Complete the following summary of Morgan’s crosses involving the mutant white-eyed fly by filling in the Punnett square and indicating the genotypes and phenotypes of the F 2 generation. (X w stands for the mutant recessive white allele; X w + for the wild-type red allele.) The Y reminds you that this eye color gene is not present on the Y chromosome. Genotypes ___ _ _ _ Phenotypes _ _ _ ___

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Answer 1

Textbook Question

Chapter 15, Problem 1IQ

Complete the following summary of Morgan’s crosses involving the mutant white-eyed fly by filling in the Punnett square and indicating the genotypes and phenotypes of the F₂ generation. (X^w stands for the mutant recessive white allele; X^w⁺ for the wild-type red allele.) The Y reminds you that this eye color gene is not present on the Y chromosome.

Chapter 15, Problem 1IQ, Complete the following summary of Morgans crosses involving the mutant white-eyed fly by filling in

Genotypes

_____ _____ _____ _____

Phenotypes

_____ _____ _____ _____

Expert Solution & Answer

Summary Introduction

To complete: The summary of Morgan’s cross that involves the mutant white-eyed fly by filling in the Punnett square and by indicating the genotypes and phenotypes of the F₂ generation.

Introduction: Sex chromosomes are those chromosomes that play a crucial role in determination of sex of the individual. They have important function in the development of sexual characteristics in the organisms.

Answer to Problem 1IQ

Pictorial representation: Fig.1 represents the summary of Morgan’s cross that involves the mutant white-eyed fly by filling in the Punnett square and by indicating the genotypes and phenotypes of the F₂ generation.

Study Guide for Campbell Biology, Chapter 15, Problem 1IQ

Fig.1: Morgan’s cross of mutant white-eyed fly with the genotypes and phenotypes of the F₂ generation

Explanation of Solution

The X and Y chromosomes act as sex chromosomes in most of the organisms. The genes that are present on the sex chromosome are called sex-linked genes. There are approximately 1,100 X-linked genes. On the other hand, Y chromosome contains relatively very few genes.

The sex-linked genes display a unique pattern of inheritance. The expression of recessive X-linked trait requires two copies of alleles in females (homozygous) and only one copy of the allele in males (hemizygous). The probability of a male to receive a single mutated X-linked gene from their mother is high as compared to a female receiving both the X-linked mutated genes from the mother (carrier) and father (carrier).

When Morgan crossed red-eyed female (wild-type) with white-eyed male (mutant), all the offspring were red-eyed in the first generation (F₁). Then, he again crossed the F₁red-eyed female to the red-eyed male of F₁. The typical ratio of 3:1 (red-eyed flies: white eyed flies) was observed in the F₂ generation, but all white-eyed flies were males.

Morgan concluded that this could be due to hemizygous condition (presence of single X-chromosome “X^W+Y”) of the males. Females required both the mutated alleles to express the phenotype (white eye color), while males needed only one mutated allele to show the phenotype. The probability to inherit both mutated copies is less.

Hence, four genotypes of F₂ generation are as follows:

X^W+X^W+
X^W+X^W
X^W+Y
X^WY

The four phenotypes of F₂ generation are as follows:

Red-eyed female
Red-eyed female
Red-eyed male
White-eyed male.

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03:46

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After you feel comfortable with your counting method and identifying cells in the various stages of mitosis, use the four images below of whitefish blastula to count the cells in each stage until you reach 100 total cells, recording your data below in Data Table 1. (You may not need to use all four images. Stop counting when you reach 100 total cells.) After totaling the cells in each stage, calculate the percent of cells in each stage. (Divide total of stage by overall total of 100 and then multiply by 100 to obtain percentage.) Data Table 1Stage Totals PercentInterphase Mitosis: Prophase Metaphase Anaphase Telophase Cytokinesis Totals 100 100% To find the length of time whitefish blastula cells spend in each stage, multiply the percent (recorded as a decimal, in other words take the percent number and divide by 100) by 24 hours. (Example: If percent is 20%, then Time in Hours = .2 * 24 = 4.8) Record your data in Data…

Answer 2

Textbook Question

Chapter 15, Problem 1IQ

Complete the following summary of Morgan’s crosses involving the mutant white-eyed fly by filling in the Punnett square and indicating the genotypes and phenotypes of the F₂ generation. (X^w stands for the mutant recessive white allele; X^w⁺ for the wild-type red allele.) The Y reminds you that this eye color gene is not present on the Y chromosome.

Chapter 15, Problem 1IQ, Complete the following summary of Morgans crosses involving the mutant white-eyed fly by filling in

Genotypes

_____ _____ _____ _____

Phenotypes

_____ _____ _____ _____

Expert Solution & Answer

Summary Introduction

To complete: The summary of Morgan’s cross that involves the mutant white-eyed fly by filling in the Punnett square and by indicating the genotypes and phenotypes of the F₂ generation.

Introduction: Sex chromosomes are those chromosomes that play a crucial role in determination of sex of the individual. They have important function in the development of sexual characteristics in the organisms.

Answer to Problem 1IQ

Pictorial representation: Fig.1 represents the summary of Morgan’s cross that involves the mutant white-eyed fly by filling in the Punnett square and by indicating the genotypes and phenotypes of the F₂ generation.

Study Guide for Campbell Biology, Chapter 15, Problem 1IQ

Fig.1: Morgan’s cross of mutant white-eyed fly with the genotypes and phenotypes of the F₂ generation

Explanation of Solution

The X and Y chromosomes act as sex chromosomes in most of the organisms. The genes that are present on the sex chromosome are called sex-linked genes. There are approximately 1,100 X-linked genes. On the other hand, Y chromosome contains relatively very few genes.

The sex-linked genes display a unique pattern of inheritance. The expression of recessive X-linked trait requires two copies of alleles in females (homozygous) and only one copy of the allele in males (hemizygous). The probability of a male to receive a single mutated X-linked gene from their mother is high as compared to a female receiving both the X-linked mutated genes from the mother (carrier) and father (carrier).

When Morgan crossed red-eyed female (wild-type) with white-eyed male (mutant), all the offspring were red-eyed in the first generation (F₁). Then, he again crossed the F₁red-eyed female to the red-eyed male of F₁. The typical ratio of 3:1 (red-eyed flies: white eyed flies) was observed in the F₂ generation, but all white-eyed flies were males.

Morgan concluded that this could be due to hemizygous condition (presence of single X-chromosome “X^W+Y”) of the males. Females required both the mutated alleles to express the phenotype (white eye color), while males needed only one mutated allele to show the phenotype. The probability to inherit both mutated copies is less.

Hence, four genotypes of F₂ generation are as follows:

X^W+X^W+
X^W+X^W
X^W+Y
X^WY

The four phenotypes of F₂ generation are as follows:

Red-eyed female
Red-eyed female
Red-eyed male
White-eyed male.

Want to see more full solutions like this?

Subscribe now to access step-by-step solutions to millions of textbook problems written by subject matter experts!

03:46

Answer 3

Textbook Question

Chapter 15, Problem 1IQ

Complete the following summary of Morgan’s crosses involving the mutant white-eyed fly by filling in the Punnett square and indicating the genotypes and phenotypes of the F₂ generation. (X^w stands for the mutant recessive white allele; X^w⁺ for the wild-type red allele.) The Y reminds you that this eye color gene is not present on the Y chromosome.

Chapter 15, Problem 1IQ, Complete the following summary of Morgans crosses involving the mutant white-eyed fly by filling in

Genotypes

_____ _____ _____ _____

Phenotypes

_____ _____ _____ _____

Expert Solution & Answer

Summary Introduction

To complete: The summary of Morgan’s cross that involves the mutant white-eyed fly by filling in the Punnett square and by indicating the genotypes and phenotypes of the F₂ generation.

Introduction: Sex chromosomes are those chromosomes that play a crucial role in determination of sex of the individual. They have important function in the development of sexual characteristics in the organisms.

Answer to Problem 1IQ

Pictorial representation: Fig.1 represents the summary of Morgan’s cross that involves the mutant white-eyed fly by filling in the Punnett square and by indicating the genotypes and phenotypes of the F₂ generation.

Study Guide for Campbell Biology, Chapter 15, Problem 1IQ

Fig.1: Morgan’s cross of mutant white-eyed fly with the genotypes and phenotypes of the F₂ generation

Explanation of Solution

The X and Y chromosomes act as sex chromosomes in most of the organisms. The genes that are present on the sex chromosome are called sex-linked genes. There are approximately 1,100 X-linked genes. On the other hand, Y chromosome contains relatively very few genes.

The sex-linked genes display a unique pattern of inheritance. The expression of recessive X-linked trait requires two copies of alleles in females (homozygous) and only one copy of the allele in males (hemizygous). The probability of a male to receive a single mutated X-linked gene from their mother is high as compared to a female receiving both the X-linked mutated genes from the mother (carrier) and father (carrier).

When Morgan crossed red-eyed female (wild-type) with white-eyed male (mutant), all the offspring were red-eyed in the first generation (F₁). Then, he again crossed the F₁red-eyed female to the red-eyed male of F₁. The typical ratio of 3:1 (red-eyed flies: white eyed flies) was observed in the F₂ generation, but all white-eyed flies were males.

Morgan concluded that this could be due to hemizygous condition (presence of single X-chromosome “X^W+Y”) of the males. Females required both the mutated alleles to express the phenotype (white eye color), while males needed only one mutated allele to show the phenotype. The probability to inherit both mutated copies is less.

Hence, four genotypes of F₂ generation are as follows:

X^W+X^W+
X^W+X^W
X^W+Y
X^WY

The four phenotypes of F₂ generation are as follows:

Red-eyed female
Red-eyed female
Red-eyed male
White-eyed male.

Want to see more full solutions like this?

Subscribe now to access step-by-step solutions to millions of textbook problems written by subject matter experts!

03:46

Answer 4

Textbook Question

Chapter 15, Problem 1IQ

Complete the following summary of Morgan’s crosses involving the mutant white-eyed fly by filling in the Punnett square and indicating the genotypes and phenotypes of the F₂ generation. (X^w stands for the mutant recessive white allele; X^w⁺ for the wild-type red allele.) The Y reminds you that this eye color gene is not present on the Y chromosome.

Chapter 15, Problem 1IQ, Complete the following summary of Morgans crosses involving the mutant white-eyed fly by filling in

Genotypes

_____ _____ _____ _____

Phenotypes

_____ _____ _____ _____

Expert Solution & Answer

Summary Introduction

To complete: The summary of Morgan’s cross that involves the mutant white-eyed fly by filling in the Punnett square and by indicating the genotypes and phenotypes of the F₂ generation.

Introduction: Sex chromosomes are those chromosomes that play a crucial role in determination of sex of the individual. They have important function in the development of sexual characteristics in the organisms.

Answer to Problem 1IQ

Pictorial representation: Fig.1 represents the summary of Morgan’s cross that involves the mutant white-eyed fly by filling in the Punnett square and by indicating the genotypes and phenotypes of the F₂ generation.

Study Guide for Campbell Biology, Chapter 15, Problem 1IQ

Fig.1: Morgan’s cross of mutant white-eyed fly with the genotypes and phenotypes of the F₂ generation

Explanation of Solution

The X and Y chromosomes act as sex chromosomes in most of the organisms. The genes that are present on the sex chromosome are called sex-linked genes. There are approximately 1,100 X-linked genes. On the other hand, Y chromosome contains relatively very few genes.

The sex-linked genes display a unique pattern of inheritance. The expression of recessive X-linked trait requires two copies of alleles in females (homozygous) and only one copy of the allele in males (hemizygous). The probability of a male to receive a single mutated X-linked gene from their mother is high as compared to a female receiving both the X-linked mutated genes from the mother (carrier) and father (carrier).

When Morgan crossed red-eyed female (wild-type) with white-eyed male (mutant), all the offspring were red-eyed in the first generation (F₁). Then, he again crossed the F₁red-eyed female to the red-eyed male of F₁. The typical ratio of 3:1 (red-eyed flies: white eyed flies) was observed in the F₂ generation, but all white-eyed flies were males.

Morgan concluded that this could be due to hemizygous condition (presence of single X-chromosome “X^W+Y”) of the males. Females required both the mutated alleles to express the phenotype (white eye color), while males needed only one mutated allele to show the phenotype. The probability to inherit both mutated copies is less.

Hence, four genotypes of F₂ generation are as follows:

X^W+X^W+
X^W+X^W
X^W+Y
X^WY

The four phenotypes of F₂ generation are as follows:

Red-eyed female
Red-eyed female
Red-eyed male
White-eyed male.

Want to see more full solutions like this?

Subscribe now to access step-by-step solutions to millions of textbook problems written by subject matter experts!

03:46

Answer 5

Textbook Question

Answer 6

Textbook Question

Answer 7

Expert Solution & Answer

Summary Introduction

To complete: The summary of Morgan’s cross that involves the mutant white-eyed fly by filling in the Punnett square and by indicating the genotypes and phenotypes of the F₂ generation.

Introduction: Sex chromosomes are those chromosomes that play a crucial role in determination of sex of the individual. They have important function in the development of sexual characteristics in the organisms.

Answer to Problem 1IQ

Pictorial representation: Fig.1 represents the summary of Morgan’s cross that involves the mutant white-eyed fly by filling in the Punnett square and by indicating the genotypes and phenotypes of the F₂ generation.

Study Guide for Campbell Biology, Chapter 15, Problem 1IQ

Fig.1: Morgan’s cross of mutant white-eyed fly with the genotypes and phenotypes of the F₂ generation

Explanation of Solution

The X and Y chromosomes act as sex chromosomes in most of the organisms. The genes that are present on the sex chromosome are called sex-linked genes. There are approximately 1,100 X-linked genes. On the other hand, Y chromosome contains relatively very few genes.

The sex-linked genes display a unique pattern of inheritance. The expression of recessive X-linked trait requires two copies of alleles in females (homozygous) and only one copy of the allele in males (hemizygous). The probability of a male to receive a single mutated X-linked gene from their mother is high as compared to a female receiving both the X-linked mutated genes from the mother (carrier) and father (carrier).

When Morgan crossed red-eyed female (wild-type) with white-eyed male (mutant), all the offspring were red-eyed in the first generation (F₁). Then, he again crossed the F₁red-eyed female to the red-eyed male of F₁. The typical ratio of 3:1 (red-eyed flies: white eyed flies) was observed in the F₂ generation, but all white-eyed flies were males.

Morgan concluded that this could be due to hemizygous condition (presence of single X-chromosome “X^W+Y”) of the males. Females required both the mutated alleles to express the phenotype (white eye color), while males needed only one mutated allele to show the phenotype. The probability to inherit both mutated copies is less.

Hence, four genotypes of F₂ generation are as follows:

X^W+X^W+
X^W+X^W
X^W+Y
X^WY

The four phenotypes of F₂ generation are as follows:

Red-eyed female
Red-eyed female
Red-eyed male
White-eyed male.

Answer 8

Expert Solution & Answer

Summary Introduction

To complete: The summary of Morgan’s cross that involves the mutant white-eyed fly by filling in the Punnett square and by indicating the genotypes and phenotypes of the F₂ generation.

Introduction: Sex chromosomes are those chromosomes that play a crucial role in determination of sex of the individual. They have important function in the development of sexual characteristics in the organisms.

Answer to Problem 1IQ

Pictorial representation: Fig.1 represents the summary of Morgan’s cross that involves the mutant white-eyed fly by filling in the Punnett square and by indicating the genotypes and phenotypes of the F₂ generation.

Study Guide for Campbell Biology, Chapter 15, Problem 1IQ

Fig.1: Morgan’s cross of mutant white-eyed fly with the genotypes and phenotypes of the F₂ generation

Explanation of Solution

The X and Y chromosomes act as sex chromosomes in most of the organisms. The genes that are present on the sex chromosome are called sex-linked genes. There are approximately 1,100 X-linked genes. On the other hand, Y chromosome contains relatively very few genes.

The sex-linked genes display a unique pattern of inheritance. The expression of recessive X-linked trait requires two copies of alleles in females (homozygous) and only one copy of the allele in males (hemizygous). The probability of a male to receive a single mutated X-linked gene from their mother is high as compared to a female receiving both the X-linked mutated genes from the mother (carrier) and father (carrier).

When Morgan crossed red-eyed female (wild-type) with white-eyed male (mutant), all the offspring were red-eyed in the first generation (F₁). Then, he again crossed the F₁red-eyed female to the red-eyed male of F₁. The typical ratio of 3:1 (red-eyed flies: white eyed flies) was observed in the F₂ generation, but all white-eyed flies were males.

Morgan concluded that this could be due to hemizygous condition (presence of single X-chromosome “X^W+Y”) of the males. Females required both the mutated alleles to express the phenotype (white eye color), while males needed only one mutated allele to show the phenotype. The probability to inherit both mutated copies is less.

Hence, four genotypes of F₂ generation are as follows:

X^W+X^W+
X^W+X^W
X^W+Y
X^WY

The four phenotypes of F₂ generation are as follows:

Red-eyed female
Red-eyed female
Red-eyed male
White-eyed male.

Answer 9

Expert Solution & Answer

Answer 10

Expert Solution & Answer

Answer 11

Summary Introduction

To complete: The summary of Morgan’s cross that involves the mutant white-eyed fly by filling in the Punnett square and by indicating the genotypes and phenotypes of the F₂ generation.

Introduction: Sex chromosomes are those chromosomes that play a crucial role in determination of sex of the individual. They have important function in the development of sexual characteristics in the organisms.

Answer 12

Answer to Problem 1IQ

Pictorial representation: Fig.1 represents the summary of Morgan’s cross that involves the mutant white-eyed fly by filling in the Punnett square and by indicating the genotypes and phenotypes of the F₂ generation.

Study Guide for Campbell Biology, Chapter 15, Problem 1IQ

Fig.1: Morgan’s cross of mutant white-eyed fly with the genotypes and phenotypes of the F₂ generation

Answer 13

Explanation of Solution

The X and Y chromosomes act as sex chromosomes in most of the organisms. The genes that are present on the sex chromosome are called sex-linked genes. There are approximately 1,100 X-linked genes. On the other hand, Y chromosome contains relatively very few genes.

The sex-linked genes display a unique pattern of inheritance. The expression of recessive X-linked trait requires two copies of alleles in females (homozygous) and only one copy of the allele in males (hemizygous). The probability of a male to receive a single mutated X-linked gene from their mother is high as compared to a female receiving both the X-linked mutated genes from the mother (carrier) and father (carrier).

When Morgan crossed red-eyed female (wild-type) with white-eyed male (mutant), all the offspring were red-eyed in the first generation (F₁). Then, he again crossed the F₁red-eyed female to the red-eyed male of F₁. The typical ratio of 3:1 (red-eyed flies: white eyed flies) was observed in the F₂ generation, but all white-eyed flies were males.

Morgan concluded that this could be due to hemizygous condition (presence of single X-chromosome “X^W+Y”) of the males. Females required both the mutated alleles to express the phenotype (white eye color), while males needed only one mutated allele to show the phenotype. The probability to inherit both mutated copies is less.

Hence, four genotypes of F₂ generation are as follows: