Chapter 14.4, Problem 6PSB

To determine

To construct a segment whose length is $\frac{1}{2}\left(b-a\right)$ .

Explanation of Solution

Given:

The given two segments are $a$ and $b$ .

Calculation:

Let the segment $a=3$

  

Let the segment $b=5$

  

Now, the length of $\frac{1}{2}\left(b-a\right)= \frac{1}{2}\left(5-3\right)=1$ is constructed as follows-

  

1cm