Basic Chemistry (5th Edition)
5th Edition
ISBN: 9780134138046
Author: Karen C. Timberlake
Publisher: PEARSON
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Chapter 15, Problem 15.45UTC
Interpretation Introduction
(a)
Interpretation:
To assign the oxidation number for each of the elements present in the given compound.
Concept Introduction:
Oxidation number or oxidation state of an atom in a molecule is the positive or the negative charge that an atom would have possessed if the compound would have been ionic. There are many rules for assigning the oxidation state to the given atom in a molecule. Some of them are:
- The oxidation state of Group 1 elements is taken to be +1.
- The oxidation state of Group 2 elements is taken to be +2.
- The oxidation state of oxygen is always -2 in most of the compounds except peroxides.
- Oxidation state of halogens is taken to be -1 usually.
- The oxidation state of hydrogen is taken to be -1 when bonded to metals and +1 when bonded to non-metals.
- Any element when present in its elemental form has zero oxidation state.
- The oxidation state of Fluorine is taken to be -1 except when present in elemental state (F2).
- The sum of oxidation states of all the atoms present in a given molecule is equal to zero.
- In case of ions, the sum of oxidation state is equal to the total charge carried by the polyatomic ion.
Interpretation Introduction
(b)
Interpretation:
To assign the oxidation number for each of the elements present in the given compound.
Concept Introduction:
Oxidation number or oxidation state of an atom in a molecule is the positive or the negative charge that an atom would have possessed if the compound would have been ionic. There are many rules for assigning the oxidation state to the given atom in a molecule. Some of them are :
- The oxidation state of Group 1 elements is taken to be +1.
- The oxidation state of Group 2 elements is taken to be +2.
- The oxidation state of oxygen is always -2 in most of the compounds except peroxides.
- Oxidation state of halogens is taken to be -1 usually.
- The oxidation state of hydrogen is taken to be -1 when bonded to metals and +1 when bonded to non-metals.
- Any element when present in its elemental form has zero oxidation state.
- The oxidation state of Fluorine is taken to be -1 except when present in elemental state (F2).
- The sum of oxidation states of all the atoms present in a given molecule is equal to zero.
- In case of ions, the sum of oxidation state is equal to the total charge carried by the polyatomic ion
Interpretation Introduction
(c)
Interpretation:
To assign the oxidation number for each of the elements present in the given compound.
Concept Introduction:
Oxidation number or oxidation state of an atom in a molecule is the positive or the negative charge that an atom would have possessed if the compound would have been ionic. There are many rules for assigning the oxidation state to the given atom in a molecule. Some of them are :
- The oxidation state of Group 1 elements is taken to be +1.
- The oxidation state of Group 2 elements is taken to be +2.
- The oxidation state of oxygen is always -2 in most of the compounds except peroxides.
- Oxidation state of halogens is taken to be -1 usually.
- The oxidation state of hydrogen is taken to be -1 when bonded to metals and +1 when bonded to non-metals.
- Any element when present in its elemental form has zero oxidation state.
- The oxidation state of Fluorine is taken to be -1 except when present in elemental state (F2).
- The sum of oxidation states of all the atoms present in a given molecule is equal to zero.
- In case of ions, the sum of oxidation state is equal to the total charge carried by the polyatomic ion
Interpretation Introduction
(d)
Interpretation:
To assign the oxidation number for each of the elements present in the given compound.
Concept Introduction:
Oxidation number or oxidation state of an atom in a molecule is the positive or the negative charge that an atom would have possessed if the compound would have been ionic. There are many rules for assigning the oxidation state to the given atom in a molecule. Some of them are :
- The oxidation state of Group 1 elements is taken to be +1.
- The oxidation state of Group 2 elements is taken to be +2.
- The oxidation state of oxygen is always -2 in most of the compounds except peroxides.
- Oxidation state of halogens is taken to be -1 usually.
- The oxidation state of hydrogen is taken to be -1 when bonded to metals and +1 when bonded to non-metals.
- Any element when present in its elemental form has zero oxidation state.
- The oxidation state of Fluorine is taken to be -1 except when present in elemental state (F2).
- The sum of oxidation states of all the atoms present in a given molecule is equal to zero.
- In case of ions, the sum of oxidation state is equal to the total charge carried by the polyatomic ion
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A covalent bond is the result of the
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Can the target compound at right be efficiently synthesized in good yield from the unsubstituted benzene at left?
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If so, draw a synthesis below. If no synthesis using reagents ALEKS recognizes is possible, check the box under the drawing area.
Be sure you follow the standard ALEKS rules for submitting syntheses.
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Note for advanced students: you may assume that you are using a large excess of benzene as your starting material.
C
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X
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Which one of the following atoms should have the largest electron affinity?
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b)
c)
d)
으으
e)
1s² 2s² 2p6 3s¹
1s² 2s² 2p5
1s² 2s² 2p 3s² 3p²
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Chapter 15 Solutions
Basic Chemistry (5th Edition)
Ch. 15.1 - Prob. 15.1QAPCh. 15.1 - Prob. 15.2QAPCh. 15.1 - Prob. 15.3QAPCh. 15.1 - Prob. 15.4QAPCh. 15.1 - Prob. 15.5QAPCh. 15.1 - Prob. 15.6QAPCh. 15.1 - Prob. 15.7QAPCh. 15.1 - Prob. 15.8QAPCh. 15.1 - Prob. 15.9QAPCh. 15.1 - Prob. 15.10QAP
Ch. 15.1 - Prob. 15.11QAPCh. 15.1 - Prob. 15.12QAPCh. 15.1 - Prob. 15.13QAPCh. 15.1 - Prob. 15.14QAPCh. 15.1 - Prob. 15.15QAPCh. 15.1 - Prob. 15.16QAPCh. 15.1 - Prob. 15.17QAPCh. 15.1 - Prob. 15.18QAPCh. 15.1 - Prob. 15.19QAPCh. 15.1 - Prob. 15.20QAPCh. 15.2 - Prob. 15.21QAPCh. 15.2 - Prob. 15.22QAPCh. 15.2 - Use the half-reaction method to balance each of...Ch. 15.2 - Prob. 15.24QAPCh. 15.2 - Use the halt-reaction method to balance each of...Ch. 15.2 - Prob. 15.26QAPCh. 15.3 - Prob. 15.27QAPCh. 15.3 - Prob. 15.28QAPCh. 15.3 - Prob. 15.29QAPCh. 15.3 - Prob. 15.30QAPCh. 15.3 - Prob. 15.31QAPCh. 15.3 - Prob. 15.32QAPCh. 15.3 - Prob. 15.33QAPCh. 15.3 - Prob. 15.34QAPCh. 15.3 - Prob. 15.35QAPCh. 15.3 - Prob. 15.36QAPCh. 15.4 - Prob. 15.37QAPCh. 15.4 - Prob. 15.38QAPCh. 15.4 - Prob. 15.39QAPCh. 15.4 - Prob. 15.40QAPCh. 15 - Prob. 15.41FUCh. 15 - Prob. 15.42FUCh. 15 - Prob. 15.43UTCCh. 15 - Prob. 15.44UTCCh. 15 - Prob. 15.45UTCCh. 15 - Prob. 15.46UTCCh. 15 - Prob. 15.47UTCCh. 15 - Prob. 15.48UTCCh. 15 - Prob. 15.49AUTCCh. 15 - Prob. 15.50AUTCCh. 15 - Prob. 15.51AUTCCh. 15 - Prob. 15.52AUTCCh. 15 - Prob. 15.53AUTCCh. 15 - Prob. 15.54AUTCCh. 15 - Which of the following are notation-reduction...Ch. 15 - Prob. 15.56AQAPCh. 15 - Prob. 15.57AQAPCh. 15 - Prob. 15.58AQAPCh. 15 - 15.59 Assign oxidation numbers to all the elements...Ch. 15 - Prob. 15.60AQAPCh. 15 - Assign oxidation numbers to all the elements in...Ch. 15 - Assign oxidation numbers to all the elements in...Ch. 15 - Prob. 15.63AQAPCh. 15 - Prob. 15.64AQAPCh. 15 - 15.65 Use the activity series in Table 15.3 to...Ch. 15 - Prob. 15.66AQAPCh. 15 - Prob. 15.67AQAPCh. 15 - In a voltaic cell, one half-cell consists of zinc...Ch. 15 - Prob. 15.69AQAPCh. 15 - 15.70 Use the activity series in Table 15.3 to...Ch. 15 - 15.71 In a lead storage battery. the following...Ch. 15 - Prob. 15.72AQAPCh. 15 - Prob. 15.73AQAPCh. 15 - Prob. 15.74AQAPCh. 15 - Prob. 15.75CQCh. 15 - Prob. 15.76CQCh. 15 - Prob. 15.77CQCh. 15 - Prob. 15.78CQCh. 15 - Prob. 15.79CQCh. 15 - Prob. 15.80CQCh. 15 - Prob. 15.81CQCh. 15 - The following unbalanced reaction takes place in...Ch. 15 - Prob. 15.83CQCh. 15 - Prob. 15.84CQCh. 15 - Using the activity series in Table 15.3, indicate...Ch. 15 - Using the activity series in Table 15.3, indicate...Ch. 15 - Prob. 15.87CQCh. 15 - Prob. 15.88CQ
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- All of the following are allowed energy levels except _. a) 3f b) 1s c) 3d d) 5p e) 6sarrow_forwardA student wants to make the following product in good yield from a single transformation step, starting from benzene. Add any organic reagents the student is missing on the left-hand side of the arrow, and any addition reagents that are necessary above or below the arrow. If this product can't be made in good yield with a single transformation step, check the box below the drawing area. Note for advanced students: you may assume that an excess of benzene is used as part of the reaction conditions. : ☐ + I X This product can't be made in a single transformation step.arrow_forwardPredict the major products of this organic reaction:arrow_forward
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