Basic Chemistry (5th Edition)
5th Edition
ISBN: 9780134138046
Author: Karen C. Timberlake
Publisher: PEARSON
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Chapter 15, Problem 15.76CQ
Interpretation Introduction
(a)
Interpretation:
Determine the oxidation number of Cr in CrO
Concept Introduction:
The rules for assigning oxidation number to elements are:
- For an element in its free state it is assigned an oxidation number of zero.
- Monatomic ions have oxidation number that is equal to charge of the monatomic ion.
- Alkali metals have +1 oxidation number, alkaline earth metals have +2 oxidation number and halogens are assigned -1 oxidation number.
- In most compounds H is assigned a +1 oxidation number and O is assigned a -2 oxidation number.
- For a neutral compound the summation of oxidation numbers of all elements in the compound is zero.
Interpretation Introduction
(b)
Interpretation:
Determine the oxidation number of Cr in HCrO4-
Concept Introduction:
The rules for assigning oxidation number to elements are:
- For an element in its free state it is assigned an oxidation number of zero.
- Monatomic ions have oxidation number that is equal to charge of the monatomic ion.
- Alkali metals have +1 oxidation number, alkaline earth metals have +2 oxidation number and halogens are assigned -1 oxidation number.
- In most compounds H is assigned a +1 oxidation number and O is assigned a -2 oxidation number.
- For a neutral compound the summation of oxidation numbers of all elements in the compound is zero.
Interpretation Introduction
(c)
Interpretation:
Determine the oxidation number of Cr in CrO3-
Concept Introduction:
The rules for assigning oxidation number to elements are:
- For an element in its free state it is assigned an oxidation number of zero.
- Monatomic ions have oxidation number that is equal to charge of the monatomic ion.
- Alkali metals have +1 oxidation number, alkaline earth metals have +2 oxidation number and halogens are assigned -1 oxidation number.
- In most compounds H is assigned a +1 oxidation number and O is assigned a -2 oxidation number.
- For a neutral compound the summation of oxidation numbers of all elements in the compound is zero.
Interpretation Introduction
(d)
Interpretation:
Determine the oxidation number of Cr in CrF4
Concept Introduction:
The rules for assigning oxidation number to elements are:
- For an element in its free state it is assigned an oxidation number of zero.
- Monatomic ions have oxidation number that is equal to charge of the monatomic ion.
- Alkali metals have +1 oxidation number, alkaline earth metals have +2 oxidation number and halogens are assigned -1 oxidation number.
- In most compounds H is assigned a +1 oxidation number and O is assigned a -2 oxidation number.
- For a neutral compound the summation of oxidation numbers of all elements in the compound is zero.
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Identify and provide an explanation of the operational principles behind a Atomic Absorption Spectrometer (AAS). List the steps involved.
Instructions: Complete the questions in the space provided. Show all your work
1. You are trying to determine the rate law expression for a reaction that you are completing at 25°C. You measure
the initial reaction rate and the starting concentrations of the reactions for 4 trials.
BrO³¯ (aq) + 5Br¯ (aq) + 6H* (aq) → 3Br₂ (l) + 3H2O (l)
Initial rate
Trial
[BrO3]
[H*]
[Br]
(mol/L)
(mol/L) | (mol/L)
(mol/L.s)
1
0.10
0.10
0.10
8.0
2
0.20
0.10
0.10
16
3
0.10
0.20
0.10
16
4
0.10
0.10
0.20
32
a.
Based on the above data what is the rate law expression?
b. Solve for the value of k (make sure to include proper units)
2. The proposed reaction mechanism is as follows:
i.
ii.
BrО¸¯ (aq) + H+ (aq) → HBrO3 (aq)
HBrO³ (aq) + H* (aq) → H₂BrO3* (aq)
iii.
H₂BrO³* (aq) + Br¯ (aq) → Br₂O₂ (aq) + H2O (l)
[Fast]
[Medium]
[Slow]
iv.
Br₂O₂ (aq) + 4H*(aq) + 4Br(aq) → 3Br₂ (l) + H2O (l)
[Fast]
Evaluate the validity of this proposed reaction. Justify your answer.
е.
Д
CH3
D*, D20
Chapter 15 Solutions
Basic Chemistry (5th Edition)
Ch. 15.1 - Prob. 15.1QAPCh. 15.1 - Prob. 15.2QAPCh. 15.1 - Prob. 15.3QAPCh. 15.1 - Prob. 15.4QAPCh. 15.1 - Prob. 15.5QAPCh. 15.1 - Prob. 15.6QAPCh. 15.1 - Prob. 15.7QAPCh. 15.1 - Prob. 15.8QAPCh. 15.1 - Prob. 15.9QAPCh. 15.1 - Prob. 15.10QAP
Ch. 15.1 - Prob. 15.11QAPCh. 15.1 - Prob. 15.12QAPCh. 15.1 - Prob. 15.13QAPCh. 15.1 - Prob. 15.14QAPCh. 15.1 - Prob. 15.15QAPCh. 15.1 - Prob. 15.16QAPCh. 15.1 - Prob. 15.17QAPCh. 15.1 - Prob. 15.18QAPCh. 15.1 - Prob. 15.19QAPCh. 15.1 - Prob. 15.20QAPCh. 15.2 - Prob. 15.21QAPCh. 15.2 - Prob. 15.22QAPCh. 15.2 - Use the half-reaction method to balance each of...Ch. 15.2 - Prob. 15.24QAPCh. 15.2 - Use the halt-reaction method to balance each of...Ch. 15.2 - Prob. 15.26QAPCh. 15.3 - Prob. 15.27QAPCh. 15.3 - Prob. 15.28QAPCh. 15.3 - Prob. 15.29QAPCh. 15.3 - Prob. 15.30QAPCh. 15.3 - Prob. 15.31QAPCh. 15.3 - Prob. 15.32QAPCh. 15.3 - Prob. 15.33QAPCh. 15.3 - Prob. 15.34QAPCh. 15.3 - Prob. 15.35QAPCh. 15.3 - Prob. 15.36QAPCh. 15.4 - Prob. 15.37QAPCh. 15.4 - Prob. 15.38QAPCh. 15.4 - Prob. 15.39QAPCh. 15.4 - Prob. 15.40QAPCh. 15 - Prob. 15.41FUCh. 15 - Prob. 15.42FUCh. 15 - Prob. 15.43UTCCh. 15 - Prob. 15.44UTCCh. 15 - Prob. 15.45UTCCh. 15 - Prob. 15.46UTCCh. 15 - Prob. 15.47UTCCh. 15 - Prob. 15.48UTCCh. 15 - Prob. 15.49AUTCCh. 15 - Prob. 15.50AUTCCh. 15 - Prob. 15.51AUTCCh. 15 - Prob. 15.52AUTCCh. 15 - Prob. 15.53AUTCCh. 15 - Prob. 15.54AUTCCh. 15 - Which of the following are notation-reduction...Ch. 15 - Prob. 15.56AQAPCh. 15 - Prob. 15.57AQAPCh. 15 - Prob. 15.58AQAPCh. 15 - 15.59 Assign oxidation numbers to all the elements...Ch. 15 - Prob. 15.60AQAPCh. 15 - Assign oxidation numbers to all the elements in...Ch. 15 - Assign oxidation numbers to all the elements in...Ch. 15 - Prob. 15.63AQAPCh. 15 - Prob. 15.64AQAPCh. 15 - 15.65 Use the activity series in Table 15.3 to...Ch. 15 - Prob. 15.66AQAPCh. 15 - Prob. 15.67AQAPCh. 15 - In a voltaic cell, one half-cell consists of zinc...Ch. 15 - Prob. 15.69AQAPCh. 15 - 15.70 Use the activity series in Table 15.3 to...Ch. 15 - 15.71 In a lead storage battery. the following...Ch. 15 - Prob. 15.72AQAPCh. 15 - Prob. 15.73AQAPCh. 15 - Prob. 15.74AQAPCh. 15 - Prob. 15.75CQCh. 15 - Prob. 15.76CQCh. 15 - Prob. 15.77CQCh. 15 - Prob. 15.78CQCh. 15 - Prob. 15.79CQCh. 15 - Prob. 15.80CQCh. 15 - Prob. 15.81CQCh. 15 - The following unbalanced reaction takes place in...Ch. 15 - Prob. 15.83CQCh. 15 - Prob. 15.84CQCh. 15 - Using the activity series in Table 15.3, indicate...Ch. 15 - Using the activity series in Table 15.3, indicate...Ch. 15 - Prob. 15.87CQCh. 15 - Prob. 15.88CQ
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