Explanation Formula used: pH = − log [ H + ] Molarity = Number of moles Volume of the solution Number of moles ( n ) is, n = given mass molar mass Calculation: The formula for calculating pH is, pH = − log [ H + ] Rearrange the above equation to calculate the [ H + ] [ H + ] = 10 − pH Substitute the value of pH in the above equation, [ H + ] = 10 − 2 = 0 .01 M The formula for calculating molarity is, Molarity = Number of moles Volume of solution in liter Rearrange the above equation to calculate moles of [ H + ] Moles of H + ion = Molarity ( M ) × Volume ( L ) Substitute the value of molarity and volume in the above equation, Moles of H + ion = 0 .01 ( M ) × 0

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Chapter 16, Problem 118IE

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To determine: The moles of H+ ions present in the stomach when pH is 2.05and the grams of sodium carbonate needed to neutralize the stomach acid.

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Chapter 16, Problem 117IE

Chapter 16, Problem 119IE

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Chapter 16 Solutions

EP CHEMISTRY:CENTRAL SCI.-MOD.MASTERING

Ch. 16.2 - Practice Exercise 1 Consider the following...Ch. 16.2 - Prob. 16.1.2PE Ch. 16.2 - Prob. 16.2.1PE Ch. 16.2 - Practice Exercise 2 When lithium oxide (Li2O) is...Ch. 16.2 - Based on information in Figure 16.4, place the...Ch. 16.2 - Practice Exercise 2 For each reaction, use Figure...Ch. 16.3 - Practice Exercise 1 In a certain acidic solution...Ch. 16.3 - Practice Exercise 2 Indicate whether solutions...Ch. 16.3 - Prob. 16.5.1PE Ch. 16.3 - Prob. 16.5.2PE

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The moles of H + ions present in the stomach when pH is 2 .05 and the grams of sodium carbonate needed to neutralize the stomach acid.

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To determine: The moles of H+ ions present in the stomach when pH is 2.05and the grams of sodium carbonate needed to neutralize the stomach acid.

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Chapter 16 Solutions