Explanation Given: The value of K w is 1 .00 × 10 − 14 at 25 °C Water possesses amphiprotic nature. The ionization equilibrium reaction of water is, H 2 O → H + + OH − At equilibrium, the equilibrium constant expression is expressed by the formula, K a = Concentration of products Concentration of reactants Where, K a is the acid dissociation constant. The equilibrium constant expression for the stated reaction is expressed by the formula, K a = [ H + ] [ OH − ] [ H 2 O ] .......(1) The formula for the ionic product of water is, K w = [ H + ] [ OH − ] .......(2) From equation (1) and (2), it is concluded that, K a = K w [ H 2 O ] ........(3) Formula used: Molarity = Number of moles Volume of solution in liter Molarity = Density of 1L Molecular mass of water K a = K w [ H 2 O ] Calculation: Formula for calculating molarity is, Molarity = Number of moles Volume of solution in liter Density of water is 1 g / mL Molarity is calculated by the formula, Molarity = Density of 1L Molecular mass of water Substitute the value of density and the molecular mass of water in the above expression

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Chapter 16, Problem 115AE

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To determine: The pKa of water from the given options.

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Chapter 16, Problem 114AE

Chapter 16, Problem 116IE

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Chapter 16 Solutions

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Ch. 16.2 - Practice Exercise 1 Consider the following...Ch. 16.2 - Prob. 16.1.2PE Ch. 16.2 - Prob. 16.2.1PE Ch. 16.2 - Practice Exercise 2 When lithium oxide (Li2O) is...Ch. 16.2 - Based on information in Figure 16.4, place the...Ch. 16.2 - Practice Exercise 2 For each reaction, use Figure...Ch. 16.3 - Practice Exercise 1 In a certain acidic solution...Ch. 16.3 - Practice Exercise 2 Indicate whether solutions...Ch. 16.3 - Prob. 16.5.1PE Ch. 16.3 - Prob. 16.5.2PE

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The p K a of water from the given options.

To determine: The pKa of water from the given options.

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Chapter 16 Solutions