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(a)
Interpretation:
The given amine has to be named and it should be indicated whether as the ammonium salt of a primary, secondary or tertiary amine.
Concept introduction:
In chemistry Structure is the arrangement of
Depending on the number of carbon side chain of the nitrogen, different types of amines can form.
From the name of the compound its structure can be determined.
Primary amines can be named in the IUPAC system in several ways,
For simple amines the suffix – amine is added to the name of the alkyl substituent.
The suffix-amine can be used in place of the final –e in the name of the parent compound.
For a secondary amine an N prefixes the compound giving the shorter carbon chain and its chain prefix name.
For a tertiary amine an N, N prefixes the compound giving the two shorter carbon chains and their side chain prefix names.
Ammonia is very soluble in water giving an alkaline solution which can be neutralized by acids to produce ammonium salts.
(b)
Interpretation:
The structure of the given compound has to be drawn and it should be indicated whether as the ammonium salt of a primary, secondary or tertiary amine.
Concept introduction:
In chemistry Structure is the arrangement of chemical bonds between atoms in a molecule, specifically which atoms are chemically bonded to what other atoms with what kind of chemical bond.
Amines are the derivatives of ammonia
Depending on the number of carbon side chain of the nitrogen, different types of amines can form.
From the name of the compound its structure can be determined.
Primary amines can be named in the IUPAC system in several ways,
For simple amines the suffix – amine is added to the name of the alkyl substituent.
The suffix-amine can be used in place of the final –e in the name of the parent compound.
For a secondary amine an N prefixes the compound giving the shorter carbon chain and its chain prefix name.
For a tertiary amine an N, N prefixes the compound giving the two shorter carbon chains and their side chain prefix names.
Ammonia is very soluble in water giving an alkaline solution which can be neutralized by acids to produce ammonium salts.
Heterocyclic amine is a five or six membered cyclic organic compound which contains one or more nitrogen atoms.
(c)
Interpretation:
The structure of the given compound has to be drawn and it should be indicated whether as the ammonium salt of a primary, secondary or tertiary amine.
Concept introduction:
In chemistry Structure is the arrangement of chemical bonds between atoms in a molecule, specifically which atoms are chemically bonded to what other atoms with what kind of chemical bond.
Amines are the derivatives of ammonia
Depending on the number of carbon side chain of the nitrogen, different types of amines can form.
From the name of the compound its structure can be determined.
Primary amines can be named in the IUPAC system in several ways,
For simple amines the suffix – amine is added to the name of the alkyl substituent.
The suffix-amine can be used in place of the final –e in the name of the parent compound.
For a secondary amine an N prefixes the compound giving the shorter carbon chain and its chain prefix name.
For a tertiary amine an N, N prefixes the compound giving the two shorter carbon chains and their side chain prefix names.
Ammonia is very soluble in water giving an alkaline solution which can be neutralized by acids to produce ammonium salts.
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Chapter 16 Solutions
Pearson eText Fundamentals of General, Organic, and Biological Chemistry -- Instant Access (Pearson+)
- Problem 15 of 15 Submit Using the following reaction data points, construct Lineweaver-Burk plots for an enzyme with and without an inhibitor by dragging the points to their relevant coordinates on the graph and drawing a line of best fit. Using the information from this plot, determine the type of inhibitor present. 1 mM-1 1 s mM -1 [S]' V' with 10 μg per 20 54 10 36 20 5 27 2.5 23 1.25 20 Answer: |||arrow_forward12:33 CO Problem 4 of 15 4G 54% Done On the following Lineweaver-Burk -1 plot, identify the by dragging the Km point to the appropriate value. 1/V 40 35- 30- 25 20 15 10- T Км -15 10 -5 0 5 ||| 10 15 №20 25 25 30 1/[S] Г powered by desmosarrow_forward1:30 5G 47% Problem 10 of 15 Submit Using the following reaction data points, construct a Lineweaver-Burk plot for an enzyme with and without a competitive inhibitor by dragging the points to their relevant coordinates on the graph and drawing a line of best fit. 1 -1 1 mM [S]' s mM¹ with 10 mg pe 20 V' 54 10 36 > ст 5 27 2.5 23 1.25 20 Answer: |||arrow_forward
- Problem 14 of 15 Submit Using the following reaction data points, construct Lineweaver-Burk plots for an enzyme with and without an inhibitor by dragging the points to their relevant coordinates on the graph and drawing a line of best fit. Using the information from this plot, determine the type of inhibitor present. 1 mM-1 1 s mM -1 [S]' V' with 10 μg per 20 54 10 36 20 5 27 2.5 23 1.25 20 Answer: |||arrow_forward12:36 CO Problem 9 of 15 4G. 53% Submit Using the following reaction data points, construct a Lineweaver-Burk plot by dragging the points to their relevant coordinates on the graph and drawing a line of best fit. Based on the plot, determine the value of the catalytic efficiency (specificity constant) given that the enzyme concentration in this experiment is 5.0 μ.Μ. 1 [S] ¨‚ μM-1 1 V sμM-1 100.0 0.100 75.0 0.080 50.0 0.060 15.0 0.030 10.0 0.025 5.0 0.020 Answer: ||| O Гarrow_forwardProblem 11 of 15 Submit Using the following reaction data points, construct a Lineweaver-Burk plot for an enzyme with and without a noncompetitive inhibitor by dragging the points to their relevant coordinates on the graph and drawing a line of best fit. 1 -1 1 mM [S]' 20 V' s mM¹ with 10 μg per 54 10 36 > ст 5 27 2.5 23 1.25 20 Answer: |||arrow_forward
- Problem 13 of 15 Submit Using the following reaction data points, construct Lineweaver-Burk plots for an enzyme with and without an inhibitor by dragging the points to their relevant coordinates on the graph and drawing a line of best fit. Using the information from this plot, determine the type of inhibitor present. 1 mM-1 1 s mM -1 [S]' V' with 10 μg per 20 54 10 36 20 5 27 2.5 23 1.25 20 Answer: |||arrow_forward12:33 CO Problem 8 of 15 4G. 53% Submit Using the following reaction data points, construct a Lineweaver-Burk plot by dragging the points to their relevant coordinates on the graph and drawing a line of best fit. Based on the plot, determine the value of kcat given that the enzyme concentration in this experiment is 5.0 μM. 1 [S] , мм -1 1 V₁ s μM 1 100.0 0.100 75.0 0.080 50.0 0.060 15.0 0.030 10.0 0.025 5.0 0.020 Answer: ||| Гarrow_forward1:33 5G. 46% Problem 12 of 15 Submit Using the following reaction data points, construct a Lineweaver-Burk plot for an enzyme with and without an uncompetitive inhibitor by dragging the points to their relevant coordinates on the graph and drawing a line of best fit. 1 -1 1 mM [S]' 20 V' s mM¹ with 10 μg per 54 10 36 > ст 5 27 2.5 23 1.25 20 Answer: |||arrow_forward
- Principles Of Radiographic Imaging: An Art And A ...Health & NutritionISBN:9781337711067Author:Richard R. Carlton, Arlene M. Adler, Vesna BalacPublisher:Cengage LearningAnatomy & PhysiologyBiologyISBN:9781938168130Author:Kelly A. Young, James A. Wise, Peter DeSaix, Dean H. Kruse, Brandon Poe, Eddie Johnson, Jody E. Johnson, Oksana Korol, J. Gordon Betts, Mark WomblePublisher:OpenStax College
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