Geometry For Enjoyment And Challenge
91st Edition
ISBN: 9780866099653
Author: Richard Rhoad, George Milauskas, Robert Whipple
Publisher: McDougal Littell
expand_more
expand_more
format_list_bulleted
Question
Chapter 14.6, Problem 8PSB
To determine
To construct the
Expert Solution & Answer

Explanation of Solution
Given:
The angles are
Calculation:
The triangle with the angles are
Step 1- Draw the hypotenuse of say
Step 2- construct the angles of
Step 3- Join all the remaining points.
Step 4- The above is the required right triangle with angles
Chapter 14 Solutions
Geometry For Enjoyment And Challenge
Ch. 14.1 - Prob. 1PSACh. 14.1 - Prob. 2PSACh. 14.1 - Prob. 3PSACh. 14.1 - Prob. 4PSACh. 14.1 - Prob. 5PSACh. 14.1 - Prob. 6PSACh. 14.1 - Prob. 7PSACh. 14.1 - Prob. 8PSACh. 14.1 - Prob. 9PSACh. 14.1 - Prob. 10PSA
Ch. 14.1 - Prob. 11PSBCh. 14.1 - Prob. 12PSBCh. 14.1 - Prob. 13PSBCh. 14.1 - Prob. 14PSBCh. 14.1 - Prob. 15PSBCh. 14.1 - Prob. 16PSBCh. 14.1 - Prob. 17PSBCh. 14.1 - Prob. 18PSBCh. 14.1 - Prob. 19PSBCh. 14.1 - Prob. 20PSBCh. 14.1 - Prob. 21PSBCh. 14.1 - Prob. 22PSBCh. 14.1 - Prob. 23PSBCh. 14.1 - Prob. 24PSCCh. 14.1 - Prob. 25PSCCh. 14.1 - Prob. 26PSCCh. 14.1 - Prob. 27PSCCh. 14.1 - Prob. 28PSCCh. 14.1 - Prob. 29PSCCh. 14.1 - Prob. 30PSCCh. 14.2 - Prob. 1PSACh. 14.2 - Prob. 2PSACh. 14.2 - Prob. 3PSACh. 14.2 - Prob. 4PSACh. 14.2 - Prob. 5PSBCh. 14.2 - Prob. 6PSBCh. 14.2 - Prob. 7PSBCh. 14.2 - Prob. 8PSBCh. 14.2 - Prob. 9PSBCh. 14.2 - Prob. 10PSBCh. 14.2 - Prob. 11PSCCh. 14.2 - Prob. 12PSCCh. 14.2 - Prob. 13PSCCh. 14.2 - Prob. 14PSCCh. 14.2 - Prob. 15PSCCh. 14.2 - Prob. 16PSCCh. 14.2 - Prob. 17PSCCh. 14.3 - Prob. 1PSACh. 14.3 - Prob. 2PSACh. 14.3 - Prob. 3PSACh. 14.3 - Prob. 4PSACh. 14.3 - Prob. 5PSACh. 14.3 - Prob. 6PSACh. 14.3 - Prob. 7PSACh. 14.3 - Prob. 8PSBCh. 14.3 - Prob. 9PSBCh. 14.3 - Prob. 10PSBCh. 14.3 - Prob. 11PSBCh. 14.3 - Prob. 12PSBCh. 14.3 - Prob. 13PSBCh. 14.3 - Prob. 14PSBCh. 14.3 - Prob. 15PSCCh. 14.3 - Prob. 16PSCCh. 14.3 - Prob. 17PSCCh. 14.3 - Prob. 18PSCCh. 14.3 - Prob. 19PSCCh. 14.3 - Prob. 20PSCCh. 14.3 - Prob. 21PSDCh. 14.4 - Prob. 1PSACh. 14.4 - Prob. 2PSACh. 14.4 - Prob. 3PSACh. 14.4 - Prob. 4PSACh. 14.4 - Prob. 5PSACh. 14.4 - Prob. 6PSBCh. 14.4 - Prob. 7PSBCh. 14.4 - Prob. 8PSBCh. 14.4 - Prob. 9PSBCh. 14.4 - Prob. 10PSBCh. 14.4 - Prob. 11PSBCh. 14.4 - Prob. 12PSBCh. 14.4 - Prob. 13PSBCh. 14.4 - Prob. 14PSCCh. 14.4 - Prob. 15PSCCh. 14.4 - Prob. 16PSCCh. 14.4 - Prob. 17PSCCh. 14.4 - Prob. 18PSCCh. 14.4 - Prob. 19PSDCh. 14.5 - Prob. 1PSACh. 14.5 - Prob. 2PSACh. 14.5 - Prob. 3PSACh. 14.5 - Prob. 4PSACh. 14.5 - Prob. 5PSACh. 14.5 - Prob. 6PSACh. 14.5 - Prob. 7PSACh. 14.5 - Prob. 8PSACh. 14.5 - Prob. 9PSACh. 14.5 - Prob. 10PSACh. 14.5 - Prob. 11PSACh. 14.5 - Prob. 12PSBCh. 14.5 - Prob. 13PSBCh. 14.5 - Prob. 14PSBCh. 14.5 - Prob. 15PSBCh. 14.5 - Prob. 16PSBCh. 14.5 - Prob. 17PSBCh. 14.5 - Prob. 18PSBCh. 14.5 - Prob. 19PSBCh. 14.5 - Prob. 20PSCCh. 14.5 - Prob. 21PSCCh. 14.5 - Prob. 22PSCCh. 14.5 - Prob. 23PSCCh. 14.5 - Prob. 24PSCCh. 14.5 - Prob. 25PSCCh. 14.5 - Prob. 26PSDCh. 14.6 - Prob. 1PSACh. 14.6 - Prob. 2PSACh. 14.6 - Prob. 3PSACh. 14.6 - Prob. 4PSACh. 14.6 - Prob. 5PSACh. 14.6 - Prob. 6PSACh. 14.6 - Prob. 7PSACh. 14.6 - Prob. 8PSBCh. 14.6 - Prob. 9PSBCh. 14.6 - Prob. 10PSBCh. 14.6 - Prob. 11PSBCh. 14.6 - Prob. 12PSBCh. 14.6 - Prob. 13PSBCh. 14.6 - Prob. 14PSBCh. 14.6 - Prob. 15PSBCh. 14.6 - Prob. 16PSBCh. 14.6 - Prob. 17PSCCh. 14.6 - Prob. 18PSCCh. 14.6 - Prob. 19PSCCh. 14.6 - Prob. 20PSCCh. 14.6 - Prob. 21PSCCh. 14.6 - Prob. 22PSDCh. 14.6 - Prob. 23PSDCh. 14.6 - Prob. 24PSECh. 14 - Prob. 1RPCh. 14 - Prob. 2RPCh. 14 - Prob. 3RPCh. 14 - Prob. 4RPCh. 14 - Prob. 5RPCh. 14 - Prob. 6RPCh. 14 - Prob. 7RPCh. 14 - Prob. 8RPCh. 14 - Prob. 9RPCh. 14 - Prob. 10RPCh. 14 - Prob. 11RPCh. 14 - Prob. 12RPCh. 14 - Prob. 13RPCh. 14 - Prob. 14RPCh. 14 - Prob. 15RPCh. 14 - Prob. 16RPCh. 14 - Prob. 17RPCh. 14 - Prob. 18RPCh. 14 - Prob. 19RPCh. 14 - Prob. 20RPCh. 14 - Prob. 21RPCh. 14 - Prob. 22RPCh. 14 - Prob. 23RPCh. 14 - Prob. 24RPCh. 14 - Prob. 25RPCh. 14 - Prob. 26RPCh. 14 - Prob. 27RPCh. 14 - Prob. 28RPCh. 14 - Prob. 29RPCh. 14 - Prob. 30RPCh. 14 - Prob. 31RPCh. 14 - Prob. 32RP
Additional Math Textbook Solutions
Find more solutions based on key concepts
8. Effect of Blinding Among 13,200 submitted abstracts that were blindly evaluated (with authors and institutio...
Elementary Statistics
CHECK POINT I You deposit $1000 in a saving account at a bank that has a rate of 4%. a. Find the amount, A, of ...
Thinking Mathematically (6th Edition)
Fill in each blanks so that the resulting statement is true. Any set of ordered pairs is called a/an _______. T...
College Algebra (7th Edition)
The table by using the given graph of h.
Calculus for Business, Economics, Life Sciences, and Social Sciences (14th Edition)
Find the point-slope form of the line passing through the given points. Use the first point as (x1, .y1). Plot ...
College Algebra with Modeling & Visualization (5th Edition)
Knowledge Booster
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, geometry and related others by exploring similar questions and additional content below.Similar questions
- Find U V . 10 U V T 64° Write your answer as an integer or as a decimal rounded to the nearest tenth. U V = Entregararrow_forwardFind the area of a square whose diagonal is 10arrow_forwardDecomposition geometry: Mary is making a decorative yard space with dimensions as shaded in green (ΔOAB).Mary would like to cover the yard space with artificial turf (plastic grass-like rug). Mary reasoned that she could draw a rectangle around the figure so that the point O was at a vertex of the rectangle and that points A and B were on sides of the rectangle. Then she reasoned that the three smaller triangles resulting could be subtracted from the area of the rectangle. Mary determined that she would need 28 square meters of artificial turf to cover the green shaded yard space pictured exactly.arrow_forward
- 7. 11 m 12.7 m 14 m S V=B₁+ B2(h) 9.5 m 16 m h+s 2 na 62-19 = 37 +, M h² = Bu-29arrow_forwardwhat would a of a interscribed angle be with an arc of 93 degrees and inside abgles of 111 and 98arrow_forwardPlease complete through GeoGebra and present the screenshots of the results. Thanks! (This supports on how to submit it.)arrow_forward
- Door 87.5in to 47 living 44.75 Closet 96in Window ISS.Sin 48in Train Table 96in 48in 132:2 Windowarrow_forward39 Two sides of one triangle are congruent to two sides of a second triangle, and the included angles are supplementary. The area of one triangle is 41. Can the area of the second triangle be found?arrow_forwardA parallelogram with an area of 211.41 m^2 hast a base Thatcher measures 24.3m. Find ist height.arrow_forward
arrow_back_ios
SEE MORE QUESTIONS
arrow_forward_ios
Recommended textbooks for you
- Elementary Geometry For College Students, 7eGeometryISBN:9781337614085Author:Alexander, Daniel C.; Koeberlein, Geralyn M.Publisher:Cengage,Elementary Geometry for College StudentsGeometryISBN:9781285195698Author:Daniel C. Alexander, Geralyn M. KoeberleinPublisher:Cengage Learning

Elementary Geometry For College Students, 7e
Geometry
ISBN:9781337614085
Author:Alexander, Daniel C.; Koeberlein, Geralyn M.
Publisher:Cengage,

Elementary Geometry for College Students
Geometry
ISBN:9781285195698
Author:Daniel C. Alexander, Geralyn M. Koeberlein
Publisher:Cengage Learning
Quadrilaterals: Missing Angles and Sides; Author: rhornfeck;https://www.youtube.com/watch?v=knVj1O0L2TM;License: Standard YouTube License, CC-BY
STD IX | State Board | Types of Quadrilateral; Author: Robomate;https://www.youtube.com/watch?v=wh0KQ4UB0EU;License: Standard YouTube License, CC-BY