EBK GENERAL, ORGANIC, & BIOLOGICAL CHEM
3rd Edition
ISBN: 9781259298424
Author: SMITH
Publisher: VST
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Question
Chapter 15, Problem 15.62P
Interpretation Introduction
(a)
Interpretation:
The specific rotation of the enantiomer of lactose should be determined.
Concept Introduction:
Chiral or optically active molecules can rotate plane-polarized light either clockwise or counter clockwise. If plane-polarized light is rotated clockwise then it is known as dextrorotatory and for counter clockwise rotation it is known as levorotatory.
Interpretation Introduction
(b)
Interpretation:
Boiling point comparison should be done for enantiomers of Taxol.
Concept Introduction:
Physical properties of enantiomers are similar except the direction of optical activity. Solubility, melting point, boiling points are similar in enantiomers.
Interpretation Introduction
(c)
Interpretation:
The solubility of Taxol needs to be compared to its enantiomer.
Concept Introduction:
Physical properties of enantiomers are similar except the direction of optical activity. Solubility, melting point, boiling points are similar in enantiomers.
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0
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Ethyl paraben n-Propyl paraben
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App ID 22925
6
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min
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and retention factor. In other words, as k' increases, N decreases. Explain this relationship
between k' and N.
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4000
3500
2500
2000
1500
1000
Figure 4. Column efficiency (N) vs retention factor (k') for 22
nonionizable solutes on FMS (red), PGC (black), and COZ (green). 3000
Eluent compositions (acetonitrile/water, A/W) were adjusted to obtain
k' less than 15, which was achieved for most solutes as follows: FMS
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compositions were used for the most highly retained solutes. All
columns were 50 mm × 4.6 mm id and packed with 5 um particles,
except for COZ, which was packed with 3 um particles. All other
chromatographic conditions were constant: column length 5 cm,
column j.§. 4.6 mm, flow rate 2 mL/min, column temperature 40 °C,
and injection volume 0.5 μL
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0.0
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Chapter 15 Solutions
EBK GENERAL, ORGANIC, & BIOLOGICAL CHEM
Ch. 15.1 - Prob. 15.1PCh. 15.1 - For trans-2-hexene: (a) draw a stereoisomer; (b)...Ch. 15.2 - Prob. 15.3PCh. 15.2 - Prob. 15.4PCh. 15.3 - Prob. 15.5PCh. 15.3 - Prob. 15.6PCh. 15.3 - Prob. 15.7PCh. 15.3 - Prob. 15.8PCh. 15.3 - Prob. 15.9PCh. 15.3 - Prob. 15.10P
Ch. 15.3 - Prob. 15.11PCh. 15.4 - Prob. 15.12PCh. 15.4 - Prob. 15.13PCh. 15.5 - Prob. 15.14PCh. 15.6 - Prob. 15.15PCh. 15.6 - Prob. 15.16PCh. 15.6 - Prob. 15.17PCh. 15.7 - Prob. 15.18PCh. 15.7 - Prob. 15.19PCh. 15.7 - Prob. 15.20PCh. 15.7 - Prob. 15.21PCh. 15.8 - Prob. 15.22PCh. 15.8 - Prob. 15.23PCh. 15.9 - Prob. 15.24PCh. 15 - Prob. 15.25PCh. 15 - Prob. 15.26PCh. 15 - Prob. 15.27PCh. 15 - Prob. 15.28PCh. 15 - Prob. 15.29PCh. 15 - Prob. 15.30PCh. 15 - Prob. 15.31PCh. 15 - Prob. 15.32PCh. 15 - Prob. 15.33PCh. 15 - Prob. 15.34PCh. 15 - Prob. 15.35PCh. 15 - Prob. 15.36PCh. 15 - Prob. 15.37PCh. 15 - Prob. 15.38PCh. 15 - Prob. 15.39PCh. 15 - Prob. 15.40PCh. 15 - How are the compounds in each pair related? Are...Ch. 15 - Prob. 15.42PCh. 15 - Prob. 15.43PCh. 15 - Prob. 15.44PCh. 15 - Answer each question with a compound of molecular...Ch. 15 - Prob. 15.46PCh. 15 - Prob. 15.47PCh. 15 - Prob. 15.48PCh. 15 - Prob. 15.49PCh. 15 - Prob. 15.50PCh. 15 - Prob. 15.51PCh. 15 - Prob. 15.52PCh. 15 - Prob. 15.53PCh. 15 - Prob. 15.54PCh. 15 - Prob. 15.55PCh. 15 - Prob. 15.56PCh. 15 - (a) Define the terms “optically active” and...Ch. 15 - Prob. 15.58PCh. 15 - Prob. 15.59PCh. 15 - Prob. 15.60PCh. 15 - Prob. 15.61PCh. 15 - Prob. 15.62PCh. 15 - Prob. 15.63PCh. 15 - Prob. 15.64PCh. 15 - Prob. 15.65PCh. 15 - Prob. 15.66PCh. 15 - Prob. 15.67PCh. 15 - Prob. 15.68PCh. 15 - Prob. 15.69PCh. 15 - Prob. 15.70PCh. 15 - Prob. 15.71PCh. 15 - Prob. 15.72PCh. 15 - Prob. 15.73CPCh. 15 - Prob. 15.74CP
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