Given that cyclopropanone is highly reactive because of the large angle strain in the molecule. Methylcyclopropenone, although even more strained than cyclopropanone, is quite stable and can even be distilled. Taking the polarity of the carbonyl group into account this observation is to be explained. Concept introduction: Carbonyl group is polar as oxygen is more electronegative than carbon. According to Huckel’s rule, any specie that is cyclic, planar and has (4n+2) Ï€ electrons will be aromatic and stable. Thus species with 2, 6, 10, 14 etc. Ï€ electrons will be aromatic and stable. To explain: Taking into account the polarity of the carbonyl group, the observation that cyclopropanone is highly reactive because of the large angle strain in the molecule while methylcyclopropenone, although even more strained than cyclopropanone, is quite stable and can even be distilled.

Question

Complete the reaction in the drawing area below by adding the major products to the right-hand side. If there won't be any products, because nothing will happen under these reaction conditions, check the box under the drawing area instead. Note: if the products contain one or more pairs of enantiomers, don't worry about drawing each enantiomer with dash and wedge bonds. Just draw one molecule to represent each pair of enantiomers, using line bonds at the chiral center. More... No reaction. my ㄖˋ + 1. Na O Me Click and drag to start drawing a structure. 2. H +

Answer 1

Question

Definition Definition Rule that estimates whether a given organic planar ring structure will show an aromatic property. A cyclic ring molecule is said to follow Hückel’s rule if the л-electrons count in a molecule is [4n+2], where n stands for a positive numerical value. It is also called the [4n+2] rule. Hückel's rule, sometimes referred to as the aromaticity rule, is one but not the only criteria to judge a molecule for aromaticity.

Chapter 15.SE, Problem 31AP

Interpretation Introduction

Interpretation:

Given that cyclopropanone is highly reactive because of the large angle strain in the molecule. Methylcyclopropenone, although even more strained than cyclopropanone, is quite stable and can even be distilled. Taking the polarity of the carbonyl group into account this observation is to be explained.

Concept introduction:

Carbonyl group is polar as oxygen is more electronegative than carbon. According to Huckel’s rule, any specie that is cyclic, planar and has (4n+2) Ï€ electrons will be aromatic and stable. Thus species with 2, 6, 10, 14 etc. Ï€ electrons will be aromatic and stable.

To explain:

Taking into account the polarity of the carbonyl group, the observation that cyclopropanone is highly reactive because of the large angle strain in the molecule while methylcyclopropenone, although even more strained than cyclopropanone, is quite stable and can even be distilled.

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Complete the reaction in the drawing area below by adding the major products to the right-hand side. If there won't be any products, because nothing will happen under these reaction conditions, check the box under the drawing area instead. Note: if the products contain one or more pairs of enantiomers, don't worry about drawing each enantiomer with dash and wedge bonds. Just draw one molecule to represent each pair of enantiomers, using line bonds at the chiral center. More... No reaction. my ㄖˋ + 1. Na O Me Click and drag to start drawing a structure. 2. H +

Predict the intermediate 1 and final product 2 of this organic reaction: NaOMe H+ + 1 2 H H work up You can draw 1 and 2 in any arrangement you like. Note: if either 1 or 2 consists of a pair of enantiomers, just draw one structure using line bonds instead of 3D (dash and wedge) bonds at the chiral center. Click and drag to start drawing a structure. X $ dm

Predict the major products of this organic reaction: 1. NaH (20°C) 2. CH3Br ? Some notes: • Draw only the major product, or products. You can draw them in any arrangement you like. • Be sure to use wedge and dash bonds where necessary, for example to distinguish between major products that are enantiomers. • If there are no products, just check the box under the drawing area. No reaction. Click and drag to start drawing a structure. G Cr

Answer 2

Question

Definition Definition Rule that estimates whether a given organic planar ring structure will show an aromatic property. A cyclic ring molecule is said to follow Hückel’s rule if the л-electrons count in a molecule is [4n+2], where n stands for a positive numerical value. It is also called the [4n+2] rule. Hückel's rule, sometimes referred to as the aromaticity rule, is one but not the only criteria to judge a molecule for aromaticity.

Chapter 15.SE, Problem 31AP

Interpretation Introduction

Interpretation:

Given that cyclopropanone is highly reactive because of the large angle strain in the molecule. Methylcyclopropenone, although even more strained than cyclopropanone, is quite stable and can even be distilled. Taking the polarity of the carbonyl group into account this observation is to be explained.

Concept introduction:

Carbonyl group is polar as oxygen is more electronegative than carbon. According to Huckel’s rule, any specie that is cyclic, planar and has (4n+2) Ï€ electrons will be aromatic and stable. Thus species with 2, 6, 10, 14 etc. Ï€ electrons will be aromatic and stable.

To explain:

Taking into account the polarity of the carbonyl group, the observation that cyclopropanone is highly reactive because of the large angle strain in the molecule while methylcyclopropenone, although even more strained than cyclopropanone, is quite stable and can even be distilled.

Expert Solution & Answer

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Answer 3

Question

Definition Definition Rule that estimates whether a given organic planar ring structure will show an aromatic property. A cyclic ring molecule is said to follow Hückel’s rule if the л-electrons count in a molecule is [4n+2], where n stands for a positive numerical value. It is also called the [4n+2] rule. Hückel's rule, sometimes referred to as the aromaticity rule, is one but not the only criteria to judge a molecule for aromaticity.

Chapter 15.SE, Problem 31AP

Interpretation Introduction

Interpretation:

Given that cyclopropanone is highly reactive because of the large angle strain in the molecule. Methylcyclopropenone, although even more strained than cyclopropanone, is quite stable and can even be distilled. Taking the polarity of the carbonyl group into account this observation is to be explained.

Concept introduction:

Carbonyl group is polar as oxygen is more electronegative than carbon. According to Huckel’s rule, any specie that is cyclic, planar and has (4n+2) Ï€ electrons will be aromatic and stable. Thus species with 2, 6, 10, 14 etc. Ï€ electrons will be aromatic and stable.

To explain:

Taking into account the polarity of the carbonyl group, the observation that cyclopropanone is highly reactive because of the large angle strain in the molecule while methylcyclopropenone, although even more strained than cyclopropanone, is quite stable and can even be distilled.

Expert Solution & Answer

Trending nowThis is a popular solution!

See solution

Check out sample textbook solution

Answer 4

Question

Definition Definition Rule that estimates whether a given organic planar ring structure will show an aromatic property. A cyclic ring molecule is said to follow Hückel’s rule if the л-electrons count in a molecule is [4n+2], where n stands for a positive numerical value. It is also called the [4n+2] rule. Hückel's rule, sometimes referred to as the aromaticity rule, is one but not the only criteria to judge a molecule for aromaticity.

Chapter 15.SE, Problem 31AP

Interpretation Introduction