Introduction to Chemical Engineering Thermodynamics
8th Edition
ISBN: 9781259696527
Author: J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Publisher: McGraw-Hill Education
expand_more
expand_more
format_list_bulleted
Concept explainers
Question
Chapter 15, Problem 15.21P
Interpretation Introduction
Interpretation:
To what extent can the features be represented by the two-term virial equation should be determined.
Concept introduction:
The two term virial equation is given as
Find a general expression using the below,
Expert Solution & Answer
Want to see the full answer?
Check out a sample textbook solution
Students have asked these similar questions
give me solution math not explin
Example (6):
An evaporator is concentrating F kg/h at
311K of a 20wt% solution of NaOH to 50wt
%. The saturated steam used for heating is
at 399.3K. The pressure in the vapor space
of the evaporator is 13.3 KPa abs. The
5:48
O
Transcribed Image Text: Example (7): Determine the
14.9. A forward feed double-effect vertical
evaporator, with equal heating areas in
each effect, is fed with 5 kg/s of a liquor
of specific heat capacity of 4.18 kJ/kg K.
and with no boiling point rise, so that 50
per cent of the feed liquor is evaporated.
The overall heat transfer coefficient in the
second effect is 75 per cent of that in the
first effect. Steam is fed at 395 K and the
boiling point in the second effect is 373 K.
The feed is heated by an external heater to
the boiling point in the first effect.
It is decided to bleed off 0.25 kg/s of
vapour from the vapour line to the second
effect for use in another process. If the
feed is still heated to the boiling point of
the first effect by external means, what
will be the change in steam consumption
of the evaporator unit? For the purpose of
calculation, the latent heat of the vapours
and of the steam may both be taken as
2230 kJ/kg
Chapter 15 Solutions
Introduction to Chemical Engineering Thermodynamics
Ch. 15 - Prob. 15.1PCh. 15 - Prob. 15.2PCh. 15 - Work Prob. 15.2 for the van Laar equation. 15.2. A...Ch. 15 - Consider a binary vapor-phase mixture described by...Ch. 15 - Prob. 15.5PCh. 15 - It has been suggested that a value for GEof at...Ch. 15 - Pure liquid species 2 and 3 are for practical...Ch. 15 - It is demonstrated in Ex. 15.5 that the Wilson...Ch. 15 - Vapor sulfur hexafluoride SF6 at pressures of...Ch. 15 - Prob. 15.10P
Ch. 15 - Toluene(l) and water (2) are essentially...Ch. 15 - n-Heptane(l) and water (2) are essentially...Ch. 15 - Consider a binary system of species 1 and 2 in...Ch. 15 - Prob. 15.14PCh. 15 - 15.15. Work the preceding problem for mole...Ch. 15 - The Case I behavior for SLE (Sec. 15.4) has an...Ch. 15 - Prob. 15.17PCh. 15 - Prob. 15.18PCh. 15 - Prob. 15.19PCh. 15 - Estimate the solubility of naphthalene! 1) in...Ch. 15 - Prob. 15.21PCh. 15 - 15.22. The UNILAN equation for pure-species...Ch. 15 - In Ex. 15.8, Henry's constant for adsorption k,...Ch. 15 - It was assumed in the development of Eq. (15.39)...Ch. 15 - Suppose that the adsorbate equation of state is...Ch. 15 - Suppose that the adsorbate equation of state is...Ch. 15 - Derive the result given in the third step of the...Ch. 15 - Consider a ternary system comprising solute...Ch. 15 - It is possible in principle for a binary liquid...Ch. 15 - With V2=V2 , Eq.(15.66) for the osmotic pressure...Ch. 15 - A liquid-process feed stream F contains 99 mol-%...Ch. 15 - At 25°C the solubility of n-hexane in water is 2...Ch. 15 - A binary liquid mixture is only partially miscible...Ch. 15 - The spinodal curve for a binary liquid system is...Ch. 15 - Prob. 15.36PCh. 15 - Many fluids could be used as solvent species for...
Knowledge Booster
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, chemical-engineering and related others by exploring similar questions and additional content below.Similar questions
- Example(3): It is desired to design a double effect evaporator for concentrating a certain caustic soda solution from 12.5wt% to 40wt%. The feed at 50°C enters the first evaporator at a rate of 2500kg/h. Steam at atmospheric pressure is being used for the said purpose. The second effect is operated under 600mmHg vacuum. If the overall heat transfer coefficients of the two stages are 1952 and 1220kcal/ m2.h.°C. respectively, determine the heat transfer area of each effect. The BPR will be considered and present for the both effect 5:49arrow_forwardالعنوان ose only Q Example (7): Determine the heating surface area 개 required for the production of 2.5kg/s of 50wt% NaOH solution from 15 wt% NaOH feed solution which entering at 100 oC to a single effect evaporator. The steam is available as saturated at 451.5K and the boiling point rise (boiling point evaluation) of 50wt% solution is 35K. the overall heat transfer coefficient is 2000 w/m²K. The pressure in the vapor space of the evaporator at atmospheric pressure. The solution has a specific heat of 4.18kJ/ kg.K. The enthalpy of vaporization under these condition is 2257kJ/kg Example (6): 5:48 An evaporator is concentrating F kg/h at 311K of a 20wt% solution of NaOH to 50wt %. The saturated steam used for heating is at 399.3K. The pressure in the vapor space of the evaporator is 13.3 KPa abs. The 5:48 1 J ۲/۱ ostrarrow_forwardExample 8: 900 Kg dry solid per hour is dried in a counter current continues dryer from 0.4 to 0.04 Kg H20/Kg wet solid moisture content. The wet solid enters the dryer at 25 °C and leaves at 55 °C. Fresh air at 25 °C and 0.01Kg vapor/Kg dry air is mixed with a part of the moist air leaving the dryer and heated to a temperature of 130 °C in a finned air heater and enters the dryer with 0.025 Kg/Kg alry air. Air leaving the dryer at 85 °C and have a humidity 0.055 Kg vaper/Kg dry air. At equilibrium the wet solid weight is 908 Kg solid per hour. *=0.0088 Calculate:- Heat loss from the dryer and the rate of fresh air. Take the specific heat of the solid and moisture are 980 and 4.18J/Kg.K respectively, A. =2500 KJ/Kg. Humid heat at 0.01 Kg vap/Kg dry=1.0238 KJ/Kg. "C. Humid heat at 0.055 Kg/Kg 1.1084 KJ/Kg. "C 5:42 Oarrow_forward
- Q1: From the Figure below for (=0.2 find the following 1. Rise Time 2. Time of oscillation 3. Overshoot value 4. Maximum value 5. When 1.2 which case will be? 1.6 1.4 1.2 12 1.0 |=0.8- 0.6 0.4 0.8 0.2- 0.6 0.4 0.2 1.2 = 1.0 0 2 4 6 8 10 10 t/Tarrow_forwardPlease, I need solution in detailsarrow_forwardplease, I need solution in detailsarrow_forward
- please, I need solution in detailsarrow_forwardA system, in a closed container, consists of an unknown number of components and three phases. You are told that the system is fully defined by giving you only one mole fraction! What is the number components that is present? 3 1 2 The question is ill-posed.arrow_forwardA mixture of 2 components in 2 phases are present. You are given the temperature and mole fraction. How many additional variables can be specified before the system is completely determined? none 2 the system is overspecified 1 3arrow_forward
- At a Pressure of 600 mm Hg, match the substance with the boiling temperature. 54.69°C 1. n-Pentane 49.34°C 2. n-Hexane 3. Acetone 29.32°C く 61.40°C 4. Chloroformarrow_forwardA mixture of oil and gas flows through a horizontal pipe with an inside diameter of 150 mm. The respective volumetric flow rates for the oil and gas are 0.015 and 0.29 m³s-1. Determine the gas void frac- tion and the average velocities of the oil and gas. The friction factor may be assumed to be 0.0045. The gas has a density of 2.4 kgm³ and viscosity of 1 x 10-5 Nsm-2. The oil has a density of 810 kgm³ and density of 0.82 Nsm². Answer: 0.79, 20.8 ms-1, 4 ms-1arrow_forward4. An experimental test rig is used to examine two-phase flow regimes in horizontal pipelines. A particular experiment involved uses air and water at a temperature of 25°C, which flow through a horizontal glass tube with an internal diameter of 25.4 mm and a length of 40 m. Water is admitted at a controlled rate of 0.026 kgs at one end and air at a rate of 5 x 104 kgs in the same direction. The density of water is 1000 kgm³, and the density of air is 1.2 kgm3. Determine the mass flow rate, the mean density, gas void fraction, and the superficial velocities of the air and water. Answer: 0.02605 kgs 1, 61.1 kgm³, 0.94, 0.822 ms-1, 0.051 ms-1arrow_forward
arrow_back_ios
SEE MORE QUESTIONS
arrow_forward_ios
Recommended textbooks for you
Introduction to Chemical Engineering Thermodynami...Chemical EngineeringISBN:9781259696527Author:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark SwihartPublisher:McGraw-Hill Education
Elementary Principles of Chemical Processes, Bind...Chemical EngineeringISBN:9781118431221Author:Richard M. Felder, Ronald W. Rousseau, Lisa G. BullardPublisher:WILEY
Elements of Chemical Reaction Engineering (5th Ed...Chemical EngineeringISBN:9780133887518Author:H. Scott FoglerPublisher:Prentice Hall
Industrial Plastics: Theory and ApplicationsChemical EngineeringISBN:9781285061238Author:Lokensgard, ErikPublisher:Delmar Cengage Learning
Unit Operations of Chemical EngineeringChemical EngineeringISBN:9780072848236Author:Warren McCabe, Julian C. Smith, Peter HarriottPublisher:McGraw-Hill Companies, The
Introduction to Chemical Engineering Thermodynami...
Chemical Engineering
ISBN:9781259696527
Author:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Publisher:McGraw-Hill Education
Elementary Principles of Chemical Processes, Bind...
Chemical Engineering
ISBN:9781118431221
Author:Richard M. Felder, Ronald W. Rousseau, Lisa G. Bullard
Publisher:WILEY
Elements of Chemical Reaction Engineering (5th Ed...
Chemical Engineering
ISBN:9780133887518
Author:H. Scott Fogler
Publisher:Prentice Hall
Industrial Plastics: Theory and Applications
Chemical Engineering
ISBN:9781285061238
Author:Lokensgard, Erik
Publisher:Delmar Cengage Learning
Unit Operations of Chemical Engineering
Chemical Engineering
ISBN:9780072848236
Author:Warren McCabe, Julian C. Smith, Peter Harriott
Publisher:McGraw-Hill Companies, The