32 . The stated reaction is, HNC 7 H 4 SO 3 ( a q ) ⇌ H + ( a q ) + NC 7 H 4 SO 3 - ( a q ) The change in the concentration of HNC 7 H 4 SO 3 is assumed to be x . The ICE table is formed for the given reaction. HNC 7 H 4 SO 2 ( a q ) → H + ( a q ) + NC 7 H 4 SO 3 − ( a q ) Initial concentration : 0.10 0 0 Change : − x + x + x Equilibrium concentration: 0.10 − x x x The equilibrium concentration of [ HNC 7 H 4 O 3 ] is ( 0.10 − x ) M . The equilibrium concentration of [ NC 7 H 4 SO 3 − ] is x M . The equilibrium concentration of [ H + ] is x M . At equilibrium, the equilibrium constant expression is expressed by the formula, K a = Concentration of products Concentration of reactants Where, K a is the acid dissociation constant

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Chapter 16, Problem 61E

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To determine: The pH of the given solution of saccharin.

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Chapter 16, Problem 60E

Chapter 16, Problem 62E

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