Chapter 14, Problem 14.3P

How many ${}^{\text{1}}\text{H}$ NMR signals does each compound show?

a. c. e. g.

b. d. f. h.

Interpretation Introduction

(a)

Interpretation: The number of ${}^{\text{1}}\text{H}$ NMR signals in the given compound is to be identified.

Concept introduction: The number of NMR signal in a compound is equal to the number of chemically non-equivalent protons present in that compound. Protons which are present in the same chemical environment that is between the same group of atoms are known as chemically equivalent protons and in ${}^1\text{H}-\text{NMR}$ all chemically equivalent proton generates one signal or one peak, whereas non-equivalent proton generates different signals.

Answer to Problem 14.3P

The given compound, propane shows two signals in ${}^{\text{1}}\text{H}$ NMR spectrum.

Explanation of Solution

The number of signals in each compound is equal to the number of hydrogen atoms present in a different chemical environment. The given compound is propane that consists of two non-equivalent hydrogen groups. Therefore, the number of ${}^{\text{1}}\text{H}$ NMR signals shown by propane is two.

Figure 1

Conclusion

The given compound, propane shows two signals in ${}^{\text{1}}\text{H}$ NMR spectrum.

Interpretation Introduction

(b)

Interpretation: The number of ${}^{\text{1}}\text{H}$ NMR signals in the given compound is to be identified.

Concept introduction: The number of NMR signal in a compound is equal to the number of chemically non-equivalent protons present in that compound. Protons which are present in the same chemical environment that is between the same group of atoms are known as chemically equivalent protons and in ${}^1\text{H}-\text{NMR}$ all chemically equivalent proton generates one signal or one peak, whereas non-equivalent proton generates different signals.

Answer to Problem 14.3P

The given compound, ethoxyethane shows two signals in ${}^{\text{1}}\text{H}$ NMR spectrum.

Explanation of Solution

The given compound is ethoxyethane that consists of two non-equivalent hydrogen groups. Therefore, the number of ${}^{\text{1}}\text{H}$ NMR signals shown by ethoxyethane is two.

Figure 2

Conclusion

The given compound, ethoxyethane shows two signals in ${}^{\text{1}}\text{H}$ NMR spectrum.

Interpretation Introduction

(c)

Interpretation: The number of ${}^{\text{1}}\text{H}$ NMR signals in the given compound is to be identified.

Concept introduction: The number of NMR signal in a compound is equal to the number of chemically non-equivalent protons present in that compound. Protons which are present in the same chemical environment that is between the same group of atoms are known as chemically equivalent protons and in ${}^1\text{H}-\text{NMR}$ all chemically equivalent proton generates one signal or one peak, whereas non-equivalent proton generates different signals.

Answer to Problem 14.3P

The given compound, butane shows two signals in ${}^{\text{1}}\text{H}$ NMR spectrum.

Explanation of Solution

The given compound is butane that consists of two non-equivalent hydrogen groups. Therefore, the number of ${}^{\text{1}}\text{H}$ NMR signals shown by butane is two as shown below.

Figure 3

Conclusion

The given compound, butane shows two signals in ${}^{\text{1}}\text{H}$ NMR spectrum.

Interpretation Introduction

(d)

Interpretation: The number of ${}^{\text{1}}\text{H}$ NMR signals in the given compound is to be identified.

Concept introduction: The number of NMR signal in a compound is equal to the number of chemically non-equivalent protons present in that compound. Protons which are present in the same chemical environment that is between the same group of atoms are known as chemically equivalent protons and in ${}^1\text{H}-\text{NMR}$ all chemically equivalent proton generates one signal or one peak, whereas non-equivalent proton generates different signals.

Answer to Problem 14.3P

The given compound, $2,3-$ dimethylbutane shows two signals in ${}^{\text{1}}\text{H}$ NMR spectrum.

Explanation of Solution

The given compound is $2,3-$ dimethylbutane that consists of two non-equivalent hydrogen groups. Therefore, the number of ${}^{\text{1}}\text{H}$ NMR signals shown by $2,3-$ dimethylbutane is two as shown below.

Figure 4

Conclusion

The given compound, $2,3-$ dimethylbutane shows two signals in ${}^{\text{1}}\text{H}$ NMR spectrum.

Interpretation Introduction

(e)

Interpretation: The number of ${}^{\text{1}}\text{H}$ NMR signals in the given compound is to be identified.

Concept introduction: The number of NMR signal in a compound is equal to the number of chemically non-equivalent protons present in that compound. Protons which are present in the same chemical environment that is between the same group of atoms are known as chemically equivalent protons and in ${}^1\text{H}-\text{NMR}$ all chemically equivalent proton generates one signal or one peak, whereas non-equivalent proton generates different signals.

Answer to Problem 14.3P

The given compound, ethyl propanoate shows four signals in ${}^{\text{1}}\text{H}$ NMR spectrum.

Explanation of Solution

The given compound is ethyl propanoate that consists of four non-equivalent hydrogen groups. Therefore, the number of ${}^{\text{1}}\text{H}$ NMR signals shown by ethyl propanoate is four as shown below.

Figure 5

Conclusion

The given compound, ethyl propanoate shows four signals in ${}^{\text{1}}\text{H}$ NMR spectrum.

Interpretation Introduction

(f)

Interpretation: The number of ${}^{\text{1}}\text{H}$ NMR signals in the given compound is to be identified.

Concept introduction: The number of NMR signal in a compound is equal to the number of chemically non-equivalent protons present in that compound. Protons which are present in the same chemical environment that is between the same group of atoms are known as chemically equivalent protons and in ${}^1\text{H}-\text{NMR}$ all chemically equivalent proton generates one signal or one peak, whereas non-equivalent proton generates different signals.

Answer to Problem 14.3P

The given compound, $1-\text{methoxy}-2-\text{methyl propane}$ shows four signals in ${}^{\text{1}}\text{H}$ NMR spectrum.

Explanation of Solution

The given compound is $1-\text{methoxy}-2-\text{methyl propane}$ that consists of four non-equivalent hydrogen groups. Therefore, the number of ${}^{\text{1}}\text{H}$ NMR signals shown by $1-\text{methoxy}-2-\text{methyl propane}$ is four as shown below.

Figure 6

Conclusion

The given compound, $1-\text{methoxy}-2-\text{methyl propane}$ shows four signals in ${}^{\text{1}}\text{H}$ NMR spectrum.

Interpretation Introduction

(g)

Interpretation: The number of ${}^{\text{1}}\text{H}$ NMR signals in the given compound is to be identified.

Concept introduction: The number of NMR signal in a compound is equal to the number of chemically non-equivalent protons present in that compound. Protons which are present in the same chemical environment that is between the same group of atoms are known as chemically equivalent protons and in ${}^1\text{H}-\text{NMR}$ all chemically equivalent proton generates one signal or one peak, whereas non-equivalent proton generates different signals.

Answer to Problem 14.3P

The given compound, $1-$ chlorooctane shows eight signals in ${}^{\text{1}}\text{H}$ NMR spectrum.

Explanation of Solution

The given compound is $1-$ chlorooctane that consists of eight non-equivalent hydrogen groups. Therefore, the number of ${}^{\text{1}}\text{H}$ NMR signals shown by $1-$ chlorooctane is eight as shown below.

Figure 7

Conclusion

The given compound, $1-$ chlorooctane shows eight signals in ${}^{\text{1}}\text{H}$ NMR spectrum.

Interpretation Introduction

(h)

Interpretation: The number of ${}^{\text{1}}\text{H}$ NMR signals in the given compound is to be identified.

Concept introduction: The number of NMR signal in a compound is equal to the number of chemically non-equivalent protons present in that compound. Protons which are present in the same chemical environment that is between the same group of atoms are known as chemically equivalent protons and in ${}^1\text{H}-\text{NMR}$ all chemically equivalent proton generates one signal or one peak, whereas non-equivalent proton generates different signals.

Answer to Problem 14.3P

The given compound, $\text{propan}-1-\text{ol}$ shows four signals in ${}^{\text{1}}\text{H}$ NMR spectrum.

Explanation of Solution

The given compound is $\text{propan}-1-\text{ol}$ that consists of four non-equivalent hydrogen groups. Therefore, the number of ${}^{\text{1}}\text{H}$ NMR signals shown by $\text{propan}-1-\text{ol}$ is four as shown below.

Figure 8

Conclusion

The given compound, $\text{propan}-1-\text{ol}$ shows four signals in ${}^{\text{1}}\text{H}$ NMR spectrum.