Chapter 14.6, Problem 6PSA

To determine

To construct the triangle with area twice as great as the given area of triangle.

Explanation of Solution

Given:

The given triangle ABC.

Calculation:

The triangle with area twice as great as the given area of triangle can be constructed as follows-

Step 1- Let the ABC be a right triangle.

Step 2- Now construct another right triangle XYZ.

Step 3- The dimensions of the triangle XYZ will be same as ABC except the length of the base will be double of the base of ABC.

Step 4- The XYZ will the triangle with area twice as that of ABC.