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A C−-D bond is harder to break than a C−-H bond, and, consequently, reactions in which C−-D bonds are broken proceed more slowly than reactions in which C−-H bonds are broken. What mechanistic information comes from the observation that perdeuterated benzene,
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- A second-order-reaction of the type A +2 B→ P was carried out in a solution that was initially 0.075 mol dm3 in A and 0.030 mol dm3 in B. After 1.0 h the concentration of A had fallen to 0.045 mol dm3. (a) Calculate the rate constant. (b) What is the half-life of the reactants? The rate constant for the decomposition of a certain substance is 1.70 x 10-2 dm³ mol-¹ s¹ at 24°C and 2.01 x 10-2 dm³ mol-¹ s¹ at 37°C. Evaluate the Arrhenius parameters of the reaction. A reaction 2 AP has a third-order rate law with k = 3.50 x 104 dmº mol2 s¹. Calculate the time required for the concentration of A to change from 0.077 mol dm3 to 0.021 mol dm³.arrow_forwardA rate constant is found to fit the expression kr = Ae−(4972 K)/T with A = 4.98 × 1013 dm3 mol−1 s−1 near 25 °C. Calculate Δ‡G for the reaction at 25 °C; assume κ = 1.arrow_forwardSome reactions proceed through a chain mechanism involving radicals, which are highly reactive species with one or more unpaired electrons. The radicals are produced in initiation steps, through either thermal or photodissociation. Reactions in which the radical centre is transferred are called propagation steps. The radicals are lost in termination steps. Consider the following chain mechanism:(1) AH → A + H·(2) A → B· + C(3) AH + B· → A + D(4) A + B· → P(a) Identify the initiation, propagation, and termination steps.(b) Use the steady-state approximation to deduce that the decompositionof AH is f irst-order in AH.arrow_forward
- Alcohol is removed from the bloodstream by a series of metabolic reactions. The first reaction produces acetaldehyde; then other products are formed. The following data have been determined for the rate at which alcohol is removed from the blood of an average male, although individual rates can vary by 25-30%. Women metabolize alcohol a little more slowly than men: [CH,OH] (M) 4.4 x 10-2 3.3 x 10-2 2.2 x 10-2 Rate (mol/L/h) 2.0 x 10-2 2.0 × 10-2 2.0 x 10-2 Determine the rate equation, the rate constant, and the overall order for this reaction.arrow_forwardConventional equilibrium considerations do not apply when a reaction is driven by light absorption and the steady-state concentration of products and reactants might differ significantly from equilibrium values. For instance, suppose the reaction A → B is driven by light absorption, and that its rate is Ia, but that the reverse reaction B → A is bimolecular and second order with a rate kr[B]2. What is the stationary state concentration of B? Why does this ‘photostationary state’ differ from the equilibrium state?arrow_forwardwrite a rate law for the following reaction if reaction order n=1 2 N2O5 (g) -> 4 NO2 (g) + O2 (g)arrow_forward
- The conversion of high molecular weight olefins into saturated hydrocarbons makes use ofH 2 and is a heterogeneous process catalyzed by nickel. Draw and describe the mechanismaccording to the LH mechanism.arrow_forward20B.2(b) The rate constant for the first-order decomposition of a compound A in the reaction 2 A→P is krr=3.56×10−7 s−1 at 25 °C. What is the half-life of A? What will be the pressure, initially 33.0 kPa after (i) 50 s, (ii) 20 min after initiation of the reaction?arrow_forwardA reaction has Keq' = 120. The rate constant of this reaction was found to be 1.11x 101s-1. If the catalytic power of an enzyme for this reaction is 1.25 x 10', what is the rate constant, in s1, for the reverse direction of the catalyzed reaction?arrow_forward
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