Explanation Neutralization reaction between methylamine and citric acid is, CH 3 NH 2 ( a q ) + H 3 C 6 H 5 O 7 ( a q ) → CH 3 NH 3 + ( a q ) + H 2 C 6 H 5 O 7 − ( a q ) At equilibrium, ionization reaction of citric acid is, H 3 C 6 H 5 O 7 ( a q ) ⇌ H + ( a q ) + H 2 C 6 H 5 O 7 + ( a q ) The value of acid dissociation ( K a ) of citric acid ( H 3 C 6 H 5 O 7 ) is 7.4 × 10 − 4 . Acid dissociation expression for citric acid is, K a = [ H + ] [ H 2 C 6 H 5 O 7 − ] [ H 2 C 6 H 5 O 7 ] ...........(1) At equilibrium, ionization reaction of methylamine is, CH 3 NH 2 ( a q ) + H 2 O ( l ) ⇌ OH − ( a q ) + CH 3 NH 3 + ( a q ) The value of the base ionization ( K b ) of methylamine ( CH 3 NH 2 ) is 4.4 × 10 − 4 . Base ionization expression for methylamine is, K b = [ OH − ] [ CH 3 NH 3 + ] [ CH 3 NH 2 ] ...........(2) Ionization reaction of water is, H 2 O ( l ) ⇌ H + ( a q ) + OH − ( a q ) The value of the ionic product of water is 1.0 × 10 − 14 . Expression for ionic product ( K w ) of water is, K w = [ H + ] [ OH − ] ...........(3) Equilibrium constant expression for the reaction between methylamine ( CH 3 NH 2 ) and citric acid ( H 3 C 6 H 5 O 7 ) is, K eq = [ CH 3 NH 3 + ] [ H 2 C 6 H 5 O 7 − ] [ CH 3 NH 2 ] [ H 3 C 6 H 5 O 7 ] ...........(4) Rearrange the equations (1),(2),(3) and (4) to derive the relationship between ( K eq ) , ( K a ) , ( K b ) , ( K w )

14th Edition

ISBN: 9780137453535

Author: Brown

Publisher: SAVVAS L

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Chapter 16, Problem 101AE

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To determine: The value of the equilibrium constant for the reaction of citric acid with methylamine.

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Chapter 16, Problem 100AE

Chapter 16, Problem 102AE

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Chapter 16 Solutions

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