Introduction to General, Organic and Biochemistry
12th Edition
ISBN: 9780357391594
Author: Frederick A. Bettelheim; William H. Brown; Mary K. Campbell
Publisher: Cengage Learning US
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Question
Chapter 15, Problem 15P
Interpretation Introduction
Interpretation:
The reason for the fact that low molecular weight
Concept introduction:
Hydrogen bonding is one of the non-covalent attractions between the molecules. This is the bonding between the hydrogen atom of one molecule and electronegative atom of the other molecule. Hydrogen bond is represented with dashed lines.
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In the video, we looked at the absorbance of a certain substance and how it varies
depending on what wavelength of light we are looking at. Below is a similar scan of a
different substance. What color BEST describes how this substance will appear?
Absorbance (AU)
Violet
Blue
Green
Orange
1.2
1.0-
0.8-
0.6-
0.4-
0.2
0.0
450
500
550
600
650
700
Wavelength (nm)
violet
indigo
blue
green
yellow orange
red
Red
O Cannot tell from this information
In the above graph, what causes -450 nm wavelength of light to have a higher
absorbance than light with a -550 nm wavelength? Check all that are true.
The distance the light travels is different
The different data points are for different substances
The concentration is different at different times in the experiment
Epsilon (molar absortivity) is different at different wavelengths
5. a. Data were collected for Trial 1 to determine the molar mass of a nonvolatile solid solute when dissolved in cyclo-
hexane. Complete the table for the analysis (See Report Sheet). Record calculated values with the correct number
of significant figures.
B. Freezing Point of Cyclohexane plus
Calculation Zone
Unknown Solute
2. Mass of cyclohexane (g)
10.14
Part C.4
3. Mass of added solute (g)
0.255
C. Calculations
1. k; for cyclohexane (°C⚫ kg/mol)
20.0
2. Freezing point change, AT, (°C)
3.04
Part C.6
3. Mass of cyclohexane in solution (kg)
4. Moles of solute, total (mol)
Show calculation.
5. Mass of solute in solution, total (g)
6. Molar mass of solute (g/mol)
Show calculation.
Chapter 15 Solutions
Introduction to General, Organic and Biochemistry
Ch. 15.1 - Prob. 15.1QCCh. 15.2 - Problem 16-2 Write a structural formula for each...Ch. 15.2 - Prob. 15.3QCCh. 15.3 - Problem 16-4 Select the stronger base from each...Ch. 15.3 - Prob. 15.5QCCh. 15 - 16-6 Answer true or false. te/7-Butylamine is a 3°...Ch. 15 - Prob. 2PCh. 15 - Prob. 3PCh. 15 - 16-9 In what way are pyridine and pyrimidine...Ch. 15 - Prob. 5P
Ch. 15 - Prob. 6PCh. 15 - Prob. 7PCh. 15 - 16-13 Classify each amino group as primary,...Ch. 15 - Prob. 9PCh. 15 - 16-15 There are eight primary amines with the...Ch. 15 - Prob. 11PCh. 15 - 16-17 Propylamine (bp 48°C), ethylmethylamine (bp...Ch. 15 - 16-18 Account for the fact that 1-butanamine (bp...Ch. 15 - 16-19 2-Me thy 1 propane (bp -12°C), 2-propanol...Ch. 15 - Prob. 15PCh. 15 - Prob. 16PCh. 15 - Prob. 17PCh. 15 - Prob. 18PCh. 15 - Prob. 19PCh. 15 - Prob. 20PCh. 15 - 16-26 The p/fb of amphetamine is approximately 3.2...Ch. 15 - 16-27 Guanidine, p/Ca 13.6, is a very strong base,...Ch. 15 - 16-28 Following is the structural formula of...Ch. 15 - Prob. 24PCh. 15 - Prob. 25PCh. 15 - Prob. 26PCh. 15 - 16*32 Many tumors of the breast are correlated...Ch. 15 - Prob. 28PCh. 15 - Prob. 29PCh. 15 - Prob. 30PCh. 15 - (Chemical Connections 15B ) Identify all...Ch. 15 - Prob. 32PCh. 15 - Prob. 33PCh. 15 - Prob. 34PCh. 15 - Prob. 35PCh. 15 - Prob. 36PCh. 15 - (Chemical Connections 15D ) Suppose you saw this...Ch. 15 - Prob. 38PCh. 15 - Prob. 39PCh. 15 - Prob. 40PCh. 15 - 16-46 Arrange these three compounds in order of...Ch. 15 - Prob. 42PCh. 15 - Prob. 43PCh. 15 - Prob. 44PCh. 15 - Prob. 45PCh. 15 - Prob. 46PCh. 15 - Prob. 47PCh. 15 - Prob. 48PCh. 15 - 16-54 Several poisonous plants, including Atropa...Ch. 15 - Prob. 50PCh. 15 - Prob. 51PCh. 15 - Prob. 52PCh. 15 - 16-58 Following is a structural formula of...Ch. 15 - Prob. 54P
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- Draw and name the R groups of all 20 amino acids.arrow_forward3. Two solutions are prepared using the same solute: Solution A: 0.14 g of the solute dissolves in 15.4 g of t-butanol Solution B: 0.17 g of the solute dissolves in 12.7 g of cyclohexane Which solution has the greatest freezing point change? Show calculations and explain.arrow_forward2. Give the ground state electron configuration (e.g., 02s² σ*2s² П 2p²) for these molecules and deduce its bond order. Ground State Configuration Bond Order H2+ 02- N2arrow_forward
- 1. This experiment is more about understanding the colligative properties of a solution rather than the determination of the molar mass of a solid. a. Define colligative properties. b. Which of the following solutes has the greatest effect on the colligative properties for a given mass of pure water? Explain. (i) 0.01 mol of CaCl2 (ii) 0.01 mol of KNO3 (iii) 0.01 mol of CO(NH2)2 (an electrolyte) (an electrolyte) (a nonelectrolyte)arrow_forward5. b. For Trials 2 and 3, the molar mass of the solute was 151 g/mol and 143 g/mol respectively. a. What is the average molar mass of the solute ? b. What are the standard deviation and the relative standard deviation (%RSD) for the molar mass of the solute ?arrow_forwardShow work. Don't give Ai generated solutionarrow_forward
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