Campbell Biology, Books a la Carte Plus Mastering Biology with eText -- Access Card Package (10th Edition)
10th Edition
ISBN: 9780133922851
Author: Jane B. Reece, Lisa A. Urry, Michael L. Cain, Steven A. Wasserman, Peter V. Minorsky, Robert B. Jackson
Publisher: PEARSON
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Chapter 14.3, Problem 3CC
WHAT IF? Ø A rooster with gray feathers and a hen of the same phenotype produce 15 gray, 6 black, and 8 white chicks. What is the simplest explanation for the inheritance of these colors in chickens? What
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For number 15-24. In man, assume that spotted skin (S) is dominant over non-spotted skin (s) and that
wooly hair (W) is dominant over non-wooly hair (w). Cross a heterozygous parent (SsWw) with a
heterozygous parent (Ssww) Give genotypic and phenotypic ratios of offspring.
15-18. What is the probability of producing spotted skin with non-wooly hair?
8/16
4/16
3/16
6/16
8/16
A.
B.
C.
D.
E.
19-21. What is the probability of producing non-spotted skin with non-wooly hair?
A
2/16
B.
4/16
C.
1/16
D.
6/16
22-24. What is the probability of producing non-spotted skin with wooly hair?
A 3/16
В. 4/16
с. 1/16
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Chapter 14 Solutions
Campbell Biology, Books a la Carte Plus Mastering Biology with eText -- Access Card Package (10th Edition)
Ch. 14.1 - DRAW IT Pea plants heterozygous for flower...Ch. 14.1 - WHAT IF? List all gametes that could be made by a...Ch. 14.1 - MAKE CONNECTIONS In some pea plant crosses, the...Ch. 14.2 - Prob. 1CCCh. 14.2 - Two organisms, with genotypcs BbDD and BBDd, are...Ch. 14.2 - WHAT IF? Three characters (flower color, seed...Ch. 14.3 - What two properties, one structural and one...Ch. 14.3 - If a man with type AB blood marries a woman with...Ch. 14.3 - WHAT IF? A rooster with gray feathers and a hen...Ch. 14.4 - Beth and Tom each have a sibling with cystic...
Ch. 14.4 - Prob. 2CCCh. 14.4 - Prob. 3CCCh. 14.4 - MAKE CONNECTIONS In Table 14.1, note the...Ch. 14 - When Mendel did crosses of true-breeding purple-...Ch. 14 - DRAW IT Redraw the Punnett Square on The right...Ch. 14 - Inheritance patterns are often more complex than...Ch. 14 - Both members of a couple know that they are...Ch. 14 - DRAW IT Two pea plants heterozygous for the...Ch. 14 - A man with type A blood marries a woman with type...Ch. 14 - A man has six fingers on each hand and six toes on...Ch. 14 - DRAW IT A pea plant heterozygous for inflated pods...Ch. 14 - Flower position, stem length, and seed shape are...Ch. 14 - Prob. 6TYUCh. 14 - The genotype of F1, individuals in a tetrahybrid...Ch. 14 - What is the probability that each of thc following...Ch. 14 - Prob. 9TYUCh. 14 - Prob. 10TYUCh. 14 - In tigers, a recessive allele of a particular gene...Ch. 14 - In maize (com) plants,a dominant allele I inhibits...Ch. 14 - The pedigree belowtraces the inheritance of...Ch. 14 - Imagine that you are a genetic counselor, and a...Ch. 14 - EVOLUTION CONNECTION Over the past half century,...Ch. 14 - SCIENTIFIC INQUIRY You are handed a mystery pea...Ch. 14 - Prob. 17TYUCh. 14 - SYNTHESIZE YOUR KNOWLEDGE Just for fun, imagine...
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Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, biology and related others by exploring similar questions and additional content below.Similar questions
- Crossing Pea Plants: Mendels Study of Single Traits Stem length in pea plants is controlled by a single gene. Consider the cross of a true-breeding long-stemmed variety to a true-breeding short-stemmed variety in which long stems are completely dominant. a. If 120 F1 plants are examined, how many plants are expected to be long stemmed? Short stemmed? b. Assign genotypes to both P1 varieties and to all phenotypes listed in (a). c. A long-stemmed F1 plant is self-crossed. Of 300 F2 plants, how many should be long stemmed? Short stemmed? d. For the F2 plants mentioned in (c), what is the expected genotypic ratio?arrow_forwardEXAMPLE PROBLEM Two black female mice are crossed with a brown male. In several litters, female I produced 9 black offspring and 7 brown; female II produced 57 black offspring. What deductions can you make about the inheritance of black and brown coat color in mice? What are the genotypes of the parents? Dominance and recessive describe which of two possible phenotypes are exhibited when two different alleles occur in the same individual.arrow_forwardIn Labrador retrievers, two genes determine fur color: the E gene and the B gene. Black fur (B) is dominant to brown fur (b). However, the presence of (ee) will overshadow and create a puppy with yellow fur. Create a Punnett square crossing 2 Labs that are heterozygous for both genes. What are the resulting phenotypes? Don’t forget to take epistasis into account!arrow_forward
- . You buy an ornamental flowering plant with red flowers. Red flowers are found when both a D and an E allele are present. Either a D or an E allele produces orange flowers and ddee plants have yellow flowers You cross your red-flowered plant with an orange-flowered plant. You obtain offspring in the following ratios: 3 red : 1 yellow : 4 orange. What are the genotypes of the red-flowered and orange-flowered parent plants?arrow_forwardIn jellyfish, let's say that long tentacles are produced by a sex-influenced allele that is dominant in males and recessive in females. Let B1 = long and B2 = short. Which of the following correctly diagrams a cross between a female with long tentacles and a male with short tentacles? O B1B1XX X B1B2XY O B1B2 XX X B1B2 XY O females with long tentacles do not exist, so this cross is impossible O B1B1 XX X B2B2 XY O X(B1) X(B2) x X(B2) Yarrow_forwardStep by steparrow_forward
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- Se www.on ican webteMSTUARTL 192 Inheritance AO Multiple Alleles in Blood Groups The four common blood groups of the human 'ABO blood group system' are determined by three alleles: A, B, and o (also represented in some textbooks as: 1ª, 1®, and ¡º or just i). This is expressed equally. They each produce a different functional an example of a multiple allele system for a gene. The ABO enzyme that adds a different, specific sugar to the basic sugar antigens consist of sugars attached to the surface of red blood molecule. The blood group A and B antigens are able to react cells. The alleles code for enzymes (proteins) that join together with antibodies present in the blood from other people and must these sugars. The allele O produces a non-functioning enzyme that is unable to make any changes to the basic antigen (sugar molecule. The other two alleles (A, B) are codominant and are be matched for transfusion. Recessive allele: O produces a non-functioning protein Dominant allele: A…arrow_forwardPea PlantsIn pea plants, a round-seed shape (R) is dominant over a wrinkled-seed shape (r). A round-seeded pea plant was crossed with another round-seeded pea plant. What are the genotype(s) and phenotype(s) ratios of the F1 generation? Show all possibilities using Punnett squares. State the F1 generation genotypes and phenotypes.arrow_forward4arrow_forward
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