Chapter 1.4, Problem 42PPE

(a)

To determine

Find the value of $6+12÷3-2\times 4$

Answer to Problem 42PPE

The answer is $2$

Explanation of Solution

The given expression is $6+12÷3-2\times 4$ .

And the value is found by taking division first then multiplication and addition and then subtraction.

  $\begin{array}{l}=6+4-8\\ =10-8\\ =2\end{array}$

(b)

To determine

Use the grouping symbol in the expression $6+12÷3-2\times 4$ to get the value greater than $2.$

Answer to Problem 42PPE

  $6+12÷\left(3-2\right)\times 4$. the answer for this is $54$

Explanation of Solution

Use parentheses in the given equation between $3and2$ . The expression become $6+12÷\left(3-2\right)\times 4$.

Solve the expression and get the result.

  $\begin{array}{l}6+12÷\left(3-2\right)\times 4\\ 6+12÷1\times 4\\ 6+12\times 4\\ 6+48\\ 54\end{array}$

The answer is $54$ which is greater the answer in above part.

(c)

To determine

Answer to Problem 42PPE

  $\left(6+12\right)÷3-2\times 4$ .

The answer is -2, which less than $2$ .

Explanation of Solution

  $\left(6+12\right)÷3-2\times 4$ is the required expression. Solve the equation to get the answer.

  $\begin{array}{l}\left(6+12\right)÷3-2\times 4\\ 18÷3-2\times 4\\ 6-8\\ -2\end{array}$

This is less than answer obtained in part (a) of the question.