Chemistry For Today: General, Organic, And Biochemistry, Loose-leaf Version
9th Edition
ISBN: 9781305968707
Author: Spencer L. Seager
Publisher: Brooks Cole
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Question
Chapter 16, Problem 16.51E
Interpretation Introduction
Interpretation:
The reason as to why the boiling points of disubstituted amides are lower than those of unsubstituted amides is to be stated.
Concept introduction:
The hydrogen bonding is formed between the electronegative atoms that are already bonded to hydrogen atoms. Mono and unsubstituted amides can form hydrogen bonding with other amides as they have hydrogen atom. Disubstituted amides can form hydrogen bonding only with water.
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Learning Goal:
This question reviews the format for writing an element's written symbol. Recall that written symbols have a particular format. Written symbols use a form like this:
35 Cl
17
In this form the mass number, 35, is a stacked superscript. The atomic number, 17, is a stacked subscript. "CI" is the chemical symbol for the element chlorine. A general way to show this form is:
It is also correct to write symbols by leaving off the atomic number, as in the following form:
atomic number
mass number Symbol
35 Cl or
mass number Symbol
This is because if you write the element symbol, such as Cl, you know the atomic number is 17 from that symbol. Remember that the atomic number, or number of protons in the nucleus, is what defines the element. Thus, if 17 protons
are in the nucleus, the element can only be chlorine. Sometimes you will only see 35 C1, where the atomic number is not written.
Watch this video to review the format for written symbols.
In the following table each column…
need help please and thanks dont understand only need help with C-F
Learning Goal:
As discussed during the lecture, the enzyme HIV-1 reverse transcriptae (HIV-RT) plays a significant role for the HIV virus and is an important drug target. Assume a concentration [E] of 2.00 µM (i.e. 2.00 x 10-6 mol/l) for HIV-RT. Two potential drug molecules, D1 and D2, were identified, which form stable complexes with the HIV-RT.
The dissociation constant of the complex ED1 formed by HIV-RT and the drug D1 is 1.00 nM (i.e. 1.00 x 10-9). The dissociation constant of the complex ED2 formed by HIV-RT and the drug D2 is 100 nM (i.e. 1.00 x 10-7).
Part A - Difference in binding free eenergies
Compute the difference in binding free energy (at a physiological temperature T=310 K) for the complexes. Provide the difference as a positive numerical expression with three significant figures in kJ/mol.
The margin of error is 2%.
Part B - Compare difference in free energy to the thermal…
need help please and thanks dont understand only need help with C-F
Learning Goal:
As discussed during the lecture, the enzyme HIV-1 reverse transcriptae (HIV-RT) plays a significant role for the HIV virus and is an important drug target. Assume a concentration [E] of 2.00 µM (i.e. 2.00 x 10-6 mol/l) for HIV-RT. Two potential drug molecules, D1 and D2, were identified, which form stable complexes with the HIV-RT.
The dissociation constant of the complex ED1 formed by HIV-RT and the drug D1 is 1.00 nM (i.e. 1.00 x 10-9). The dissociation constant of the complex ED2 formed by HIV-RT and the drug D2 is 100 nM (i.e. 1.00 x 10-7).
Part A - Difference in binding free eenergies
Compute the difference in binding free energy (at a physiological temperature T=310 K) for the complexes. Provide the difference as a positive numerical expression with three significant figures in kJ/mol.
The margin of error is 2%.
Part B - Compare difference in free energy to the thermal…
Chapter 16 Solutions
Chemistry For Today: General, Organic, And Biochemistry, Loose-leaf Version
Ch. 16 - Prob. 16.1ECh. 16 - Prob. 16.2ECh. 16 - Prob. 16.3ECh. 16 - Prob. 16.4ECh. 16 - Prob. 16.5ECh. 16 - Prob. 16.6ECh. 16 - Prob. 16.7ECh. 16 - Prob. 16.8ECh. 16 - Give each of the following amines an IUPAC name:...Ch. 16 - Give each of the following amines an IUPAC name....
Ch. 16 - Prob. 16.11ECh. 16 - Prob. 16.12ECh. 16 - Prob. 16.13ECh. 16 - Prob. 16.14ECh. 16 - Prob. 16.15ECh. 16 - Prob. 16.16ECh. 16 - Prob. 16.17ECh. 16 - Prob. 16.18ECh. 16 - Prob. 16.19ECh. 16 - Draw diagrams similar to Figure 16.1 to illustrate...Ch. 16 - Prob. 16.21ECh. 16 - Prob. 16.22ECh. 16 - Prob. 16.23ECh. 16 - Prob. 16.24ECh. 16 - Prob. 16.25ECh. 16 - Prob. 16.26ECh. 16 - Prob. 16.27ECh. 16 - Prob. 16.28ECh. 16 - Prob. 16.29ECh. 16 - Prob. 16.30ECh. 16 - Prob. 16.31ECh. 16 - Prob. 16.32ECh. 16 - Prob. 16.33ECh. 16 - Describe the general structure of a neuron.Ch. 16 - Name the two amino acids that are starting...Ch. 16 - Prob. 16.36ECh. 16 - Prob. 16.37ECh. 16 - Prob. 16.38ECh. 16 - Prob. 16.39ECh. 16 - Prob. 16.40ECh. 16 - Prob. 16.41ECh. 16 - Prob. 16.42ECh. 16 - Why are alkaloids weakly basic?Ch. 16 - Prob. 16.44ECh. 16 - Prob. 16.45ECh. 16 - Prob. 16.46ECh. 16 - Prob. 16.47ECh. 16 - Prob. 16.48ECh. 16 - Prob. 16.49ECh. 16 - Prob. 16.50ECh. 16 - Prob. 16.51ECh. 16 - Complete the following reactions: a. b.Ch. 16 - Complete the following reactions: a. b.Ch. 16 - Prob. 16.54ECh. 16 - What are the products of the acid hydrolysis of...Ch. 16 - Prob. 16.56ECh. 16 - Prob. 16.57ECh. 16 - Prob. 16.58ECh. 16 - Prob. 16.59ECh. 16 - Prob. 16.60ECh. 16 - Prob. 16.61ECh. 16 - Prob. 16.62ECh. 16 - Prob. 16.63ECh. 16 - Prob. 16.64ECh. 16 - Prob. 16.65ECh. 16 - Prob. 16.66ECh. 16 - Prob. 16.67ECh. 16 - Prob. 16.68ECh. 16 - Prob. 16.69ECh. 16 - Prob. 16.70ECh. 16 - Prob. 16.71ECh. 16 - The stimulant in coffee is: a. tannic acid b....Ch. 16 - What are the most likely products of a reaction...
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