Chapter 1.2, Problem 35PPE

To determine

To find: the momentums of a vehicle with the given mass $1000\text{kg}$ moving under the different velocities.

Answer to Problem 35PPE

For increasing in velocity with constant mass increases the momentum of an objects.

Explanation of Solution

Given:

The mass of the vehicle is $1000\text{kg}$ moves with a velocity of $15m/s,20m/s\text{ and }25m/s$ .

Concept used:

According to the second law of motion:

Rate of change of momentum is directly proportional to the force applied.

Where momentum is product of mass and velocity.

  $P=m\times v$ .

Calculation:

Given is to write an expression for:

Momentum of an object $\left(P\right)$ : mass of body $m\times$ velocity of object $v$ .

So, expression for momentum of an object $\left(P\right)=m\times v$ .

Where $P$ is momentum of object.

  $m$ is mass of the body.

  $v$ is velocity at which body moves standards units at which given terms are expressed are below:

Unit for momentum $=\text{kg×}\frac{\text{m}}{\text{s}}\left(\text{ki log rams}\times \text{meter per second}\right).$

Unit for mass of body $=\text{kg}\left(\text{kilograms}\right)$ .

Unit for velocity $\text{=}\frac{\text{m}}{\text{s}}\left(\text{meter per second}\right)$ .

Below is the table showing different values of momentum at different velocities:

Sr. No	Mass of a body$\left(m\right)$	Velocity $\left(v\right)$	Momentum $\left(P\right)$ $P=m\times v$	Final value of Momentum $\left(M\right)$
$1$	$1000kg$	$15m/s$	$1000kg\times 15m/s=15000kg.m/s$	$15,000kgm/s$
$2$	$1000kg$	$20m/s$	$1000kg\times 20m/s=20000kg.m/s$	$20,000kgm/s$
$3$	$1000kg$	$25m/s$	$1000kg\times 25m/s=25000kg.m/s$	$25,000kgm/s$

Hence, for increasing in velocity with constant mass increases the momentum of an objects.