Introduction to Chemical Engineering Thermodynamics
8th Edition
ISBN: 9781259696527
Author: J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Publisher: McGraw-Hill Education
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Chapter 15, Problem 15.23P
In Ex. 15.8, Henry's constant for adsorption k, identified as the intercept on a plot of n/P vs. n, was found from a polynomial curve-fit of n/P vs. n. An alternative procedure is based on a plot of
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Chapter 15 Solutions
Introduction to Chemical Engineering Thermodynamics
Ch. 15 - Prob. 15.1PCh. 15 - Prob. 15.2PCh. 15 - Work Prob. 15.2 for the van Laar equation. 15.2. A...Ch. 15 - Consider a binary vapor-phase mixture described by...Ch. 15 - Prob. 15.5PCh. 15 - It has been suggested that a value for GEof at...Ch. 15 - Pure liquid species 2 and 3 are for practical...Ch. 15 - It is demonstrated in Ex. 15.5 that the Wilson...Ch. 15 - Vapor sulfur hexafluoride SF6 at pressures of...Ch. 15 - Prob. 15.10P
Ch. 15 - Toluene(l) and water (2) are essentially...Ch. 15 - n-Heptane(l) and water (2) are essentially...Ch. 15 - Consider a binary system of species 1 and 2 in...Ch. 15 - Prob. 15.14PCh. 15 - 15.15. Work the preceding problem for mole...Ch. 15 - The Case I behavior for SLE (Sec. 15.4) has an...Ch. 15 - Prob. 15.17PCh. 15 - Prob. 15.18PCh. 15 - Prob. 15.19PCh. 15 - Estimate the solubility of naphthalene! 1) in...Ch. 15 - Prob. 15.21PCh. 15 - 15.22. The UNILAN equation for pure-species...Ch. 15 - In Ex. 15.8, Henry's constant for adsorption k,...Ch. 15 - It was assumed in the development of Eq. (15.39)...Ch. 15 - Suppose that the adsorbate equation of state is...Ch. 15 - Suppose that the adsorbate equation of state is...Ch. 15 - Derive the result given in the third step of the...Ch. 15 - Consider a ternary system comprising solute...Ch. 15 - It is possible in principle for a binary liquid...Ch. 15 - With V2=V2 , Eq.(15.66) for the osmotic pressure...Ch. 15 - A liquid-process feed stream F contains 99 mol-%...Ch. 15 - At 25°C the solubility of n-hexane in water is 2...Ch. 15 - A binary liquid mixture is only partially miscible...Ch. 15 - The spinodal curve for a binary liquid system is...Ch. 15 - Prob. 15.36PCh. 15 - Many fluids could be used as solvent species for...
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- give me solution math not explinarrow_forwardExample (6): An evaporator is concentrating F kg/h at 311K of a 20wt% solution of NaOH to 50wt %. The saturated steam used for heating is at 399.3K. The pressure in the vapor space of the evaporator is 13.3 KPa abs. The 5:48 O Transcribed Image Text: Example (7): Determine thearrow_forward14.9. A forward feed double-effect vertical evaporator, with equal heating areas in each effect, is fed with 5 kg/s of a liquor of specific heat capacity of 4.18 kJ/kg K. and with no boiling point rise, so that 50 per cent of the feed liquor is evaporated. The overall heat transfer coefficient in the second effect is 75 per cent of that in the first effect. Steam is fed at 395 K and the boiling point in the second effect is 373 K. The feed is heated by an external heater to the boiling point in the first effect. It is decided to bleed off 0.25 kg/s of vapour from the vapour line to the second effect for use in another process. If the feed is still heated to the boiling point of the first effect by external means, what will be the change in steam consumption of the evaporator unit? For the purpose of calculation, the latent heat of the vapours and of the steam may both be taken as 2230 kJ/kgarrow_forward
- Example(3): It is desired to design a double effect evaporator for concentrating a certain caustic soda solution from 12.5wt% to 40wt%. The feed at 50°C enters the first evaporator at a rate of 2500kg/h. Steam at atmospheric pressure is being used for the said purpose. The second effect is operated under 600mmHg vacuum. If the overall heat transfer coefficients of the two stages are 1952 and 1220kcal/ m2.h.°C. respectively, determine the heat transfer area of each effect. The BPR will be considered and present for the both effect 5:49arrow_forwardالعنوان ose only Q Example (7): Determine the heating surface area 개 required for the production of 2.5kg/s of 50wt% NaOH solution from 15 wt% NaOH feed solution which entering at 100 oC to a single effect evaporator. The steam is available as saturated at 451.5K and the boiling point rise (boiling point evaluation) of 50wt% solution is 35K. the overall heat transfer coefficient is 2000 w/m²K. The pressure in the vapor space of the evaporator at atmospheric pressure. The solution has a specific heat of 4.18kJ/ kg.K. The enthalpy of vaporization under these condition is 2257kJ/kg Example (6): 5:48 An evaporator is concentrating F kg/h at 311K of a 20wt% solution of NaOH to 50wt %. The saturated steam used for heating is at 399.3K. The pressure in the vapor space of the evaporator is 13.3 KPa abs. The 5:48 1 J ۲/۱ ostrarrow_forwardExample 8: 900 Kg dry solid per hour is dried in a counter current continues dryer from 0.4 to 0.04 Kg H20/Kg wet solid moisture content. The wet solid enters the dryer at 25 °C and leaves at 55 °C. Fresh air at 25 °C and 0.01Kg vapor/Kg dry air is mixed with a part of the moist air leaving the dryer and heated to a temperature of 130 °C in a finned air heater and enters the dryer with 0.025 Kg/Kg alry air. Air leaving the dryer at 85 °C and have a humidity 0.055 Kg vaper/Kg dry air. At equilibrium the wet solid weight is 908 Kg solid per hour. *=0.0088 Calculate:- Heat loss from the dryer and the rate of fresh air. Take the specific heat of the solid and moisture are 980 and 4.18J/Kg.K respectively, A. =2500 KJ/Kg. Humid heat at 0.01 Kg vap/Kg dry=1.0238 KJ/Kg. "C. Humid heat at 0.055 Kg/Kg 1.1084 KJ/Kg. "C 5:42 Oarrow_forward
- Q1: From the Figure below for (=0.2 find the following 1. Rise Time 2. Time of oscillation 3. Overshoot value 4. Maximum value 5. When 1.2 which case will be? 1.6 1.4 1.2 12 1.0 |=0.8- 0.6 0.4 0.8 0.2- 0.6 0.4 0.2 1.2 = 1.0 0 2 4 6 8 10 10 t/Tarrow_forwardPlease, I need solution in detailsarrow_forwardplease, I need solution in detailsarrow_forward
- please, I need solution in detailsarrow_forwardA system, in a closed container, consists of an unknown number of components and three phases. You are told that the system is fully defined by giving you only one mole fraction! What is the number components that is present? 3 1 2 The question is ill-posed.arrow_forwardA mixture of 2 components in 2 phases are present. You are given the temperature and mole fraction. How many additional variables can be specified before the system is completely determined? none 2 the system is overspecified 1 3arrow_forward
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