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Concept explainers
(a)
Interpretation:
IUPAC name for the given
Concept Introduction:
For naming an aldehyde in
IUPAC rules for naming an aldehyde:
- • The longest parent carbon chain is identified that includes the carbonyl group.
- • The parent chain name is changed by replacing the suffix “-e” with “-al”.
- • Numbering is done in a way that the carbonyl group is designated as number 1. This is not indicated in the part of the name because for aldehyde, the carbonyl carbon is always numbered 1.
- • The identity and location of substituents if any has to be determined and this information has to be added in front of the IUPAC name.
- • If the carbonyl
functional group is attached to a ring of carbon atoms, the ring is named and “-carbaldehyde” is added as suffix.
(b)
Interpretation:
IUPAC name for the given aldehyde has to be assigned.
Concept Introduction:
For naming an aldehyde in IUPAC nomenclature, the suffix “-al” is added to the parent alkane name.
IUPAC rules for naming an aldehyde:
- • The longest parent carbon chain is identified that includes the carbonyl group.
- • The parent chain name is changed by replacing the suffix “-e” with “-al”.
- • Numbering is done in a way that the carbonyl group is designated as number 1. This is not indicated in the part of the name because for aldehyde, the carbonyl carbon is always numbered 1.
- • The identity and location of substituents if any has to be determined and this information has to be added in front of the IUPAC name.
- • If the carbonyl functional group is attached to a ring of carbon atoms, the ring is named and “-carbaldehyde” is added as suffix.
(c)
Interpretation:
IUPAC name for the given aldehyde has to be assigned.
Concept Introduction:
For naming an aldehyde in IUPAC nomenclature, the suffix “-al” is added to the parent alkane name.
IUPAC rules for naming an aldehyde:
- • The longest parent carbon chain is identified that includes the carbonyl group.
- • The parent chain name is changed by replacing the suffix “-e” with “-al”.
- • Numbering is done in a way that the carbonyl group is designated as number 1. This is not indicated in the part of the name because for aldehyde, the carbonyl carbon is always numbered 1.
- • The identity and location of substituents if any has to be determined and this information has to be added in front of the IUPAC name.
- • If the carbonyl functional group is attached to a ring of carbon atoms, the ring is named and “-carbaldehyde” is added as suffix.
(d)
Interpretation:
IUPAC name for the given aldehyde has to be assigned.
Concept Introduction:
For naming an aldehyde in IUPAC nomenclature, the suffix “-al” is added to the parent alkane name.
IUPAC rules for naming an aldehyde:
- • The longest parent carbon chain is identified that includes the carbonyl group.
- • The parent chain name is changed by replacing the suffix “-e” with “-al”.
- • Numbering is done in a way that the carbonyl group is designated as number 1. This is not indicated in the part of the name because for aldehyde, the carbonyl carbon is always numbered 1.
- • The identity and location of substituents if any has to be determined and this information has to be added in front of the IUPAC name.
- • If the carbonyl functional group is attached to a ring of carbon atoms, the ring is named and “-carbaldehyde” is added as suffix.
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Chapter 15 Solutions
General, Organic, And Biological Chemistry, Hybrid (with Owlv2 Quick Prep For General Chemistry Printed Access Card)
- Nonearrow_forwardTransmitance 3. Which one of the following compounds corresponds to this IR spectrum? Point out the absorption band(s) that helped you decide. OH H3C OH H₂C CH3 H3C CH3 H3C INFRARED SPECTRUM 0.8- 0.6 0.4- 0.2 3000 2000 1000 Wavenumber (cm-1) 4. Consider this compound: H3C On the structure above, label the different types of H's as A, B, C, etc. In table form, list the labeled signals, and for each one state the number of hydrogens, their shifts, and the splitting you would observe for these hydrogens in the ¹H NMR spectrum. Label # of hydrogens splitting Shift (2)arrow_forwardNonearrow_forward
- Draw the Lewis structure of C2H4Oarrow_forwarda) 5. Circle all acidic (and anticoplanar to the Leaving group) protons in the following molecules, Solve these elimination reactions, and identify the major and minor products where appropriate: 20 points + NaOCH3 Br (2 productarrow_forwardNonearrow_forward
- Organic And Biological ChemistryChemistryISBN:9781305081079Author:STOKER, H. Stephen (howard Stephen)Publisher:Cengage Learning,General, Organic, and Biological ChemistryChemistryISBN:9781285853918Author:H. Stephen StokerPublisher:Cengage LearningChemistry for Today: General, Organic, and Bioche...ChemistryISBN:9781305960060Author:Spencer L. Seager, Michael R. Slabaugh, Maren S. HansenPublisher:Cengage Learning
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