(a) Explanation From Doppler’s effect the expression for observed frequency when observer is moving towards the source is, f = f 0 ( v + v o v ) (1) Here, f 0 is the actual frequency. v is the speed of the sound. v o is speed of the observer. For the received frequency be double of the observed frequency. Substitute 2 f o for f in the above expression. 2 f o = f o ( v + v o v ) 2 = v + v o v 2 v = v + v o v o = v (2) For observer moving towards the source the received frequency is double the actual frequency the speed of the observer is speed of the sound. For the condition source is moving towards the observer and observer is at rest. The expression for received frequency is, f = f o ( v v − v s ) Here, v s is the speed of the harmonica (b) To determine The speed of the harmonica if the received frequency is 523.3 Hz . (c) To determine The speed of the observer if the received frequency is 523.3 Hz .

Physics, Books a la Carte Edition (5th Edition)

5th Edition

ISBN: 9780134020853

Author: James S. Walker

Publisher: PEARSON

See similar textbooks

Concept explainers

Wave Motion

A wave motion is defined as the propagation of disturbances or transfer of energy and momentum from the state of rest or equilibrium to another point in a medium without any actual transfer of matter between them. In a simple explanation, it is the propa…

Question

Chapter 14, Problem 50PCE

(a)

To determine

Whether harmonica or observer is moved to double the received frequency.

(b)

To determine

The speed of the harmonica if the received frequency is 523.3 Hz .

(c)

To determine

The speed of the observer if the received frequency is 523.3 Hz .

Expert Solution & Answer

Want to see the full answer?

Check out a sample textbook solution

See solution

Chapter 14, Problem 49PCE

Chapter 14, Problem 51PCE

Students have asked these similar questions

43. A mass må undergoes circular motion of radius R on a hori- zontal frictionless table, con- nected by a massless string through a hole in the table to a second mass m² (Fig. 5.33). If m₂ is stationary, find expres- sions for (a) the string tension and (b) the period of the circu- lar motion. m2 R m₁ FIGURE 5.33 Problem 43

CH 70. A block is projected up an incline at angle 0. It returns to its initial position with half its initial speed. Show that the coefficient of ki- netic friction is μk = tano.

Passage Problems A spiral is an ice-skating position in which the skater glides on one foot with the other foot held above hip level. It's a required element in women's singles figure-skating competition and is related to the arabesque performed in ballet. Figure 5.40 shows Canadian skater Kaetlyn Osmond executing a spiral during her medal-winning perfor- mance at the 2018 Winter Olympics in Gangneung, South Korea. 77. From the photo, you can conclude that the skater is a. executing a turn to her left. b. executing a turn to her right. c. moving in a straight line out of the page. 78. The net force on the skater a. points to her left. b. points to her right. c. is zero. 79. If the skater were to execute the same maneuver but at higher speed, the tilt evident in the photo would be a. less. b. greater. c. unchanged. FIGURE 5.40 Passage Problems 77-80 80. The tilt angle 0 that the skater's body makes with the vertical is given ap- proximately by 0 = tan¯¹(0.5). From this you can conclude…

Chapter 14 Solutions

Physics, Books a la Carte Edition (5th Edition)

Ch. 14.1 - Rank the following systems in order of increasing...Ch. 14.2 - Suppose the tension in a string is doubled, its...Ch. 14.3 - A particular harmonic wave is described by the...Ch. 14.4 - Which is faster: wave 1 in medium 1 with a...Ch. 14.5 - Enhance Your Understanding (Answers given at the...Ch. 14.6 - Observer 1 approaches a stationary 1000-Hz source...Ch. 14.7 - Prob. 7EYU Ch. 14.8 - When a string oscillates with the standing wave...Ch. 14.9 - Rank the following systems in order of increasing...Ch. 14 - A long nail has been driven halfway into the side...

Knowledge Booster

Learn more about

Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, physics and related others by exploring similar questions and additional content below.

Whether harmonica or observer is moved to double the received frequency.

Solution Summary: The author explains that harmonica is moved towards the observer to double the received frequency.

Concept explainers

Whether harmonica or observer is moved to double the received frequency.

The speed of the harmonica if the received frequency is 523.3 Hz .

The speed of the observer if the received frequency is 523.3 Hz .

Want to see the full answer?

Chapter 14 Solutions